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Leona [35]
2 years ago
7

A 500.0 ml buffer solution is 0.10 m in benzoic acid and 0.10 m in sodium benzoate and has an initial ph of 4.19. part a what is

the ph of the buffer upon addition of 0.025 mol of naoh?
Chemistry
1 answer:
slavikrds [6]2 years ago
8 0
Initial moles of C₆H₅COOH = 500/1000 × 0.10 = 0.05mol
Initial moles of C₆H₅COONa = 500/1000 × 0.10 = 0.05 mol
initial pH = Pka + log([C₆H₅COONa/ moles of C₆H₅COOH)
4.19 = pKa + log(0.05/0.05)
→pKa = 4.19
C₆H₅COOH + NaOH → C₆H₅COONa ₊ H₂o
moles of NaOH added = 0.010 mol
moles of C₆H₅COOH = 0.05 - 0.025 = 0.025 mol
Final pH = pKa + log([C₆H₅COONa)/[ C₆H₅COOH])
=pKa + log(moles of C₆H₅COONa/moles of C₆H₅COOH)
= 4.19 + log(0.025/0.075)
4.29
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Answer:

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Explanation:

The above reaction is least energetic because there is no phosphoanhydride bond present with adenosine mono phosphate.Phospho anhydride bond is an energy rich bond.

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8 0
2 years ago
Given that cao(s) + h2o(l) → ca(oh)2(s), δh°rxn = –64.8 kj/mol, how many grams of cao must react in order to liberate 525 kj of
USPshnik [31]

Answer:

454.3 g.

Explanation:

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1.0 mol of CaO liberates → – 64.8 kJ.

??? mol of CaO liberates → - 525  kJ.

∴ The no. of moles needed = (1.0 mol)(- 525 kJ)/(- 64.8 kJ) = 8.1 mol.

<em>∴ The no. of grams of CaO needed = no. of moles x molar mass</em> = (8.1 mol)(56.077 g/mol) = <em>454.3 g.</em>

8 0
2 years ago
How much heat must be removed from 25.0g of steam at 118.0C in order to form ice at 15C
NemiM [27]

Answer:

-10778.95 J heat must be removed in order to form the ice at 15 °C.

Explanation:

Given data:

mass of steam = 25 g

Initial temperature = 118 °C

Final temperature = 15 °C

Heat released = ?

Solution:

Formula:

q = m . c . ΔT

we know that specific heat of water is 4.186 J/g.°C

ΔT = final temperature - initial temperature

ΔT = 15 °C - 118 °C

ΔT = -103 °C

now we will put the values in formula

q = m . c . ΔT

q = 25 g × 4.186 J/g.°C × -103 °C

q = -10778.95 J

so, -10778.95 J heat must be removed in order to form the ice at 15 °C.

3 0
2 years ago
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Arlecino [84]

Answer:

A. \lambda_0=2.196\times 10^{-7}\ m

Explanation:

The work function of the Platinum = 9.05\times 10^{-19}\ J

For maximum wavelength, the light must have energy equal to the work function. So,

\psi _0=\frac {h\times c}{\lambda_0}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda_0 is the wavelength of the light being bombarded

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Thus,

9.05\times 10^{-19}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda_0}

\frac{9.05}{10^{19}}=\frac{19.878}{10^{26}\lambda_0}

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8 0
2 years ago
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tino4ka555 [31]

Answer:

<h3>Pressure of CO_2 in the container=1.6 atm</h3>

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CaCO_3(s) ⇄  CaO(s) + CO_2(g)

two components are solid so these two will not exert any kind of pressure in the container so at equilibrium only CO2 will apply pressure on the container

Therefore only partial pressure of CO2 will be taken for the calculation of equilibrium pressure constant i.e. Kp

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Pressure of CO_2 in the container=1.6 atm

8 0
2 years ago
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