Question

On a cool morning (12"C), a balloon is filled with 1.5 L of helium. By mid afternoon, the temperature has soared to 32°C. What is the new volume of the balloon? Selected Answer:

Answer 1

Answer:

1.6 L

Explanation:

Using Charle's law  

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,  

V₁ = 1.5 L

V₂ = ?

T₁ = 12 °C

T₂ = 32 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (12 + 273.15) K = 285.15 K  

T₂ = (32 + 273.15) K = 305.15 K  

Using above equation as:

$\frac{1.5}{285.15}=\frac{V_2}{305.15}$

$V_2=\frac{1.5\cdot \:305.15}{285.15}$

New volume = 1.6 L