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aliya0001 [1]
2 years ago
6

A virus has a mass of ×9.010−12mg and an oil tanker has a mass of ×3.0107kg . Use this information to answer the questions below

. Be sure your answers have the correct number of significant digits.What is the mass of one mole of viruses in grams?
Chemistry
1 answer:
puteri [66]2 years ago
6 0

Answer: Mass of one mole of viruses in grams is 54\times 10^{8}  

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Given : One virus has mass of = 9.0\times 10^{-12}mg=9.0\times 10^{-15}g     1mg=10^{-3}g

One mole of virus 6.023\times 10^{23} has mass of = \frac{9.0\times 10^{-15}}{1}\times 6.023\times 10^{23}=54\times 10^{8}g  

Thus mass of one mole of viruses in grams is 54\times 10^{8}  

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A bag of fertilizer is labeled 10-20-20. What is the actual percentage of phosphorus in the fertilizer?
aleksandr82 [10.1K]

Answer:

20% of phosphorus

Explanation:

A fertilizer is used to improve the fertility of soils. Most fertilizers contains the element nitrogen, phosphorus and potassium.

They are often designated NPK fertilizers.

  Now we know that the numbers 10-20-20 depicts the nitrogen-phosphorus and potassium content of the fertilizer.

From the designation,

    The actual percentage is 20% of phosphorus.

                                               10%  of nitrogen

                                                20% of potassium

8 0
2 years ago
During translation, the new polypeptides are often directed to specific parts of the cell by the presence or absence of short se
kotegsom [21]

Answer:

The correct option is b. an amino-terminal signal

Explanation:

A polypeptide that will eventually fold to become an ion channel protein, it means a kind of integral membrane protein, has an amino terminal signal that indicates its delivery to endoplasmic reticulum (ER) and then to the membrane. This type of signal usually consist in a nucleus of 6 to 12 aminoacids and one or more basic aminoacids. Once the polypeptide enters the ER, this signal is removed.

6 0
2 years ago
Read the information on Hydrochloric Acid. List four ways you can avoid injury while using HCl and three steps you would take in
lisabon 2012 [21]

Answer:

Find the list and explanation below.

Explanation:

Hydrochloric acid shortened as HCl is a harmful chemical when not handled properly. Four ways to avoid injury with hydrochloric acid include;

1. Dilution: It is advised to dilute the concentrated hydrochloric acid with a reasonable amount of water so that its corrosive effect can be significantly reduced.

2. Wear a laboratory coat: When working with hydrochloric acid in the laboratory it is always advised to wear a laboratory suit so as to ensure a minimal amount of harm in case of an accident or spillage with the acid.

3. Wear a face shield: It is also important that a face shield is worn while working with the acid to prevent contact with the eyes.

4. Wear a protective rubber glove: The rubber gloves would ensure that there is minimal contact of the acid with the hands.

Three steps to be taken in case of an accidental exposure include;

1. Medical Attention: In serious cases, such as in a case of ingesting the acid, urgent medical help should be sought for immediately.

2. Water: If there is contact with the skin or eye, a lot of water should be used on the affected area, and then medical help obtained.

3. Inhalation of fresh air: In a case whereby the hydrochloric acid was inhaled for a long time, the affected person should try to get some fresh air and if other effects are noticed, urgent medical attention should be gotten.

3 0
2 years ago
A 100-W lightbulb is placed in a cylinder equipped with a moveable piston. The lightbulb is turned on for 0.020 h, and the assem
nasty-shy [4]

Answer: The workdone W = 505J

Explanation:

Applying the pressure-volume relationship

W= - PΔV

Where negative sign indicates the power is being delivered to the surrounding

W = - 1.0atm * ( 5.88 - 0.9)L

= - 1.0atm * (4.98)

W = -4.98 atmL

Converting to Joules

1atmL = 101.325J

-4.98atmL = x joules.

Work done in J = -4.98 * 101.325

W= -505J

Therefore the workdone is -505J

5 0
2 years ago
A solution of 0.108 M cysteine is titrated with 0.0540 M HNO3 . The pKa values for cysteine are 1.70 , 8.36 , and 10.74 , corres
kirill [66]

Answer:

2.698

Explanation:

Cysteine + H+ <==> cysteineH+

at the equivalence point

cosidering 1 L of cysteine solution

volume of HNO3 to reach equivalence point = 0.108 M x 1 L/0.0540 M = 2.0 L

[CysteineH+] formed = (0.108 M x 1 L)/(1.0 + 2.0) L = 0.036 M

hydrolysis of salt

cysteineH+ + H_2O <==> cysteine + H_3O+

let x amount hydrolyzed

Ka1 = [cysteine][H3O+]/[cysteineH+]

pKa1 = -log[Ka1] = 1.70

Ka = 0.02

so,

0.02 = x^2/(0.036-x)

x^2 + 0.02x - 0.00072 = 0

x = 0.002

pH at equivalence point = -log(0.002) = 2.698

5 0
2 years ago
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