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Katena32 [7]
2 years ago
6

which diagram best illustrates the ion-molecule attractions that occur when the ions of NaCl(s) are added to water

Chemistry
1 answer:
tatuchka [14]2 years ago
8 0
Diagram is on the picture below.
Answer is: 1).
Sodium chloride is ionic compound and in the water dissociate in sodium cation (positive charge) and chloride anion (negative charge). Water is polar compound, oxagan has negative charge and hydrogen charge. Positive interact witn negative charge and negative with positive charge.

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Eddie is going to do an experiment to find out which freezes more easily—distilled water or salt water. In what order should he
mel-nik [20]

1. Make a Prediction

2. Fill both beakers with water

3. Dissolve salt in one of the beakers

4. Place both in the freezer and observe

5. Write a report

(Always make the prediction first! That's a hypothesis!)

4 0
2 years ago
Read 2 more answers
Calculate the amount of work done against an atmospheric pressure of 1.00 atm when 500.0 g of zinc dissolves in excess acid at 3
ZanzabumX [31]

Answer:

19,26 kJ

Explanation:

The work done when a gas expand with a constant atmospheric pressure is:

W = PΔV

Where P is pressure and ΔV is the change in volume of gas.

Assuming the initial volume is 0, the reaction of 500g of Zn with H⁺ (Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g)) produce:

500,0g Zn(s)×\frac{1molZn}{65,38g}×\frac{1molH_{2}(g)}{1molZn} = 7,648 moles of H₂

At 1,00atm and 303,15K (30°C), the volume of these moles of gas is:

V = nRT/P

V = 7,648mol×0,082atmL/molK×303,15K / 1,00atm

V = 190,1L

That means that ΔV is:

190,1L - 0L = <em>190,1L</em>

And the work done is:

W = 1atm×190,1L = 190,1atmL.

In joules:

190,1 atmL×\frac{101,325}{1atmL} = <em>19,26 kJ</em>

I hope it helps!

5 0
2 years ago
Determine the percent composition by mass of a 100g salt solution which contains 20g salt
prisoha [69]

Answer:

Mass of solution=100g

mass of salt=20g

so; mass of solute=80g

percentage composition =(mass of salt/total

mass) ×100

=  \frac{20}{100}  \times 100 \\  = 20\%

glad to help you

hope it helps

8 0
1 year ago
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The specific rotation of (R) carvone is (+) 61°. The optical rotation of a sample of a mixture of R &amp;S carvone is measured a
shusha [124]

Answer:

See explanation

Explanation:

% optical purity = specific rotation of mixture/specific rotation of pure enantiomer  * 100/1

specific rotation of mixture = 23°

specific rotation of pure enantiomer = 61°

Hence;

% optical purity = 23/61 * 100 = 38 %

More abundant enantiomer = 100% - 38 % = 62%

Hence the pure  (S) carvone is (-) 62° is the more abundant enantiomer.

Enantiomeric excess = 62 - 50/50 * 100 = 24%

Hence

(R) - carvone  =  38 %

(S) - carvone = 62%

7 0
1 year ago
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The equilibrium reaction below has the Kc = 4.00 at 25°C. If the temperature of the system at equilibrium is increased to 100°C,
professor190 [17]

Answer:

Following are the answer to this question:

Explanation:

In the given question information is missing, that is equation which can be defined as follows:

CH_4(g)+H_2O(g)\rightarrow CO(g)+3H_2(g)   \ \ \bigtraingleup H^0=+206.2KJ

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2 years ago
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