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Nostrana [21]
2 years ago
7

What is the density (in g/L) of a gas with a molar mass of 146.06 g/mol at 1.03 atm and 297k

Chemistry
1 answer:
marshall27 [118]2 years ago
6 0
Lets assume the gas is acting Ideally, then According to Ideal Gas Equation the density is given as,

                                            d  =  P M / R T         -------  (1)
Where;
P  = Pressure =  1.03 atm

M  = Molar Mass =  146.06 g/mol

R  = Gas Constant =  0.08206 atm.L.mol⁻¹.K⁻¹

T  = Temperature =   297 K

Putting Values in eq. 1,

           d  =  (1.03 atm × 146.06 g/mol) ÷ (0.08206 atm.L.mol⁻¹.K⁻¹ × 297 K)

                                          density  =  6.17 g/L
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The molar mass of an imaginary molecule is is 93.89 g/mol. Determine its density at STP.
Igoryamba

Answer:

Density = 4.191 gm/L

Explanation:

Given:

Molar mass = 93.89 g/mol

Volume(Missing) = 22.4 L (Approx)

Find:

Density at STP

Computation:

Density = Mass/Volume  

Density = 93.89 / 22.4  

Density = 4.191 gm/L

3 0
1 year ago
Two different compounds are obtained by combining nitrogen with oxygen. The first compound results from combining 46.7 gg of NN
mina [271]

Answer:

4.02

Explanation:

The mass ratios will be given by dividing the mass of O₂ into the mass of N₂.

So lets do our calculations:

First Compound:

53.3 g O₂ / 46.7 g N₂ =  1.14

Second Compound:

82.0 g O₂ / 17.9 g N₂ = 4.58

Ratio = 4.58 / 1.14 =  4.02

This result for all practical purposes is a whole number, and it is telling us that there are 4 times as many oxygen atoms in the second coumpound as in the first compound. This is so because the ratio we just calculated is also the ratio in mol atoms:

Ratio = [ mass O₂ / MW O2/ mass N₂/ MW N₂] 2nd compound  /   [mass O₂ / MW O2/ mass N₂/ MW N₂  !st compound]

and the molecular weights cancel each other.

The only N and O compounds that follow this ratio are N₂O₄ and N₂O, and this question could be made in a multiple choice to match  formulas.

3 0
2 years ago
An archeologist finds a 1.62 kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i
katovenus [111]
The  answer is

<span>The density (D) is quotient of mass (m) and volume (V):
</span>D= \frac{m}{V}
The unit is g/cm³

It is given:
m = 1.62 kg = 1620 g
V = 205 mL = 205 cm³
D = ?

Thus:
D= \frac{m}{V} = \frac{1620g}{205cm ^{3} } = 7.90 g/cm ^{3}

The density of the goblet is 7.90 g/cm³.
5 0
2 years ago
A particular sheet of paper measures 8.5 × 6.5 inches. What is the surface area of one side of the paper in cm2? (2.54 cm = 1 in
Zanzabum
<span>In order to calculate the surface are of the sheet of paper in square centimeters you must first convert the dimensions of the paper to centimeters. You can do this by multiplying 8.5 * 2.54 and 6.5 * 2.54. The paper measures 21.59cm by 16.51cm. To find the surface area you multiply the dimensions of the paper to equal 356.4509cm2</span>
4 0
2 years ago
Stephanie has been doing research on how petroleum is formed. She says that oxygen must be present while the tiny plants and ani
madreJ [45]

Answer:

No, Stephanie is incorrect. Formation of petroleum cannot take place under the presence of oxygen.

Explanation:

Since, the petroleum is fossil product. Fossil fuel are formed under high pressure and temperature with absence of oxygen for longer period. so the way she is performing is completely incorrect. With the presence of oxygen in no way petroleum will be formed. The temperature and pressure should be in different combination for the formation of the petroleum. Along with the layers of sediments to maintain the pressure is required.

5 0
2 years ago
Read 2 more answers
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