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slavikrds [6]
2 years ago
14

On a cool morning (12"C), a balloon is filled with 1.5 L of helium. By mid afternoon, the temperature has soared to 32°C. What i

s the new volume of the balloon? Selected Answer:
Chemistry
1 answer:
ddd [48]2 years ago
8 0

Answer:

1.6 L

Explanation:

Using Charle's law  

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = 1.5 L

V₂ = ?

T₁ = 12 °C

T₂ = 32 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (12 + 273.15) K = 285.15 K  

T₂ = (32 + 273.15) K = 305.15 K  

Using above equation as:

\frac{1.5}{285.15}=\frac{V_2}{305.15}

V_2=\frac{1.5\cdot \:305.15}{285.15}

New volume = 1.6 L

You might be interested in
Which graphic below shows the correct orientation of each water molecule when it is near the cl- ion in the aqueous solution?
andrew-mc [135]
The question is missing the graphics required to answer which I have attached as an image.

There are four different representations of the orientation of water molecules around chloride anion. Let's first analyze the water molecule.

We have H-O-H as the structure of water. The oxygen atom is more electronegative than the hydrogen atoms, which results in a partial positive charge on the hydrogen atoms and a partial negative charge on the oxygen atom.

The chloride anion is a negative charge. Therefore, the water molecules should orient themselves with the hydrogen atoms facing the chlorine atom as the partial positive charge on the hydrogen atoms will be attracted to the negative charge of the chlorine atom.

The correct representation is shown in graph 3 which shows all hydrogen atoms facing the chlorine anion.

8 0
2 years ago
6. Under standard-state conditions, what spontaneous reaction will occur in aqueous solution among the ions Ce4+, Ce3+, Fe3+, an
xz_007 [3.2K]

Answer:

ΔG° = -80.9 KJ

Assuming this reaction takes place at room temperature (25 °C):

K=1.53x10^{14}

Explanation:

1) Reduction potentials

First of all one should look up the reduction potentials for the species envolved:

Ce^{4+} + e→Ce^{3+}         E°red=1.61V

Fe^{3+} + e→Fe^{2+}         E°red=0.771V

2) Redox pair

Knowing their reduction pontentials one can determine a redox pair: one species must oxidate while the other is reducing. <u>Remember: the table gives us the reduction potential, so if we want to know the oxidation potential all that has to be done is reverce the equation and change the potencial signal (multiply to -1).</u>

1)  Ce^{4+} reduces while  Fe^{2+} oxidates

  (oxidation)               Fe^{2+}→Fe^{3+} + e          E°oxi=-0.771V

  (reduction)               Ce^{4+} + e→Ce^{3+}         E°red=1.61V

  (overall equation)    Fe^{2+}+Ce^{4+}→Ce^{3+}+Fe^{3+} E°=Ereduction + Eoxidation= 1.61 v+(-0.771 v) = 0.839v

The cell potential can also be calculated as the cathode potencial minus the anode potential:

E° = E cathode - E anode =1.61 v - 0.771 v=0.839 v

3) Gibbs free energy and Equilibrium constant

ΔG°=-nFE°, where 'n' is the number of electrons involved in the redox equation, in this case n is 1. 'F' is the Faraday constant, whtch is 96500 C. E° is the standard cell potencial.

ΔG°=-nFE°=-1*96500*0.839

ΔG° = - 80963 J = -80.9 KJ

The Nerst equation gives us the relation of chemical equilibrium and Electric potential.

E=E°-\frac{RT}{nF} Ln Q

Where 'R' is the molar gas constant (8.314 J/mol)

It's known that in the equilibrium E=0, so the Nerst equation, at equilibrium, becomes:

E°=\frac{RT}{nF} Ln K

Isolating for 'K' gives:

K=e^{\frac{nFE^{o} }{RT} }

This shows that 'K' is a fuction of temperature. Assuming this reaction takes place at room temperature (25 °C):

K=1.53x10^{14}

6 0
2 years ago
the half life of the radioactive element strontium-90 is 29.1 years. If 16 grams of strontium-90 are initially present, how many
8_murik_8 [283]

Answer:

4 g after 58.2 years

0.0156 After 291 years

Explanation:

Given data:

Half-life of strontium-90 = 29.1 years

Initially present: 16g

mass present after 58.2 years =?

Mass present after 291 years =?

Solution:

Formula:

how much mass remains =1/ 2n (original mass) ……… (1)

Where “n” is the number of half lives

to find n

For 58.2 years

n = 58.2 years /29.1 years

n= 2

or  291 years

n = 291 years /29.1 years

n= 10

Put values in equation (1)

Mass after 58.2 years

mass remains =1/ 22 (16g)

mass remains =1/ 4 (16g)

 mass remains = 4g

Mass after 58.2 years

mass remains =1/ 210 (16g)

mass remains =1/ 1024 (16g)

mass remains = 0.0156g

8 0
2 years ago
Read 2 more answers
Which traits does the common garter snake have that might be adaptive for the environment where it lives?
Licemer1 [7]

Answer:

As the garter snake can be found almost in any kind of habitat, what makes them be able to survive in any environment include:

1. They hibernate to increase their chances of survival in unfavorable weather conditions.

2. They can blend with the background of any environment especially grass to escape being eaten.

3. They produce an odor that is usually unpleasant especially when about to be attacked.

Explanation:

The garter snakes are distinguished by the three stripes running the length of their body and can often be found in forests, places that are even close to water bodies, and almost any place, even in holes.

 

           

4 0
1 year ago
Imagine that a chemist is trying to establish whether a piece of rock is from a meteorite that fell from outer space. the rock c
rusak2 [61]
The sample is likely to be from a meteorite.

The reason for this is the fact that the isotope Copper-63 is more abundant on planet Earth than the isotope Copper-65 is. Therefore, if a sample of rock has Cu-65 in a greater quantity, it is likely to be from outer space. Many other elements entered the Earth's crust as a result of meteorite impacts, such as Iron (Fe).
8 0
2 years ago
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