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alexgriva [62]
2 years ago
12

Butter has a specific gravity of 0.86. What is the mass of 2.15 L of butter?

Chemistry
1 answer:
s344n2d4d5 [400]2 years ago
7 0

Answer:

The mass of butter is 1849 g.

Explanation:

Given data:

Specific gravity of butter = 0.86

Volume = 2.15 L

Mass = ?

Solution:

Specific gravity of a substance is the ratio of density of substance divided by the density of water.

Thus the density of butter is 0.86 g/mL

Formula:

Conversion from L to mL

2.15 /1000 = 2150 mL

d = m/v

0.86 g/mL = m/2150 mL

m =  1849 g

Thus the mass of butter is 1849 g.

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4. A sample of silicon contains<br> 5.23 x 1011 atoms. Write this amount<br> as a whole number.
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The answer is 523000000000
8 0
2 years ago
Draw the best lewis structure for bro4- and determine the formal charge on bromine
Svetach [21]

Answer :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. The electrons are represented by dot.

The given molecule is, perbromate ion.

Bromine has '7' valence electrons and oxygen has '6' valence electron.

Therefore, the total number of valence electrons in perbromate ion, BrO_4^- = 7 + 4(6) + 1 = 32

According to Lewis-dot structure, there are 14 number of bonding electrons and 18 number of non-bonding electrons.

Formula for formal charge :

\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}

\text{Formal charge on }Br=7-0-\frac{14}{2}=0

The Lewis-dot structure of perbromate ion is shown below.

7 0
2 years ago
Read 2 more answers
In a titration experiment, H2O2(aq) reacts with aqueous MnO4-(aq) as represented by the equation above. The dark purple KMnO4 so
pickupchik [31]

Answer:

C. 4x10⁻⁴ mol / (Ls)

Explanation:

Based in the reaction:

5 H₂O₂(aq) + 2 MnO₄⁻(aq) + 6 H⁺(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 O₂(g)

2 moles of MnO₄⁻ disappears while 5 moles of O₂ appears.

If 5 moles appears in a rate of 1.0x10⁻³mol /(Ls), 2 moles will disappear:

2 moles ₓ (1.0x10⁻³mol /(Ls) / 5 moles) = <em>4x10⁻⁴ mol / (Ls)</em>

Right answer is:

C. 4x10⁻⁴ mol / (Ls)

8 0
2 years ago
According to the reaction below, how many moles of Ba3(PO4)2(s) can be produced from 115 mL of 0.218 M BaCl2(aq)? Assume that th
Anna71 [15]

Answer:

0.01125 moles of Ba_3(PO_4)_2(s) can be produced from 115 mL of 0.218 M BaCl_2(aq).

Explanation:

Moles of BaCl_2 = n

Volume of the solution = 115 mL = 0.115 L ( 1 mL=0.001 L)

Molarity of the BaCl_2 solution = 0.218 M

0.218 M=\frac{n}{0.115 L}

n = 0.218\times 0.115 L=0.03379 mol

3 BaCl_2(aq) + 2Na_3PO_4(aq)\rightarrow Ba_3(PO_4)_2(s) + 6NaCl(aq)

According to reaction, 3 moles BaCl_2 gives 1 mole of Ba_3(PO_4)_2 .Then 0.03379 moles of BaCl_2 will give :

0.03379 mol\times \frac{1}{3}=0.01126 mol

0.01125 moles of Ba_3(PO_4)_2(s) can be produced from 115 mL of 0.218 M BaCl_2(aq).

3 0
2 years ago
Read 2 more answers
Diana raises a 1000. N piano a distance of 5.00 m using a set of pulleys. She pulls
Alina [70]

Answer:

a) 250 N

b) 50 N

c) 5000 J

d) 4

e) 3.33

Explanation:

Given that weight of piano (F_r) = 1000 N, distance moved by pulley (d_r) = 5 m and the rope used (d_e) =20 m

a) The effort applied (F_e) if it was an ideal machine is:

F_e=\frac{F_rd_r}{d_e} = \frac{1000*5}{20}=250N

b) If the actual effort  = 300 N

The force to overcome friction = actual effort - F_e = 300 - 250 = 50 N

c) Work output = F_rd_r=1000*5=5000J

d) ideal mechanical  advantage (IMA) = \frac{d_e}{d_r} =\frac{20}{5} = 4

e) Input force = 300 N, Therefore:

actual mechanical advantage = F_r / input force = 1000 / 300 = 3.33

5 0
2 years ago
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