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emmasim [6.3K]
2 years ago
10

If the temperature of an ideal gas is raised from 100◦C to 200◦C, while the pressure remains constant, the volume 1. increases b

y a factor of 100. 2. None of these 3. doubles. 4. remains the same. 5. goes to 1 2 of the original volume.
Chemistry
1 answer:
mel-nik [20]2 years ago
3 0

Answer:

3. doubles

Explanation:

for an ideal gas behavior, the relationship between volume and temperature is given by Charles law

Charles law states that the volume of a given mass of gas is directly proportional to its temperature provided that pressure remains constant. Mathematically, this is represented as

V ∝ T

V=KT

K = V/T

where V is the volume of the gas

T is the Temperature

k represents the constant of proportionality

For initial and final conditions of a gas,

\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }

where 1 and 2 represent initial and final conditions respectively

therefore, T₁ = 100 and T₂ = 200

\frac{V_{1} }{100} = \frac{V_{2} }{200}

200 × V₁ = 100 × V₂

divide both sides by 100

2V₁ = V₂

final volume,V₂ = 2V₁

there the volume doubles

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Answer:

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Explanation:

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Thus, given the temperature change and the total heat capacity, we obtain the following total heat of reaction:

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Now, by dividing by the moles in 1.04 g of cyclopropane (42.09 g/mol) we obtain the enthalpy of combustion of this fuel:

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4 0
1 year ago
When a known quantity of compound, at a known concentration, is added to a known volume of another compound to determine the con
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A titration

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A student carries out the precipitation reaction shown below, starting with 0.030 moles of calcium nitrate. The final mass of th
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Answer:

a. Ca₃(PO₄)₂.

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d. Percent yield = 93.5%

Explanation:

a. Based on the reaction:

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<em>3 moles of calcium nitrate reacts with 2 moles of sodium phosphate producieng 1 mole of calcium phosphate.</em>

<em />

As you can see, Ca₃(PO₄)₂ is a solid product -(s)-, that means when the reaction occurs the precipitate produced is the solid,

<h3>Ca₃(PO₄)₂</h3><h3 />

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0.030 moles Ca(NO₃)₂ × (1 mol Ca₃(PO₄)₂ / 3 moles Ca(NO₃)₂) =

<h3>0.010 moles of Ca₃(PO₄)₂ can we expect to be produced</h3><h3 />

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\frac{2.9g}{3.1g} *100

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7 0
2 years ago
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Answer:

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