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Flauer [41]
2 years ago
7

A flask containing helium gas is connected to an open-ended mercury manometer. The open end is exposed to the atmosphere, where

the prevailing pressure is 752 torr. The mercury level in the open arm is 26 mm above that in the arm connected to the flask of helium.What is the helium pressure, in torr?
Chemistry
1 answer:
stepladder [879]2 years ago
8 0

Answer:

726 torr

Explanation:

Generally, atmospheric pressure can be measured using a manometer which is in form of a U-shaped tube. In addition, 1 mm Hg is equivalent to 1 torr. Therefore, 752 torr is equivalent to 752 mm Hg. Therefore, the total pressure will be equivalent to the atmospheric pressure (mm Hg) + the mercury height.

In this case, the mercury height = -26 mm

Thus:

The helium pressure = 752 - 26 = 726 mm Hg

This is also equivalent to 726 torr

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DanielleElmas [232]

Answer:

25.99mL is the volume internal volume of the flask

Explanation:

<em>To complete the question:</em>

<em>The temperature of the water was measured to be 21ºC. Use this data to find the internal volume of the stoppered flask</em>

<em />

The flask was filled with water, that means the internal volume of the flask is equal to the volume that the water occupies.

To find the volume of the water you need to find the mass and by the use of density of water at 21ºC (0.997992g/mL), you can find the volume of the flask, thus:

Mass water = Mass filled flask - Mass of clean flask

Mass water = 60.167g - 34.232g

Mass water = 25.935g of water.

To convert this mass to volume:

25.935g × (1mL / 0.997992g) =

<h3>25.99mL is the volume internal volume of the flask</h3>
3 0
2 years ago
What is the density ρh of hot air inside the balloon? assume that this density is uniform throughout the balloon. express the de
enyata [817]

Answer 1) : The density of the hot air inside the balloon can be found out by using ideal gas equation;


PV = nRT;


As n is number of moles and in gases, number of moles along with mass per mole is equal to the density of the gas.


If the moles in the gas are more the density will be more.


here, density (ρ) = mass (m) / volume (V); substituting in the ideal gas equation we get,

ρ = mP / RT


Answer 2) ρ (hot air) = ρ (cold air) X \frac{T_{h}}{T_{c}}

Here according to the formula because T(hot air) >T(cold air),


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The relationship between the ρ (h) = ρ(c) X \frac{T_{h}}{T_{c}}

6 0
2 years ago
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Limes have a [H3O+] of 1.3 x 10-2 mol/L. Their pOH is​
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To determine the pOH assuming water is the universal solvent take the value of 10 ^ -14 and then divide it by the hydronium concentration and then take the negative logarithm of the final answer that is the solution to the hydroxide ion concentration in the solution.
4 0
2 years ago
Calculate the internal energy of 2 moles of argon gas (assuming ideal behavior) at 298 K. Suggest two ways to increase its inter
Dominik [7]
I hope this helps you.

5 0
2 years ago
Uranium–232 has a half–life of 68.9 years. A sample from 206.7 years ago contains 1.40 g of uranium–232. How much uranium was or
givi [52]

<u>Answer:</u> The initial amount of Uranium-232 present is 11.3 grams.

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

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We are given:

t_{1/2}=68.9yrs

Putting values in above equation, we get:

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Rate law expression for first order kinetics is given by the equation:

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where,

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[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process = 1.40 g

Putting values in above equation, we get:

0.0101yr^{-1}=\frac{2.303}{206.7yrs}\log\frac{[A_o]}{1.40}

[A_o]=11.3g

Hence, the initial amount of Uranium-232 present is 11.3 grams.

4 0
2 years ago
Read 2 more answers
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