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VikaD [51]
1 year ago
12

Which feature defines a neutral atom? (1 point)

Chemistry
2 answers:
harina [27]1 year ago
7 0

  • The features  which gives the definition of neutral atom is : the numbers of electrons is equal to number of protons

  • Atoms can be regarded as neutral atom when they has same number of protons and the same numbers of electrons. Even after formation of the ion, there will still be the same number of protons.

  • Example of this is  sodium atom, which has 11 protons as well as  11 electrons

Therefore, number of electrons will be the same as the number of protons as regards neutral atom

Learn more at : brainly.com/question/1641336?referrer=searchResults

Brilliant_brown [7]1 year ago
7 0

Answer:1. A. The number of electrons equal to the number of protons

2. D. The electrons in an atoms outermost energy level

3. A. To obtain a full outer electron shell

4. C. Seven

5. C. It will give up electrons forming a positive ion

Explanation:

I use this app plenty, time to give back a little.

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You multiply avogadro's number to what you were given.
8.30x10^23 * 6. 0221409x10^23
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Conversion of kinetic energy to potential energy (chemo mechanical energy)

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Explanation:

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By which process is a precipitate most easily separated from the liquid in which it is suspended
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<span>Filtration, if its a precipitate that means its insoluble. </span>
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Ancient Egyptians used a variety of lead compounds as white pigments in their cosmetics, including PbS, PbCO3, PbCl(OH), and Pb2
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Answer : The compound contains the highest percentage of lead (by mass) is, PbS.

Explanation :

To calculate the percentage of lead in sample, we use the equation:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100

<u>For PbS :</u>

Mass of PbS = 239.3 g

Mass of Pb = 207.2 g

Putting values in above equation, we get:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{239.3g}\times 100=86.58\%

The percentage of lead in the PbS is 86.58 %.

<u>For PbCO_3 :</u>

Mass of PbCO_3 = 267.2 g

Mass of Pb = 207.2 g

Putting values in above equation, we get:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{267.2g}\times 100=77.55\%

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<u>For PbCl(OH) :</u>

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Putting values in above equation, we get:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{259.7g}\times 100=79.78\%

The percentage of lead in the PbCl(OH) is 79.78 %.

<u>For Pb_2Cl_2CO_3 :</u>

Mass of Pb_2Cl_2CO3_ = 545.3 g

Mass of Pb = 207.2 g

Putting values in above equation, we get:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{545.3g}\times 100=37.99\%

The percentage of lead in the Pb_2Cl_2CO3_ is 37.99 %.

Hence, from this we conclude that, the compound PbS contains the highest percentage of lead (by mass).

6 0
2 years ago
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