In 2021, you were given a 100. g wine sample to verify its age. Using tritium dating you observe that the sample has 0.688 decay
1 answer:
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Answer:
Explanation:
Given the moles, we are asked to find the mass of a sample.
We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.
Multiply by the given number of moles, which is 2.0
The moles of methanol will cancel each other out.
The denominator of 1 can be ignored.
Multiply.
There are 64 grams of methanol in the sample.
<em>The mass of a gold bar = 1.424 x 10⁴ gram</em>
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<h3><em>Further Explanation</em></h3>Density is a quantity derived from the mass and volume
density is the ratio of mass per unit volume
With the same mass, the volume of objects that have a high density will be smaller than type
The unit of density can be expressed in g / cm3 or kg / m3
Density formula:
ρ = density
m = mass
v = volume
A common example is the water density of 1 gr / cm3
The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force
<em>Known variable</em>
volume gold bar 7.379 × 10⁻⁴ m³
a density of 19.3 g/cm³
<em>Asked</em>
the mass of a gold bar
<em>Answer</em>
volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density
7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³
then:
mass = volume x density
mass = 7.379 × 10² cm³ x 19.3 g/cm³
mass = 1.424 x 10⁴ gram
<h3><em>Learn more </em></h3>density acetone
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Keywords: density, mass, volume, a gold bar
Answer:
Explanation:
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In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:
Thus, we solve for the molarity of the acid to obtain:
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Answer: The molecular formula will be
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C= 70.6 g
Mass of H = 5.9 g
Mass of O = 23.5 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of H =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For O =
The ratio of C : H: O= 4: 4:1
Hence the empirical formula is
The empirical weight of = 4(12)+4(1)+1(16)= 68g.
The molecular weight = 136 g/mole
Now we have to calculate the molecular formula.
The molecular formula will be=