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lora16 [44]
2 years ago
11

Label the molecular shape around each of the central atoms in the amino acid glycine. hint

Chemistry
2 answers:
svetlana [45]2 years ago
6 0

The Structure of Glycine is attached below and each central atom is encircled with different colors.

Molecular Shape around Nitrogen Atom (Orange):

As shown, Nitrogen is making three single bonds with two hydrogen atoms and one carbon atom hence, it has three bonded pair electrons and a single lone pair of electron. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Trigonal Pyramidal.

Molecular Shape around Carbon Atom (Green):

As shown, Carbon is making four single bonds with two hydrogen atoms and one nitrogen atom one with carbon atom of carbonyl group hence, it has four bonded pair electrons. Therefore, according to VSEPR theory it has Tetrahedral geometry.

Molecular Shape around Carbon Atom (Blue):

As shown, Carbon is making two single bonds with oxygen and carbon atoms and a double bond with oxygen. Hence, it has a Trigonal Planar geometry.

Molecular Shape around Oxygen Atom (Red):

As shown, Oxygen is making two single bonds with one carbon atoms and one hydrogen atom hence, it has two bonded pair electrons and two lone pair of electrons. Therefore, according to VSEPR theory it has a tetrahedral electronic geometry but due to repulsion created by lone pair of electrons its molecular geometry becomes Bent.


Natalija [7]2 years ago
5 0

The molecular shape around nitrogen is \boxed{{\text{trigonal planar}}}.

The molecular shape around orange carbon is \boxed{{\text{tetrahedral}}}.

The molecular shape around pink carbon is \boxed{{\text{tetrahedral}}}.

The molecular shape around oxygen is \boxed{{\text{linear}}}.

Further Explanation:

VSEPR or Valence Shell Electron Pair Repulsion theory is used for the prediction of the shapes of the molecules by the arrangement of electron pairs around the central atom. According to this theory, such a shape is adopted by the molecule in which it experiences a minimum electron repulsion. Refer the table at the end of the answer for the molecular shapes predicted by the number of electron pairs.

Nitrogen forms two single bonds with two hydrogen atoms and one single bond with one carbon atoms (Refer structure at the end). So three bond pairs are present around the nitrogen atom. According to VSEPR theory, the molecular shape around nitrogen is trigonal planar.

The orange-colored carbon atom forms two single bonds with two hydrogen atoms, one single bond with one nitrogen and pink carbon atom separately (Refer structure at the end). So four bond pairs are present around the orange carbon atom. According to VSEPR theory, the molecular shape around this carbon atom is tetrahedral.

The pink-colored carbon atom forms one single bond with the orange carbon and one oxygen atom separately and one double bond with the other oxygen atom (Refer structure at the end). So four bond pairs are present around the pink carbon atom. According to VSEPR theory, the molecular shape around this carbon atom is tetrahedral.

Oxygen forms one single bond with pink carbon and one single bond with one hydrogen atom (Refer structure at the end). So two bond pairs are present around the oxygen atom. According to VSEPR theory, the molecular shape around oxygen is linear.

Learn more:  

1. Mass of copper: brainly.com/question/1680090  

2. Transformation in chemistry by Lavoisier: brainly.com/question/5310569

Answer details:  

Grade: Senior School  

Subject: Chemistry  

Chapter: Covalent bonding and molecular structure

Keywords: glycine, amino acid, molecular shape, central atom, linear, tetrahedral, trigonal planar, oxygen, nitrogen, carbon, VSEPR, repulsion, single bonds, double bond.

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What is the conjugate acid of each of the following? What is the conjugate base of each?
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Answer:

a. H₂O (conjugate acid) ; b. OH⁻ (conjugate base), H₃O⁺ (conjugate acid) ; c. H₂CO₃ (conjugate acid), CO₃⁻² (conjugate base) ; d. NH₄⁺ (conjugate strong acid) e. H₂SO₄ (conjugate acid), SO₄⁻² (conjugate base) ; f. No conjugate acid either base;  g. H₂S (conjugate acid), S⁻² (conjugate base);

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Explanation:

a.  OH⁻  +  H⁺  ⇄ H₂O

The hydroxide acts like a Bronsted Lory base, so it can catch a proton. Water will be the conjugate acid.

b. H₂O, is an amphoterus compound. It can act as an acid or a base. If it is a base, the conjugate acid is the H₃O⁺. If it is an acid, the conjugate base is the OH⁻.

c. HCO₃⁻  +  H⁺  ⇄  H₂CO₃

HCO₃⁻  +  H₂O  ⇄ CO₃⁻²  +  H₃O⁺

The bicarbonate is also amphoteric. When it catches the proton, the carbonic acid is the conjugate acid, cause it works as a base.

When the HCO₃⁻ (acid) release the proton, the conjugate base is the carbonate.

d. Ammonia is a weak base, so the conjugate strong acid is the ammonium.

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e. Another amphoteric compound. The acid sulfate acts an acid and a base.

(like bicarbonate). When it is a base, the conjugate acid is the sulfuric acid, when it is an acid, the conjugate base is the sulfate.

HSO₄⁻  +  H₂O  ⇄  SO₄⁻²  +  H₃O⁺

HSO₄⁻  +  H⁺  ⇄  H₂SO₄

f. H₂O₂ does not recieve H⁺ or OH⁻, and it does not release H⁺. It is a neutral compound and it doesn't act as a base or acid.

g. HS⁻ is amphoterous.

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Same case as bicarbonate or acid sulfate.

h. H₅N₂⁺  +  H₂O  ⇄  H₄N₂  + H₃O⁺

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Therefore:
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Now, we know that 2 x </span><span> 117.5 = 235 grams of ammonium perchlorate are required to produce 28 grams of nitrogen. We can use cross multiplication to determine the amount of hydrogen produced from 3.1 grams of ammonium perchlorate as follows:
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