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saul85 [17]
2 years ago
14

Choose the statements about benzene that are correct.

Chemistry
1 answer:
FromTheMoon [43]2 years ago
3 0

Answer:

All of the C-C bonds are actually identical,

The structure of the molecule is closed like a ring structure,

Explanation:

1) all benzene hydrocarbons are ChHp-2 ⇔ this is <u>false</u> the formula for benzene is C6H6 ( CnHn).

2)All C-C bonds share 2 pairs of electrons ⇔ <u>False </u>

There are not enough electrons to form double bonds on all the carbon atoms

3) Three C-C bonds share 2 pairs of electrons  ⇔ False

Since there are not enough electrons to form double bonds on all the carbon atoms, although the electrons do strengthen all of the bonds on the ring equally.

4) All of the C-C bonds are actually identical ⇔ <u>correct </u>

⇒The actual structure of benzene is a resonance hybrid, with six delocalised π-electrons.  (4n + 2 = π)

⇒Due to this structure with delocalised π-electrons, the structure of benzene is very stable and it's reactivity quite low.

⇒ All the C-C bonds of bezene have sp2-sp2 overlap on both sides, what makes them to form 3 π-bonds

5) The structure of the molecule is closed like a ring structure ⇔ <u>correct</u>

Since there are not enough electrons to form double bonds on all the carbon atoms, although the electrons do strengthen all of the bonds on the ring equally. This results in symmetric molecular orbital. The delocalisation of the electrons is also known as aromaticity or ring structure, what gives benzene a great stability.

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1 year ago
Describe the changes in properties (from metals to nonmetals or from nonmetals to metals) as we move (a) down a periodic group a
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Answer:

Explanation:

The changes in properties from metals to non-metals on a periodic table can be measured and determined by the metallicity or electropositivity of elements.

Metallicity is a measure of the tendency of atoms of an element to lose electrons.

a.

Down a periodic group, metallicity increases.

b.

Across a period from left to right electropositivity or metallicity decreases.

Metals are found in the left part of periodic table and the most reactive metal sits in the lower left corner. Non-metals are towards the right side of the table.

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2 years ago
Why does iron not fit the pattern in column 7
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Iron doesn't fit because it doesn't have enough atoms or protons in its nucleus so there for it belongs in column 2. <span />
3 0
2 years ago
Time Remaining: 1:27:31 If 50.0 g of H₂ and 100.0 g of O₂ react, how many moles of H₂O can be produced in the reaction below? 2
Novay_Z [31]

Answer:

Explanation:

2 H₂(g) + O₂(g) → 2 H₂O(g

2 moles     1 mole      2 mole

50 g of H₂ = 50 /2 = 25 moles of H₂

100 g of O₂ = 100 / 32 = 3.125 moles of O₂

So oxygen is the limiting reagent .

3.125 moles of O₂ will react with 6.25 moles of H₂ to give 6.25 moles of H₂O .

Hence moles of H₂O produced = 6.25 moles .

6 0
1 year ago
In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat
LiRa [457]

Answer: 1.14

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M

To calculate pH of gastric juice:

molarity of H^+ = 0.072

pH=-log[H^+]

pH=-log(0.072)=1.14

Thus the pH of the gastric juice is 1.14

3 0
2 years ago
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