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ki77a [65]
1 year ago
15

Which diastereomer of oct−4−ene yields a single meso compound, (4r, 5s)−4,5−dibromooctane on reaction with br2?

Chemistry
1 answer:
stepladder [879]1 year ago
4 0
How does that mean that the number is a little too late and you don’t have a phone number so you please look at it
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A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6
Alexxandr [17]
Specific heat capacity is the required amount of heat per unit of mass in order to raise teh temperature by one degree Celsius. It can be calculated from this equation: H = mCΔT where the H is heat required, m is mass of the substance, ΔT is the change in temperature, and C is the specific heat capacity.

H = m<span>CΔT
2501.0 = 0.158 (C) (61.0 - 32.0)

C = 545.8 J/kg</span>·°C
5 0
2 years ago
An aqueous solution of licl is 34.0 % licl. what mass of water is present in 250.0 g of the solution? (density of water is 1.00
adell [148]
<span>If the aqueous solution is 34% Licl then it is 100 - 34% water = 66% From the calculation we've found out that it is 66% water. Then we need to find the weight from a 250 g solution. 66/100 * 250 = 165g Hence it is 165g</span>
4 0
1 year ago
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Suppose you place an ice cube into a cup of hot tea? What will happen to the temperature of the ice cube and the tea? A) The tem
Ksivusya [100]

Answer:

The answer is D

Explanation:

8 0
2 years ago
What would the % p, on the npk ratio, be reported as for a 100g sample containing 7.5g of phosphorous?
kati45 [8]
When the concentration is expressed in percentage, you simply have to divide the amount of substance to the total amount of the mixture, then multiply it by 100. In this case, when you want to find the percentage of P in the sample, the solution is as follows:

%P = 7.5 g/100 g * 100 =<em> 7.5%</em>
6 0
1 year ago
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An unknown element X has the following isotopes: ²⁵X (80.5% abundant) and ²⁷X (19.5% abundant). What is the average atomic mass
IgorC [24]

Answer:

25.39

Explanation:

Given parameters:

Abundance of X-25  = 80.5%

Abundance of X - 27  = 19.5%

Unknown:

Average atomic mass of X  = ?

Solution:

The average atomic mass of X can be derived using the expression below:

Average atomic mass = (abundance x mass of X - 25) + (abundance x mass of X - 27)

Average atomic mass  =  (80.5%  x 25) +   (19.5% x 27)  = 25.39

5 0
1 year ago
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