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chubhunter [2.5K]
2 years ago
14

Suppose that 2.5 mmol n2 (g) occupies 42 cm3 at 300 k and expands isothermally to 600 cm3. calculate δgm in kj/mol for the proc

ess. hint: boyle's law p1v1=p2v2
Chemistry
1 answer:
andriy [413]2 years ago
8 0

<u>Given:</u>

MilliMoles of N2 = 2.5 mmol = 0.0025 moles

Initial volume V1 = 42 cm3

Final volume V2 = 600 cm3

Temperature T = 300 K

<u>To determine:</u>

The change in Gibbs free energy, ΔG

<u>Explanation:</u>

The change in Gibbs free energy is related to the ration of the volumes:

ΔG = -nRTln(V2)/(V1)

      = -0.0025*8.314*300*ln(600/42) = -16.582 J/mol

Ans: The Gibbs free energy for the process is 0.0166 kJ/mol

     


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If 25 g of NH3, and 96 g of H2S react according to the following reaction, what is the
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