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1 year ago

How are NGC 1427A and U different? How are they the same?

Chemistry

2 answers:

irga5000 [103]1 year ago

5 0

Answer:

Sample Response: NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in that both contain plenty of dust and gas. Both also have active star-forming sites.

Explanation:

Which ideas did you include in your answer? Check all that apply.

✅ NGC 1427A is an irregular galaxy.

✅ U is a spiral galaxy.

✅ Both galaxies contain plenty of dust and gas.

✅ Both galaxies have active star-forming sites.

Ik I'm late but YW

agasfer [191]1 year ago

3 0

Answer:

that looks pretty and also well NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in the both certain plenty of dust and gas. Both also have active star-forming sites.

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The mass of a solid copper penny is 3.46 g. how many copper atoms are in the penny?

solong [7]

3.46 g Cu 1 mol Cu 6.02*10^23 atoms Cu =
63.55 g Cu 1 mol Cu

3.28*10^22 atoms Cu

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2 years ago

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What are the empirical formulas of a) ethylene glycol, a radiator antifreeze, molecular formula C2H6O2 b) peroxodisulfuric acid,

Temka [501]

<h2>The answers are $CH_3O$ and $HSO_4$ </h2>

Explanation:

Given -

a) The molecular formula of ethylene glycol -

$C_2H_6O_2$

∴ The empirical formula of ethylene glycol will be -

$CH_3O$

Given -

b) The molecular formula of per-oxo-disulfuric acid (a compound used in bleaching agents) -

$H_2S_2O_8$

∴ The empirical formula of per-oxo-disulfuric acid will be -

$HSO_4$

Hence, the answers are $CH_3O$ and $HSO_4$ .

6 0

2 years ago

A solution is prepared by dissolving 91.7 g fructose in 545 g of water. Determine the mole fraction of fructose if the final vol

oee [108]

Answer:

Mole fraction = 0,0166

Explanation:

Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.

The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:

91,7g fructose × (1mol / 180,16g) = <em>0,509 moles of fructose</em>

545g water × (1mol / 18,02g) = <em>30,24 moles of water</em>

Thus, mole fraction of fructose is:

$\frac{0,509 moles}{0,509mol + 30,24mol} = 0,0166$

<em>Mole fraction = 0,0166</em>

I hope it helps!

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2 years ago

A human lung at maximum capacity has a volume of 3.0 liters. If the partial pressure of oxygen in the air is 21.1 kilopascals an

MrRa [10]

Answer : 0.026 moles of oxygen are in the lung

Explanation :

We can solve the given question using ideal gas law.

The equation is given below.

$PV = nRT$

We have been given P = 21.1 kPa

Let us convert pressure from kPa to atm unit.

The conversion factor used here is 1 atm = 101.3 kPa.

$21.1 kPa \times \frac{1atm}{101.3kPa}= 0.208 atm$

V = 3.0 L

T = 295 K

R = 0.0821 L-atm/mol K

Let us rearrange the equation to solve for n.

$n = \frac{PV}{RT}$

$n = \frac{0.208atm\times 3.0L}{0.0821 L.atm/mol K\times 295 K}$

$n = 0.026 mol$

0.026 moles of oxygen are in the lung

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2 years ago

while your finger is still pushing the coin, there are four forces acting on the coin: what are they?

Viefleur [7K]

Is there some kind of diagram? how is your finger pushing the coin, and where? It may be:
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2 years ago

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