CH3CH2CH(Cl)CHO iupac name?

the energy to break 1 mol of C-C bonds is 348 kj/mol. what would be the minimum frequency of a single photon that would break a

mr_godi [17]

Answer:

f = 5.25 x 10³⁸ s⁻¹

Explanation:

Energy = 348KJ = 348,000 J

Frequency = ?

Energy and frequency are related by the equation below;

E = hf

where h = Planck's constant = (6.626 x 10-34 J · s),

Upon making f subject of formular;

f = E / h

substituting the values, we have;

f = 348,000 / 6.626 x 10-34

f = 52,520 x 10 ³⁴ s⁻¹

f = 5.25 x 10³⁸ s⁻¹

4 0

2 years ago

How many moles of N2 are essential for generating 0.08 moles of Li3N in the given reaction?6Li N2 2Li3N

jeka57 [31]

08 moles Li3N * 1mole N2/2moles Li3N = 0.04

3 0

2 years ago

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A metal oxide with the formula mo contains 15.44% oxygen. in the box below, type the symbol for the element represented by m.

lana66690 [7]

Answer: The element represented by M is Strontium.

Explanation:

Let us consider the molar mass of metal be 'x'.

The molar mass of MO will be = Molar mass of oxygen + Molar mass of metal = (16 + x)g/mol

It is given in the question that 15.44% of oxygen is present in metal oxide. So, the equation becomes:

$\frac{15.44}{100}\times (x+16)=16g/mol\\\\(x+16)=\frac{16g/mol\times 100}{15.44}\\\\x=(103.626-16)g/mol\\\\x=87.62g/mol$

The metal atom having molar mass as 87.62/mol is Strontium.

Hence, the element represented by M is Strontium.

8 0

2 years ago

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The shape of an atomic orbital is associated with

Diano4ka-milaya [45]

The properties of the atomic orbital are actually dependent on the quantum numbers.

size of atomic orbital: governed by the principal quantum number (n)

shape of atomic orbital: governed by the angular momentum quantum number (l)

orientation in space: governed by the magnetic quantum number (ml)

Since we are asked about the shape, hence the correct answer is:

angular momentum quantum number (l)

8 0

1 year ago

HCN forms when synthetic fibers containing Orlon® or Acrilan® burn. Acrilan® has an empirical formula of CH2CHCN, so HCN is 50.9

hichkok12 [17]

Answer:

676 g

Explanation:

First, let's calculate the area of the rug: 3.70x4.20 = 15.54 m². Knowing that 1 yard has 0.9144 m, so

1 yd² = (0.9144 m)² = 0.8361 m²

So, there is 30.0 oz in 0.8361 m²

30.0 oz-----------------0.8361 m²

x -----------------15.54 m²

By a simple direct three rule:

0.8361x = 466.2

x = 557.6 oz of Acrilan in the rug

1 oz = 28.35 grams, so 557.6 oz = 15807.96 g

The potencial of HCN is 50.9% of this mass, so: 0.509x15807.96 = 8046.25 g.

But only 42.0% of the rug is burned, so the potencial of HCN is 42.0% of 8046.25: 0.42x 8046.25 = 3379.42 g.

And the yield is only 20.%, so the mass formed of HCN is:

0.20x3379.42 = 676 g

5 0

1 year ago