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emmasim [6.3K]
2 years ago
10

If the temperature of an ideal gas is raised from 100◦C to 200◦C, while the pressure remains constant, the volume 1. increases b

y a factor of 100. 2. None of these 3. doubles. 4. remains the same. 5. goes to 1 2 of the original volume.
Chemistry
1 answer:
mel-nik [20]2 years ago
3 0

Answer:

3. doubles

Explanation:

for an ideal gas behavior, the relationship between volume and temperature is given by Charles law

Charles law states that the volume of a given mass of gas is directly proportional to its temperature provided that pressure remains constant. Mathematically, this is represented as

V ∝ T

V=KT

K = V/T

where V is the volume of the gas

T is the Temperature

k represents the constant of proportionality

For initial and final conditions of a gas,

\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

where 1 and 2 represent initial and final conditions respectively

therefore, T₁ = 100 and T₂ = 200

\frac{V_{1} }{100} = \frac{V_{2} }{200}

200 × V₁ = 100 × V₂

divide both sides by 100

2V₁ = V₂

final volume,V₂ = 2V₁

there the volume doubles

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Calculate the mass, in grams, of 2.74 l of co gas measured at 33°c and 945 mmhg.
nalin [4]
<span>T = 33 + 273 =306 K moles CO = pV/RT = 1.24 x 2.74 / 0.08206 x 306=0.135 mass CO = 0.135 mol x 28.01 g/mol=3.78 g</span>
4 0
2 years ago
2) Of the following, which has the shortest de Broglie wavelength? A) an airplane moving at a velocity of 300 mph B) a helium nu
8090 [49]

Answer:

B) a helium nucleus moving at a velocity of 1000 mph

Explanation:

According to the De Broglie relation

λ= h/mv

h= planks constant

m= mass of the body

v= velocity of the body.

As we can see from De Broglie's relation, the wavelength of matter waves depends on its mass and velocity. Hence, a very small mass moving at a very high velocity will have the greatest De Broglie wavelength.

Of all the options given, helium is the smallest matter. A velocity of 1000mph is quite high hence it will have the greatest De Broglie wavelength.

5 0
2 years ago
f 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric a
Eduardwww [97]

Answer:

Explanation:

H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)

mole of NaOH = 23.6 * 10 ⁻³L * 0.2M

= 0.00472mole

let x be the no of mole of H3PO4 required of  0.00472mole of NaOH

3 mole of NaOH required ------- 1 mole of H3PO4

0.00472mole of NaOH ----------x

cross multiply

3x = 0.0472

x = 0.00157mole

[H3PO4] = mole of H3PO4 / Vol. of H3PO4

= 0.00157mole / (10*10⁻³l)

= 0.157M

<h3>The concentration of unknown phosphoric acid is  0.157M</h3>
7 0
1 year ago
Read 2 more answers
The flame produced by the burner of a gas (propane) grill is a pale blue color when enough air mixes with the propane (C3H8) to
adelina 88 [10]

Answer:

At the burner temp. and pressure, 18.85 litres of air is needed to completely combust each gram of propane

Explanation:

The combustion stoichiometry is as follows:

      C₃H₈ + 5O₂  = 4 H₂O + 3CO₂      The molecular weights (g/mol) are:

MW  44    5x32      4x18    3x44

So each gram of propane is 1/44 = 0.02272 mol propane

and will need 5 x 0.02272 = 0.1136 mol oxygen

At 0.21 mol fraction oxygen in air, 0.1136 / 0.21 = 0.54 mol air is needed to burn the propane.

At the low pressure in the burner we can use the Ideal Gas Law

PV=nRT, or V = nRT/P

P = 1.1 x 101325 Pa = 111457 Pa

T = 195°C + 273 = 468 K

R = 8.314

and we calculated n = number of moles air = 0.54 mol

So V m³ = 0.54 x 8.314 x 468 / 111457 = 0.0188 m³ = 18.85 litres air.

6 0
2 years ago
A 2.550 x 10^−2 M solution of glycerol (C3H8O3) in water is at 20.0°C. The sample was created by dissolving a sample of C3H8O3 i
BARSIC [14]

Answer:

2.557\times 10^{-2}\ molal.

Explanation:

Given , molarity of glycerol= 2.55\times 10^-^2\ M.

Volume= 1 L.

Therefore, No of moles of glycerol= molarity\times volume\ in\ liters=2.55\times 10^-^2\ moles.

Now, volume of water needed, V=998.8 mL.

Density is given as= 0.9982 g/mL.

Therefore, mass of water = volume\times density=998.8\times 0.9982=997\ g=0.997\ kg

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Hence, this is the required solution.

3 0
1 year ago
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