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Lesechka [4]
2 years ago
15

A student assistant is cleaning up after a chemistry laboratory exercise and finds three one-liter bottles containing alcohol so

lutions. The first bottle is one-half full with a 20% alcohol solution, the second bottle is one-fifth full with a 30% alcohol solution, and the third bottle is one-tenth full with a 50% alcohol solution. The student pours the contents of all three bottles into an empty one-liter bottle. What is the approximate alcohol content of this mixed solution
Chemistry
1 answer:
Svetllana [295]2 years ago
3 0

The approximate alcohol content is 210 ml.

Explanation:

It can be deduced from the question that each bottle is of 1000ml or 1 litre.

The first bottle is one half full means it has 500 ml of solution and it has 20% alcohol in it. So volume of alcohol in the solution is

20/100*500

=100 ml

The first bottle is one fifth full, so the volume of mixture is 1/5th of 1000ml

so it is 200ml having 30% alcohol

30/100*200

= 60 ml

The third bottle is one tenth full so its volume is 1/10*1000

100 ml.  having 50% of alcohol

50/100*100

50 ml.

The alcohol content obtained from all these 3 litres is:

100+60+50

= 210 ml of alchohol is obtained from 800 ml of mixture.

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Answer: intermolecular forces are described as forces that either cause attraction or repulsion between neighbouring particles or molecules

Explanation: liquids with strong intermolecular forces has the following properties:

1.) High boiling point

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3.) Low viscosity

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While liquids with weak intermolecular forces has the following properties:

1.) Low boiling point

2.)low surface tension

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3 0
2 years ago
What is the mass of a sample of NH3 containing 7.20 × 1024 molecules of NH3? 161 grams 187 grams 203 grams 214 grams
Shkiper50 [21]

Answer:

203 grams

Explanation:

<em>It is known that 1.0 mole of a compound contains Avogadro's number of molecules (6.022 x 10²³). </em>

<em><u>Using cross multiplication:</u></em>

1.0 mol contains → 6.022 x 10²³ molecules.

??? mol contains → 7.2 x 10²⁴ molecules.

∴ The no. of moles of (6.3 x 10²⁴ molecules) of NH₃ = (1.0 mol)(7.2 x 10²⁴ molecules)/(6.022 x 10²³ molecules) = 11.96 mol.

<em>∴ The no. of grams of NH₃ present = no. of moles x molar mass </em>= (11.96 mol)(17.0 g/mol) = <em>203.3 g ≅ 203.0 g.</em>

7 0
2 years ago
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In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen)
Maru [420]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.6 L  

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Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

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7 0
2 years ago
There is water on the pan of the scale as you measure the mass of an object. If you were to ignore the water, what would be the
mihalych1998 [28]
Remember that density refers to the "mass per unit volume" of an object.

So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.

In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is

As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:

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The effect on density would be that it would erroneously appear to be greater

Hope this helps!

Good luck
6 0
2 years ago
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