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aliya0001 [1]
2 years ago
6

A virus has a mass of ×9.010−12mg and an oil tanker has a mass of ×3.0107kg . Use this information to answer the questions below

. Be sure your answers have the correct number of significant digits.What is the mass of one mole of viruses in grams?
Chemistry
1 answer:
puteri [66]2 years ago
6 0

Answer: Mass of one mole of viruses in grams is 54\times 10^{8}  

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Given : One virus has mass of = 9.0\times 10^{-12}mg=9.0\times 10^{-15}g     1mg=10^{-3}g

One mole of virus 6.023\times 10^{23} has mass of = \frac{9.0\times 10^{-15}}{1}\times 6.023\times 10^{23}=54\times 10^{8}g  

Thus mass of one mole of viruses in grams is 54\times 10^{8}  

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A proton transfer reaction can occur when an aldehyde is placed in strong base, such as an alkoxide ion, producing an alcohol an
Pani-rosa [81]

Hi, you have not provided structure of the aldehyde and alkoxide ion.

Therefore i'll show a mechanism corresponding to the proton transfer by considering a simple example.

Explanation: For an example, let's consider that proton transfer is taking place between a simple aldehyde e.g. acetaldehyde and a simple alkoxide base e.g. methoxide.

The hydrogen atom attached to the carbon atom adjacent to aldehyde group are most acidic. Hence they are removed by alkoxide preferably.

After removal of proton from aldehyde, a carbanion is generated. As it is a conjugated carbanion therefore the negative charge on carbon atom can conjugate through the carbonyl group to form an enolate which is another canonical form of the carbanion.

All the structures are shown below.

7 0
2 years ago
Ancient Egyptians used a variety of lead compounds as white pigments in their cosmetics, including PbS, PbCO3, PbCl(OH), and Pb2
ser-zykov [4K]

Answer : The compound contains the highest percentage of lead (by mass) is, PbS.

Explanation :

To calculate the percentage of lead in sample, we use the equation:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100

<u>For PbS :</u>

Mass of PbS = 239.3 g

Mass of Pb = 207.2 g

Putting values in above equation, we get:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{239.3g}\times 100=86.58\%

The percentage of lead in the PbS is 86.58 %.

<u>For PbCO_3 :</u>

Mass of PbCO_3 = 267.2 g

Mass of Pb = 207.2 g

Putting values in above equation, we get:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{267.2g}\times 100=77.55\%

The percentage of lead in the PbCO_3 is 77.55 %.

<u>For PbCl(OH) :</u>

Mass of PbCl(OH) = 259.7 g

Mass of Pb = 207.2 g

Putting values in above equation, we get:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{259.7g}\times 100=79.78\%

The percentage of lead in the PbCl(OH) is 79.78 %.

<u>For Pb_2Cl_2CO_3 :</u>

Mass of Pb_2Cl_2CO3_ = 545.3 g

Mass of Pb = 207.2 g

Putting values in above equation, we get:

\%\text{ of lead}=\frac{\text{Mass of lead}}{\text{Mass of sample}}\times 100=\frac{207.2g}{545.3g}\times 100=37.99\%

The percentage of lead in the Pb_2Cl_2CO3_ is 37.99 %.

Hence, from this we conclude that, the compound PbS contains the highest percentage of lead (by mass).

6 0
2 years ago
A red car and a black car begin to accelerate from rest at the same time. The red car accelerates at a constant rate of 3 meters
Vladimir79 [104]

That car moves or accelerates faster which has the higher speed.

If the red car accelerate at higher speed than black car then the red car reach first on the destination but if the black car moves with higher speed than red car then the black car reach its destination earlier than the red car.

The conclusion can be drawn when the image is present or any data but there is no data or image present which provides us accurate information so we can conclude logically that car which moves at higher speed will move faster than the other car.

Learn more: brainly.com/question/25525382

8 0
1 year ago
Convert 3.4 x 10^23 molecules of NaCl to grams
shusha [124]

Answer:

m_{NaCl}=33g

Explanation:

Hello,

In this case, in order to compute the grams of sodium chloride starting by the molecules, the first step is to compute the moles contained in the given amount of molecules by using the Avogadro's number:

n_{NaCl}=3.4x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules} =0.56mol

Then, by using the molar mass of sodium chloride (58.45 g/mol) we can directly compute the grams:

m_{NaCl}=0.56mol*\frac{58.45g}{1mol} \\\\m_{NaCl}=33g

Regards.

7 0
2 years ago
Current of 250. a flows for 24.0 hours at an anode where the reaction occurring is as follows: mn2+(aq) + 2h2o(l) → mno2(s) + 4h
Tju [1.3M]
From Faraday's 1st law of electrolysis,
Total electricity passed into system = Q = IT = 250 X 24 X 60 X 60
                                                                       = 2.16 X 10^7 C

We know that, 96500 C = 1 F
∴ 2.16 X 10^7 C =  <span>223.8 F
</span>
Now, number of moles of<span> MnO2  deposited = 223.8/2=111.9 
</span>
Finally, 1 mole of MnO2 ≡ 86.94 g
∴ 111.9 mole of MnO2 ≡  111.9 X 86.94 = 9728 g

Thus, <span>mass of MnO2 that will be deposited at anode = 9728 g</span>
7 0
2 years ago
Read 2 more answers
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