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ira [324]
2 years ago
14

Phosphoric acid has a pka of 2.1. at what ph will 75% of phosphoric acid be in the conjugate base form?

Chemistry
2 answers:
Colt1911 [192]2 years ago
8 0

Answer:

pH is 2.58

Explanation:

The pH of the buffer made from the mixture of phosphoric acid (H₃PO₄) and its conjugate base form (H₂PO₄⁻) follows the Henderson-Hasselbalch equation:

pH = pka + log [H₂PO₄⁻] /[H₃PO₄]

If 75% of the buffer is in the conjugate base form (H₂PO₄⁻), 25% will be as H₃PO₄. Replacing to find pH:

pH = 2.1 + log [75%] /[25%]

pH = 2.58

<em>pH is 2.58</em>

<em></em>

EleoNora [17]2 years ago
5 0

solution:

from henderson hasselbalch equation\\pH=pka+log[\frac{conjugate}{acid}]\\given[\frac{conjugate base}{acid}]\\=\frac{75}{25}=3\\PH=2.1+log3\\pH=2.1+0.5=2.6

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Answer:

A) homotopic and B) enantiotopic

Explanation:

Protons chemically equivalent are those that have the same chemical shift, also if they are interchangeable by some symmetry operation or by a rapid chemical process.

The existence of symmetry axes, Cn, that relate to the protons results in the protons being homotopic, that is chemically equivalent in both chiral and aquiral environments.

The existence of a plane of symmetry, σ, makes the protons related by it, are enantiotopic and these protons will only be equivalent in an aquiral medium; if the medium is chiral both protons will be chemically NOT equivalent. The existence of a center of symmetry, i, in the molecule makes the related protons through it enantiotopic and therefore chemically only in the aquiral medium.

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Initially, 50.0 g iron(iii) chloride is present. what amount of fecl3 is this, in moles?
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Answer:

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