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riadik2000 [5.3K]
2 years ago
13

if the fundamental frequency of a certain string is 84 hz, what is the frequency of the second harmonic? 42 hz 84 hz 126 hz 168

hz
Chemistry
2 answers:
neonofarm [45]2 years ago
6 0

<u>Answer:</u> The frequency of the second harmonics is 168 Hz.

<u>Explanation:</u>

Fundamental frequency is the frequency associated with the ground state energy level. It is denoted by f_0

Second harmonic frequency is the frequency associated with the second energy level where n = 2. It is denoted by f_1

The relationship between fundamental and second harmonic frequency is:

f_1=2f_0

We are given:

f_0=84Hz

Putting value in above relationship, we get:

f_1=2\times 84=168Hz

Hence, the frequency of the second harmonics is 168 Hz.

makkiz [27]2 years ago
3 0
Fundamental frequency, f₀ = 84 Hz

Second harmonic is  2f₀ = 2* 84 Hz = 168 Hz
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Answer:

9.88

Explanation:

As higher is the Ksp, more soluble is the compound. So, Co(OH)₂ is the less soluble hydroxide.

The maximum concentration of it must be 1x10⁻⁶ M, and the reaction is:

Co(OH)₂(s) ⇄ Co⁺²(aq) + 2OH⁻(aq)

So, [Co⁺²] = 1x10⁻⁶M

Ksp =  [Co⁺²] *[OH⁻]²

[OH⁻]² = 5.9x10⁻¹⁵/1x10⁻⁶

[OH⁻] = √(5.9x10⁻⁹)

[OH⁻] = 7.6811x10⁻⁵

pOH = -log[OH⁻]

pOH = -log(7.6811x10⁻⁵)

pOH = 4.11

Knowing that pH + pOH = 14

pH = 14 - 4.11

pH = 9.88

7 0
1 year ago
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Calculate the heat of reaction, ΔH°rxn, for overall reaction for the production of methane, CH4.
Lesechka [4]

<u>Answer:</u> The enthalpy of the reaction for the production of CH_4 is coming out to be -74.9 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H^o

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]

For the given chemical reaction:

C(s)+2H_2(g)\rightarrow CH_4(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(CH_4(g))})]-[(1\times \Delta H^o_f_{(C(s))})+(2\times \Delta H^o_f_{(H_2(g))})]

We are given:

\Delta H^o_f_{(C(s))}=0kJ/mol\\\Delta H^o_f_{(H_2)}=0kJ/mol\\\Delta H^o_f_{CH_4}=-74.9kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-74.9))]-[1\times 0)+(2\times 0)]\\\\\Delta H^o_{rxn}=-74.9kJ

Hence, the enthalpy of the reaction for the production of CH_4 is coming out to be -74.9 kJ

3 0
2 years ago
The button batteries in small devices like watches are commonly composed of silver-zinc or mercury-zinc batteries. The reaction
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Answer:

The mercury button battery line notation is:

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Mercury batteries either use

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The first step is an electrochemical reaction step:

Zn + 4OH− → Zn(OH)4−2 + 2e−[3]

cathode has a half reaction :

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+0.0977 V  standard potential is of this reaction.

which is followed by a chemical reaction step:

Anode consists of oxidation:

Zn+2OH>ZnO+H2O+2e

which gives an overall anode half-reaction of:

Zn + 2OH− → ZnO + H2O + 2e−[3]

Therefore,

The overall reaction for the battery is:

Zn + HgO → ZnO + Hg

7 0
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Answer:

Total Ionic equation:

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Explanation:

Chemical equation:

HNO₃ + NaOH →  NaNO₃ + H₂O

Balanced chemical equation:

HNO₃(aq) + NaOH(aq) →  NaNO₃(aq) + H₂O(l)

Total Ionic equation:

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Net ionic equation:

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The NO₃⁻ (aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation

6 0
1 year ago
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