Answer:
A) homotopic and B) enantiotopic
Explanation:
Protons chemically equivalent are those that have the same chemical shift, also if they are interchangeable by some symmetry operation or by a rapid chemical process.
The existence of symmetry axes, Cn, that relate to the protons results in the protons being homotopic, that is chemically equivalent in both chiral and aquiral environments.
The existence of a plane of symmetry, σ, makes the protons related by it, are enantiotopic and these protons will only be equivalent in an aquiral medium; if the medium is chiral both protons will be chemically NOT equivalent. The existence of a center of symmetry, i, in the molecule makes the related protons through it enantiotopic and therefore chemically only in the aquiral medium.
Diastereotopic protons cannot be interconverted by any symmetry operation and they are different, with different chemical displacement.
1, Read the entire lab procedure through and make sure it is understandable. 2, Put on safety goggles and an apron. 3, Check the flask for chips and cracks. 4, <span> Use heat-resistant gloves or tongs to swirl the flask.</span>
One mole of a compound contains the mass equivalent to the molecular mass or relative formula mass of the compound.
1 mole of iron iii chloride contains a mass of 162.2 g.
Therefore, 50 g will contain 50 g/162.2 g = 0.3083 moles
= 0.3083 moles of Fe2Cl3
<span>The hint here is to look at the anion of the compound. That is the polyatomic ion, sulfate or SO4. It has a charge of -2. Since the compound does not show any subscript, then it means that the cation must have a charge of +2 for it to be cancelled out. Hence, the elements that can represent X are the elements that have a +2 charge like Fe, Ca, Ba, Mg, Zn, etc.</span>
Answer:
% yield = 58.33 %
Explanation:
∴ moles X = 2.00 mol
∴ moles Y = 2.00 mol
∴ moles Z = 1.75 mol = moles produced
- % Yield = ( moles produced / theoretical moles ) × 100
theoretical moles:
⇒ moles Z = (2.00 mol X)*(3 mol Z/2 mol X) = 3.00 mol Z
⇒ % yield = [(1.75 mol produced)/(3.00 theoretical mol)]×100
⇒ % yield = 58.33 %
