Okey so 1st find the moles of F2 which is :
n = 15/22.4 = 0.667mol
Then according to stoichiometric values, F2 and NaCl, they are to a ratio of 1 : 2
So take the twice value of the calculated moles.
Use the moles to find the mass using the equation :
m = n×M
Where m is the mass
n is moles
M is molar mass (of NaCl)
Therefore m = 1.334×57.5
(given the molar mass of Na 22gmol^-1 and CL 35.5gmol^-1)
m = 76.705g
The balanced chemical reaction is written as:
<span>Cu +2AgNO3 → Cu(NO3)2 + 2Ag
</span>
We are given the amount of silver nitrate to be used for the reaction. This value will be the starting point of our calculations. It is as follows:
4.00 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Cu / 2 mol AgNO3 ) ( 63.456 g / 1 mol ) = 0.747 g Cu
Percentage by volume of solution is the percentage volume of solute in total volume of solution.
Volume percentage (v/v%) = volume of solute / total volume of solution x 100%
volume of solute - 16.0 mL
total volume of solution - 155 mL
v/v% = 16.0 / 155 x 100% = 10.32%
this means that in a volume of 100 mL solution, 10.32 mL is acetone.
