A mixture of sand and table salt cam be separated by filtration because the substances in the mixture differ in
1 answer:
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Answer : The exit temperature of the product is,
Explanation :
Total heat = Heat lost by liquid + Latent heat of fusion + Heat lost by frozen
where,
Q = Total heat = 6000 kJ
m = mass of product = 15 kg
= specific heat of liquid =
= latent heat of fusion =
= specific heat of frozen =
= initial temperature of liquid =
= final temperature of liquid =
= initial temperature of frozen = ?
= final temperature of frozen =
Now put all the given value in the above expression, we get:
Thus, the exit temperature of the product is,
Answer:
Normality N = 0.2 N
Explanation:
Normality is the number of gram of equivalent of solute divided of volume of solution, where the number of gram of equivalent of solute is weight of the solute divided by the equivalent weight.
Normality is represented by N.
Mathematically, we have :
Given that:
number of gram of equivalent of solute = 90 milliequivalents 90 × 10⁻³ equivalent
volume of solution (HCl) = 450 mL 450 × 10⁻³ L
Normality N = 0.2 N