Hi!
The radical bromination reaction of C₆H₅CH₂CH₃ is performed through a mechanism in which radical reactions are involved. This compound is an alkylbenzene compound, and the carbon that is more reactive towards radical bromination is the carbon bonded to the aromatic ring because in the reaction mechanism the intermediaries are stabilized by resonance in the aromatic ring.
A terminal substitution will not occur because substitution there will not be stabilized by resonance. The compound that will be formed in this reaction would be:
C₆H₅CH₂CH₃ + Br₂ → C₆H₅CH₂(Br)CH₃ + HBr
Well ask yourself why don't we count it in moles and you should get your answer.
First, let us find the corresponding amount of moles H₂ assuming ideal gas behavior.
PV = nRT
Solving for n,
n = PV/RT
n = (6.46 atm)(0.579 L)/(0.0821 L-atm/mol-K)(45 + 273 K)
n = 0.143 mol H₂
The stoichiometric calculations is as follows (MW for XeF₆ = 245.28 g/mol)
Mass XeF₆ = (0.143 mol H₂)(1 mol XeF₆/3 mol H₂)(245.28 g/mol) = <em>11.69 g</em>
Different wavelength are involved.
Explanation:
If magnesium burns with a bright white flame, one can conclude that different wavelengths accompany the electron transitions for the magnesium atom.
- When an atom burns, the electrons in it are excited.
- They give out characteristic light commensurate with their energy.
- A white light is made up of different combinations of wavelength of radiations.
- When we see a white light we can infer that different joined together in the emission observed.
Learn more:
Spectrum brainly.com/question/6255073
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