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Bad White [126]

2 years ago

8

Hen water ionizes, it produces equal amounts of hydrogen and hydroxide ions that can reassociate with each other. the ph of wate

r is:

1 answer:

Olin [163]2 years ago

5 0

When there are equal number of H+ and OH- ions, the pH of water is 7.

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Which feature defines a neutral atom? (1 point)

harina [27]

The features which gives the definition of neutral atom is : the numbers of electrons is equal to number of protons

Atoms can be regarded as neutral atom when they has same number of protons and the same numbers of electrons. Even after formation of the ion, there will still be the same number of protons.

Example of this is sodium atom, which has 11 protons as well as 11 electrons

Therefore, number of electrons will be the same as the number of protons as regards neutral atom

Learn more at : brainly.com/question/1641336?referrer=searchResults

7 0

1 year ago

Read 2 more answers

How can we predict how the moon will change appearance from day to day?

kvv77 [185]

Answer:

1. When you see the moon, think of the whereabouts of the sun

2. The moon rises in the east and sets in the west, each and every day

3. The moon takes about a month (one month) to orbit the Earth

4. The moon’s orbital motion is toward the east

Explanation:

7 0

2 years ago

Read 2 more answers

Find the de Broglie wavelength lambda for an electron moving at a speed of 1.00 \times 10^6 \; {\rm m/s}. (Note that this speed

masya89 [10]

(A) $7.28\cdot 10^{-10} m$

The De Broglie wavelength of an electron is given by

$\lambda=\frac{h}{p}$ (1)

where

h is the Planck constant

p is the momentum of the electron

The electron in this problem has a speed of

$v=1.00\cdot 10^6 m/s$

and its mass is

$m=9.11\cdot 10^{-31} kg$

So, its momentum is

$p=mv=(9.11\cdot 10^{-31} kg)(1.00\cdot 10^6 m/s)=9.11\cdot 10^{-25}kg m/s$

And substituting into (1), we find its De Broglie wavelength

$\lambda=\frac{6.63\cdot 10^{-34}Js}{9.11\cdot 10^{-25} kg m/s}=7.28\cdot 10^{-10} m$

(B) $1.16\cdot 10^{-34}m$

In this case we have:

m = 0.143 kg is the mass of the ball

v = 40.0 m/s is the speed of the ball

So, the momentum of the ball is

$p=mv=(0.143 kg)(40.0 m/s)=5.72 kg m/s$

And so, the De Broglie wavelength of the ball is given by

$\lambda=\frac{h}{p}=\frac{6.63\cdot 10^{-34} Js}{5.72 kg m/s}=1.16\cdot 10^{-34}m$

(C) $9.02\cdot 10^{-9}m$

The location of the first intensity minima is given by

$y=\frac{L\lambda}{a}$

where in this case we have

$y=0.492 cm = 4.92\cdot 10^{-3} m$

L = 1.091 is the distance between the detector and the slit

$a=2.00\mu m=2.00\cdot 10^{-6}m$ is the width of the slit

Solving the formula for $\lambda$ , we find the wavelength of the electrons in the beam:

$\lambda=\frac{ya}{L}=\frac{(4.92\cdot 10^{-3}m)(2.00\cdot 10^{-6} m)}{1.091 m}=9.02\cdot 10^{-9}m$

(D) $7.35\cdot 10^{-26}kg m/s$

The momentum of one of these electrons can be found by re-arranging the formula of the De Broglie wavelength:

$p=\frac{h}{\lambda}$

where here we have

$\lambda=9.02\cdot 10^{-9}m$ is the wavelength

Substituting into the formula, we find

$p=\frac{6.63\cdot 10^{-34}Js}{9.02\cdot 10^{-9}m}=7.35\cdot 10^{-26}kg m/s$

7 0

2 years ago

A compound with molecular formula C4H6O4 produces a broad signal between 2500 and 3600 cm-1 in its IR spectrum and produces two

tiny-mole [99]

Answer:

Succinic Acid

Explanation:

We have to start using the info given by the IR spectrum. In this case, we have a <u>broad signal in 3600</u>. This indicates the presence of OH in the structure. Therefore we can have an <u>alcohol or an acid</u> in the structure.

Now, the NMR info tells us that we only have 2 signals, this indicates that we have a <u>very symmetric structure</u>. Also, we have a signal in 12 ppm therefore we can affirm that we have an O-H bond with <u>high polarity</u> (a downfield signal) this behavior is given in the <u>acid groups</u>.

The structure that fulfill these requirements it the succinic acid. In which we only have 2 signals in the 1H- NMR. We have an acid group and we have a formula of $C_4H_6O_4$ .

<u>For further explanations see the attached images.</u>

3 0

2 years ago

What is the density (in g/L) of a gas with a molar mass of 146.06 g/mol at 1.03 atm and 297k

marshall27 [118]

Lets assume the gas is acting Ideally, then According to Ideal Gas Equation the density is given as,

d = P M / R T ------- (1)
Where;
P = Pressure = 1.03 atm

M = Molar Mass = 146.06 g/mol

R = Gas Constant = 0.08206 atm.L.mol⁻¹.K⁻¹

T = Temperature = 297 K

Putting Values in eq. 1,

d = (1.03 atm × 146.06 g/mol) ÷ (0.08206 atm.L.mol⁻¹.K⁻¹ × 297 K)

density = 6.17 g/L

6 0

2 years ago