we are given
a swimming pool contains 2,850 kiloliters (kL) of water
2,850 kiloliters (kL)=2850000L
we know that
Firstly , we will find for 1L
now, we can multiply both sides by 2850000
so,
a swimming pool contains 752972.25892gal of water...........Answer
Colligative properties are usually used in relation to solutions.
Colligative properties are those properties of solutions, which depend on the concentration of the solutes [molecules, ions, etc.] in the solutions and not on the chemical nature of those chemical species. Examples of colligative properties include: vapour pressure depression, boiling point elevation, osmotic pressure, freezing point depression, etc.
For the question given above, the correct option is D. This is because the statement is talking about freezing point elevation, which is not part of colligative properties.
There is an exact value for the standard volume at standard conditions of 1 atm and 273 K. This standard volume for any ideal gas is 22.4 L/mol. Thus,
Moles SO₂ = 5.9 L * 1 mol/22.4 L = 0.263 mol
The molar mass for SO₂ is 64.066 g/mol. So, the mass is:
Mass = 0.263 mol * 64.066 g/mol = <em>16.87 g SO₂</em>
Answer:
The Michaelis‑Menten equation is given as
v₀ = Kcat X [E₀] X [S] / (Km + [S])
where,
Kcat is the experimental rate constant of the reaction; [s] is the substrate concentration and
Km is the Michaelis‑Menten constant.
Explanation:
See attached image for a detailed explanation
