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Karolina [17]
2 years ago
14

Oxides of nitrogen are pollutant gases which are emitted from car exhausts.

Chemistry
2 answers:
victus00 [196]2 years ago
5 0

Answer:

The correct answer is option B.

Explanation:

Mass of N_xO_y ,m= 0.23 g

Molar mass of N_xO_y=M=14 g\mol\times x+16 g/mol\times y

n=\frac{m}{M}

Volume occupied by the N_xO_y=120 cm^3=0.120 dm^3

1 cm^3 = 0.001 dm^3

1 mol of gas molecules occupies 24.0 dm^3.

Then n moles of N_xO_y will occupy volume of 0.120 dm^3.

n\times 24.0 dm^3/mol=0.120 dm^3

n = 0.005 moles

0.005 mol=\frac{0.23 g}{14g/mol\times x+16 g/mol\times y}

14x+16y=46

Putting values from option A:  x = 1, y = 1

14 × 1+16× 1 ≠ 46

Putting values from option B:  x = 1, y = 2

14 × 1+16× 2 = 46  (The correct answer)

Putting values from option C:  x = 2, y = 1

14 × 2+16× 1 ≠ 46

Putting values from option D:  x = 2, y = 4

14 × 2+16× 4 ≠ 46

V125BC [204]2 years ago
4 0
Let's look at the molar weight of the answers: 
NO is 30 g/mol 
NO2 is 46 
N2O is 44 
N2O4 is 124 

<span>We have the grams of the product, so we need the moles in order to calculate the molar weight. We us PV=nRT for this, assuming standard temperature and pressure. </span>
You were given the liters (.120L) 
Std pressure is 1 atmosphere 
You&#x27;re looking for n, the number of moles 
<span>Temp is 293.15 kelvin, thats standard </span>
And r is the gas constant in liters-atm per mol kelvin 

(.120 liters)(1atm)=n(293.15K)(.08206) 
Solving for n is .0049883835 mol 

<span>.23g divided by .0049883 mol is about 46g&#x2F;mol. You&#x27;re answer is B I think, NO2

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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