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Alexeev081 [22]
2 years ago
8

What volume of 0.500 M HNO₃(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?

Chemistry
1 answer:
USPshnik [31]2 years ago
4 0

Answer:

v = 500 milliliters

Explanation:

HNO_{3}  ⇒  H^{+}  + NO^{3-}

KOH  ⇒  K^{+}  + OH^{-}

1 H^{+} to 1 OH^{-}

\frac{0,5}{V}  = \frac{0,1}{100} \\\\v * 0,1 = 50\\v = 500 milliliters

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