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Dmitriy789 [7]
2 years ago
12

Give the coordination number, the charge of the central metal ion, and select the correct name in each coordination compound: A.

Na3[CoCl6] coordination number charge of the central metal ion name B. [Ni(CO)4] coordination number charge of the central metal ion name C. [Ni(NH3)3(H2O)3] (NO3)2 coordination number charge of the central metal ion name
Chemistry
1 answer:
Komok [63]2 years ago
4 0

The correct question is

Give the coordination number, the charge of the central metal ion, and select the correct name in each coordination compound:

Na3[CoCl6]

[Ni(CO)4]

[Ni(NH3)3(H2O)2] (NO3)2

Answer:

See explanation for details

Explanation:

Na3[CoCl6]

Name: Sodium hexacholorocobalt III

Charge on the complex: -3

Central metal ion name : cobalt III

coordination number: 6

[Ni(CO)4]

Name: tetracarbonyl nickel (0)

Charge on the complex: 0

Central metal ion name : nickel (0)

coordination number: 4

[Ni(NH3)3(H2O)2] (NO3)2

Name: Diaquatriaminenickel II nitrate

Charge on the complex: +2

Central metal ion name : nickel (+2)

coordination number: 5

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How many liters of radon gas would be in 3.43 moles at room temperature and pressure (293 K and 100 kPa)?
OLga [1]

Using ideal gas equation,

P\times V=n\times R\times T

Here,

P denotes pressure

V denotes volume

n denotes number of moles of gas

R denotes gas constant

T denotes temperature

The values at STP will be:

P=100 kPa

T=293 K

R=8.314472 L kPa K⁻¹ mol⁻¹

Number of moles of gas=3.43 mole

Putting all the values in the above equation,

V=\frac{3.43\times 8.314\times 293}{100}

V=83.55 L

So the volume will be 83.55 L.

83.55 L of radon gas would be in 3.43 moles at room temperature and pressure (293 K and 100 kPa).

4 0
2 years ago
If 25.0 g of NH₃ and 45.0g of O₂ react in the following reaction, what is the mass in grams of NO that will be formed? 4 NH₃ (g)
Allisa [31]

Answer:

The correct answer would be : 33.8 g

Explanation:

Molar mass of ammonia,

Molar Mass = 1* Molar Mass(N) + 3* Molar Mass (H)

= 1*14.01 + 3*1.008  = 17.034 g/mol

mass(NH3)= 25.0 g  (given)

number of mol of NH3,

n = mass of NH3/molar mass of NH3

=(25.0 g)/(17.034 g/mol)

= 1.468 mol

Now,

Molar mass of O2

= 32 g/mol

mass(O2)= 45.0 g

similar as ammonia

n (O2)=(45.0 g)/(32 g/mol)

= 1.406 mol

Balanced chemical equation is:

4 NH3 + 5 O2 ---> 4 NO + 6 H2O

1.83456 mol of O2 is required  for 1.46765 mol of NH3

by the calculation we have only 1.40625 mol of O2

Thus, the limiting agent will be - O2

now the Molar mass of NO,

= 1*14.01 + 1*16.0

= 30.01 g/mol  (similar formula used for NH3)

Balanced equation :

mol of NO formed = (4/5)* moles of O2

= (4/5)×1.40625  (from above calculation)

= 1.125 mol

mass of NO = number of moles × molar mass

= 1.125*30.01

= 33.8 g

Thus, the correct answer would be : 33.8 g

5 0
2 years ago
Quinine, an antimalarial drug, is 8.63% nitrogen. There are two nitrogen atoms per molecule. What is the molecular weight of qui
Furkat [3]

Answer:

324.18 g/mol

Explanation:

Let the molecular mass of the antimalarial drug, Quinine is x g/mol

According to question,

Nitrogen present in the drug is 8.63% of x

So, mass of nitrogen = \frac {8.63}{100}\times x

Also, according to the question,

2 atoms are present in 1 molecule of the drug.

Mass of nitrogen = 14.01 amu = 14.01 g/mol (grams for 1 mole)

So, mass of nitrogen = 14.01×2 = 28.02

These 2 must be equal so,

\frac {8.63}{100}\times x=28.02

solving for x, we get:

<u>x = 324.18 g/mol</u>

6 0
2 years ago
Calculate the mass percent of Cl in Freon -112 (C2 Cl4 F2), a CFC refrigerant
Karolina [17]

Answer:

The answer to your question is:  69.6 %

Explanation:

Freon -112 (C₂Cl₄F₂)

MW = (12 x 2) + (35.5 x 4) + (19 x 2)

      = 24 + 142 + 38

      = 204 g

                       204 g of C₂Cl₄F₂  -----------------  100%

                       142 g                     -----------------   x

                      x = (142 x 100 ) / 204

                      x = 69.6 %

5 0
2 years ago
Read 2 more answers
The specific heat of aluminum is 0.214 cal/g.oC. Determine the energy, in calories, necessary to raise the temperature of a 55.5
Natasha2012 [34]
For this problem, we use the formula for sensible heat which is written below:

Q= mCpΔT
where Q is the energy
Cp is the specific heat capacity
ΔT is the temperature difference

Q = (55.5 g)(<span>0.214 cal/g</span>·°C)(48.6°C- 23°C)
<em>Q = 304.05 cal</em>
4 0
2 years ago
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