The balloon will reach its maximum volume and it will burst.
Given:
- A weather balloon at sea level, with gas at 65.0 L volume, 745 Torr pressure, and 25C temperature.
- When the balloon was taken to an altitude at which temperature was 25C and pressure was 0.066atm its volume expanded.
- The maximum volume of the weather balloon is 835 L.
To find:
Whether the weather balloon will reach its maximum volume or not.
Solution:
The pressure of the gas in the weather balloon at sea level = 
The volume of the weather balloon at sea level = 
The temperature of the gas in the weather balloon at sea level:
The balloon rises to an altitude.
The pressure of the gas in the weather balloon at the given altitude:
The volume of the weather balloon at the given altitude = 
The temperature of the gas in the weather balloon at the given altitude:
Using the Combined gas law:
The maximum volume of the weather balloon= V = 835 L
The volume of the weather balloon at a given altitude is greater than its maximum volume which means the balloon will reach its maximum volume and it will burst.
Learn more about the combined gas law:
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Q1)
molarity is defined as the number of moles of solute in 1 L solution
the number of moles of LiNO₃ - 0.38 mol
volume of solution - 6.14 L
since molarity is number of moles in 1 L
number of moles in 6.14 L - 0.38 mol
therefore number of moles in 1 L - 0.38 mol / 6.14 L = 0.0619 mol/L
molarity of solution is 0.0619 M
Q2)
the mass of C₂H₆O in the solution is 72.8 g
molar mass of C₂H₆O is 46 g/mol
number of moles = mass present / molar mass of compound
the number of moles of C₂H₆O - 72.8 g / 46 g/mol
number of C₂H₆O moles - 1.58 mol
volume of solution - 2.34 L
number of moles in 2.34 L - 1.58 mol
therefore number of moles in 1 L - 1.58 mol / 2.34 L = 0.675 M
molarity of C₂H₆O is 0.675 M
Q3)
Mass of KI in solution - 12.87 x 10⁻³ g
molar mass - 166 g/mol
number of mole of KI = mass present / molar mass of KI
number of KI moles = 12.87 x 10⁻³ g / 166 g/mol = 0.0775 x 10⁻³ mol
volume of solution - 112.4 mL
number of moles of KI in 112.4 mL - 0.0775 x 10⁻³ mol
therefore number of moles in 1000 mL- 0.0775 x 10⁻³ mol / 112.4 mL x 1000 mL
molarity of KI - 6.90 x 10⁻⁴ M
1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!
2) Mass fraction of this is excessive data.
3) The solution is:
m(Ca)=1.2 g
m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)
m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
Answer:
37.65mL
Explanation:
Given parameters:
density of liquid Z = 0.9237g/mL
Mass of liquidZ + mass of cup = 50.7g
Mass of cup= 15.92g
Volume of liquid Z in cup=?
Solution:
Density is the mass per unit volume of a substance. It is mathematically expressed as shown below:
Density = 
To find the volume of liquid Z, we know the density of the liquid but we dont know the mass yet.
Mass of liquidZ = 50.7g - mass of cup = 50.7g - 15.92g = 34.98g
Therefore:
Volume of liquidZ = 
= 
= 37.65mL
Answer:
Explanation:
Hermione is pretty smart. She realizes that, according to Dalton's Law of Partial Pressures, each gas exerts its pressure independently of the others, as if the others weren't even there.
She shows Ron how to use the Ideal Gas Law to solve the problem.
pV = nRT
She collects the data:
V = 1.00 L; n = 0.0319 mol; T = 25.0 °C
She reminds him to convert the temperature to kelvins
T = (25.0 +273.15) K = 298.15 K
Then she shows him how to do the calculation.
Isn't she smart?
