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slavikrds [6]
2 years ago
14

On a cool morning (12"C), a balloon is filled with 1.5 L of helium. By mid afternoon, the temperature has soared to 32°C. What i

s the new volume of the balloon? Selected Answer:
Chemistry
1 answer:
ddd [48]2 years ago
8 0

Answer:

1.6 L

Explanation:

Using Charle's law  

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = 1.5 L

V₂ = ?

T₁ = 12 °C

T₂ = 32 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (12 + 273.15) K = 285.15 K  

T₂ = (32 + 273.15) K = 305.15 K  

Using above equation as:

\frac{1.5}{285.15}=\frac{V_2}{305.15}

V_2=\frac{1.5\cdot \:305.15}{285.15}

New volume = 1.6 L

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Answer:

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2 years ago
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For the reaction PCl5(g) <--> PCl3(g) Cl2(g) at equilibrium, which statement correctly describes the effects of increasing
xenn [34]

The given question is incomplete. The complete question is :

For the reaction PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g) at equilibrium, which statement correctly describes the effects of increasing pressure and adding PCl_5, respectively

a) Increasing pressure causes shift to reactants, adding PCl_5 causes shift to products.

b) Increasing pressure causes shift to products ,adding PCl_5 causes shift to reactants.

c) Increasing pressure causes shift to products, adding PCl_5 causes shift to products.

d) Increasing pressure causes shift to reactants,adding PCl_5 causes shift to reactants

Answer: Increasing pressure causes shift to reactants, adding PCl_5 causes shift to products.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)

a)  If the pressure is increased, the volume will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. As the number of moles of gas molecules is lesser at the reactant side. So, the equilibrium will shift in the left direction. i.e. towards reactants.

b) If PCl_5 is added, the equilibrium will shift in the direction where PCl_5 is decreasing. So, the equilibrium will shift in the right direction. i.e. towards products.

8 0
2 years ago
The incomplete table below shows selected characteristics of gas laws.
Elenna [48]

Explanation :

In the given case different law related to gas is given. The attached figure shows the required solution.

Boyle's law states that the pressure is inversely proportional to the volume of the gas i.e.

P\propto \dfrac{1}{V}

PV=k

k is a constant.

Charle's law states that the volume of directly proportional to the temperature of the gas.

V\propto T

V=kT

Combined gas law is the combination of the pressure, volume and the temperature of the gas i.e.

\dfrac{PV}{T}=k

Hence, this is the required solution.

6 0
2 years ago
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g When 2.50 g of methane (CH4) burns in oxygen, 125 kJ of heat is produced. What is the enthalpy of combustion (in kJ) per mole
Anna [14]

Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

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Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

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Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

3 0
2 years ago
What reaction is depicted by the given equation: Au3+ + 3e− Au
mr Goodwill [35]
Reduction. B is the correct answer
3 0
2 years ago
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