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topjm [15]
2 years ago
7

A mixture of sand and table salt cam be separated by filtration because the substances in the mixture differ in

Chemistry
1 answer:
Stels [109]2 years ago
6 0
A mixture of sand and table salt can be separated by filtration because the substances in the mixture differ in solubility. Because sand and table salt have a different ability to dissolve they can easily be separated. What can be done to separate this mixture is to add water to it and stir it thoroughly. The salt will easily dissolve in water while the sand will stay insoluble. The filtration of this mixture will result in salt being drained off with water while only the sand will remain. 
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Oxygen _____.
Marysya12 [62]
The answer is it breaks down food into energy
Have a Nice day
7 0
1 year ago
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A) To generate the spectrum above a source capable of producing electromagnetic radiation with an energy of 7 * 10 ^ 4 * k * J p
marin [14]

Answer:

Gamma

Explanation:

I'm not sure how to do it without calculations but:

E=hv

7*10^7 J/mol=6.626*10^34 Js * v

v=1*10^41

Gamma rays.

More here: https://www.hasd.org/faculty/AndrewSchweitzer/spectroscopy.pdf

3 0
2 years ago
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The data in the table below were obtained for the reaction: 2clo2 (aq) + 2 oh- (aq) --> clo3- (aq) + clo2- (aq) + h2o (l) exp
SVETLANKA909090 [29]
Lets organise the data given in the question
                [ClO₂] (m)       [OH⁻] (m)        initial rate (m/s)
                  <span>0.060              0.030               0.0248
</span><span>                  0.020              0.030               0.00276
</span><span>                  0.020              0.090                0.00828
rate equation as follows 
rate = k [</span>ClO₂]ᵃ [OH⁻]ᵇ
where k - rate constant 
we need to find order with respect to ClO₂ therefore lets take the 2 equations where OH⁻ is constant.
1) 0.00276 = k [0.020]ᵃ[0.030]ᵇ
2) 0.0248 = k [0.060]ᵃ[0.030]ᵇ
divide first equation from the second
0.0248/0.00276 = [0.060/0.020]ᵇ
8.99 = 3ᵇ
8.99 rounded off to 9
9 = 3ᵇ
b = 2
order with respect to ClO₂ is 2
3 0
2 years ago
5. You have 100 kg of gas of the following composition: CH4 - 30% H2 - 10% N2 - 60% What is the average molecular weight of this
Lorico [155]

Answer:

21.8 g/mol

Explanation:

Molecular weight of CH4 = 16g/mol

H2 = 2g/mol

N2 = 28g/mol

(16*30 + 2*10 + 28*60)/100

=2180/100

=21.8g/mol

6 0
2 years ago
Molecular bromine is 24 percent dissociated at 1600 k and 1.00 bar in the equilibrium br2 (
dlinn [17]
Br2 == 2Br

24% dissociated => n total moles, 0.24 mol*n of Br, and 0.76*n mol of Br2

=> partial pressure of Br, P Br = 0.24 bar, and
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kp = (P Br)^2 / P Br2 = (0.24)^2 / 0.76 = 0.0758


3 0
2 years ago
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