Answer:
1.3 L.
Explanation:
- Molarity is the no. of moles of solute per 1.0 L of the solution.
<em>M = (no. of moles of CaSO₄)/(Volume of the solution (L))</em>
<em></em>
M = 0.352 M.
no. of moles of CaSO₄ = mass/molar mass = (62.1 g / 136.14 g/mol) = 0.456 mol,
Volume of the solution = ??? L.
∴ (0.352 M) = (0.456 mol)/(Volume of the solution (L))
<em>∴ (Volume of the solution (L) </em>= (0.456 mol)/(0.352 M) = <em>1.296 L ≅ 1.3 L.</em>
Answer:

Explanation:
We are asked to find the specific heat capacity of a sample of lead. The formula for calculating the specific heat capacity is:

The heat absorbed (Q) is 237 Joules. The mass of the lead sample (m) is 22.7 grams. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature. The temperature increases <em>from</em> 29.8 °C <em>to </em>95.6 °C.
- ΔT = final temperature -inital temperature
- ΔT= 95.6 °C - 29.8 °C = 65.8 °C
Now we know all three variables and can substitute them into the formula.
- Q= 237 J
- m= 22.7 g
- ΔT = 65.8 °C

Solve the denominator.
- 22.7 g * 65.8 °C = 1493.66 g °C

Divide.

The original values of heat, temperature, and mass all have 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place tells us to round the 8 up to a 9.

The specific heat capacity of lead is approximately <u>0.159 Joules per gram degree Celsius.</u>
According to Arrhenius theory, acid is a substance that releases H⁺ ions when dissolved in water.
In order to apply this theory, the substance must be soluble in water.
H₂SO₄ is highly soluble in water. It undergoes following dissociation reaction when dissolved in water.

From the above equation, we can see that H₂SO₄ forms 2 H⁺ ions when dissolved in water. Therefore it behaves as an acid according to Arrhenius theory.
Thermal energy will flow from an object high temperature to an object of low one. In this case, the thermal energy will flow from object B to object A.