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Nataly_w [17]
1 year ago
15

Cherylanne mixes together Chemical A and Chemical B in a test tube, forming Chemical C. The mixture instantly turns cool to the

touch. She then adds Chemical D, and the reaction becomes hot and explodes. What can be known about this situation? Chemicals A and B form an endothermic reaction, and chemicals C and D form an exothermic reaction. Chemicals A and B form an exothermic reaction, and chemicals C and D form an endothermic reaction. Chemicals A and C form an endothermic reaction, and chemicals B and D form an exothermic reaction. Chemicals A and B form an exothermic reaction, and chemicals B and D form an endothermic reaction.
Chemistry
2 answers:
Anarel [89]1 year ago
7 0

Answer:

Chemicals A and B form an endothermic reaction, and chemicals C and D form an exothermic reaction.

Explanation:

The reaction that produced chemical C is an endothermic reaction whereas, the reaction between C and D is an exothermic one.

An exothermic change is one in which heat is liberated to the surroundings. So the surrounding becomes hotter at the end of the reaction.

An endothermic reaction is a change in which heat is absorbed from the surrounding and hence the surrounding colder at the end of the change.

  • We can see that the first reaction is endothermic.
  • The second reaction is exothermic.
asambeis [7]1 year ago
7 0

Answer:

<h2><em><u>A or 1</u></em></h2>

Explanation:

<h3><u>Chemicals A and B form an endothermic reaction, and chemicals C and D form an exothermic reaction.</u></h3>

<h3><u>the rest are wrong</u></h3>

<u />

Chemicals A and B form an exothermic reaction, and chemicals C and D form an endothermic reaction.

Chemicals A and C form an endothermic reaction, and chemicals B and D form an exothermic reaction.

Chemicals A and B form an exothermic reaction, and chemicals B and D form an endothermic reaction.

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The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is ________. the density of the sol
Thepotemich [5.8K]
The answer:
all that we search for is the number of mole of HCl and the number of mole of C2H6O

M(HCl) = 5.5g/ mole of HCl , so mole of HCl = 5.5/M(HCl), where M(HCl) is the molar mass.
M(HCl) = 1+ 36.5= 37.5 

moles of HCl = 5.5/37.5=0.14 

M(C2H6O) = 200g / moles of C2H6O, so moles of C2H6O=200g / M(C2H6O)

M(C2H6O)= 2x12+ 6 + 16=46,

moles of C2H6O=200g / 46 =<span>4.35 </span><span> moles 
</span>
the sum of the moles is    0.14 + <span>4.35 </span> = 4.501 moles

finally,  <span>The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is 0.031
</span>
because it can be found by  0.14 / 4.501= 0.031

5 0
2 years ago
If 1.50 μg of CO and 6.80 μg of H2 were added to a reaction vessel, and the reaction went to completion, how many gas particles
iogann1982 [59]
The chemical reaction would be as follows:

CO + 2H2 =CH3OH

We are given the amount of reactants to be used. We have to use these amounts to determine which is the limiting reactant and how much of the excess reactant is left.

1.50x10^-6 g CO ( 1 mol / 28.01 g ) = 5.36x10^-8 mol CO
6.80 x10^-6 g H2 ( 1 mol / 2.02 g ) = 3.37x10^-6 mol H2

Therefore, it is CO that is consumed completely in the reaction and the number of moles gas left would be 3.37x10^-6 - 5.36x10^-8 = 3.32x10^-6 moles.

5 0
2 years ago
Which of the following statements concerning a metal crystallized in a face-centered cubic cell is/are CORRECT? 1. One metal ato
AleksAgata [21]

Answer:

Only 3 is correct.

Explanation:

The crystal of a metal or an ionic compound is called a cell, and there are 7 types of unit cells: cubic, tetragonal, orthorhombic, monoclinic, hexagonal, rhombohedral, and triclinic.

In a face-centered cubic cell (FCC) all angles are 90º and all lengths are equal. Each cubic cell has 8 atoms in each corner of the cube, and that atom is shared with 8 neighboring cells. So for a metal crystal, the atom is located at each of the eight lattice points, where it is shared equally between eight unit cells.

5 0
2 years ago
What mass of oxygen reacts when 84.9 g of iron is consumed in the following reaction: Fe+O2= Fe2O3
konstantin123 [22]
First we will calculate the number of moles of Iron:
n =  \frac{m}{M}&#10;, where n is the number of moles, m is the mass of iron in the reaction and M is the Atomic weight.
n= \frac{84.9}{55.845} = 1,52 moles of Iron.
The same number of moles of Oxygen will take part in the reaction.
So 1,52= \frac{mOxygen}{32} where 32 is the Atomical Weight of Oxygen (16 x 2).
=>mOxygen=32*1,52=48,64g
6 0
1 year ago
Read 2 more answers
The French chemists, Pierre L. Dulong and Alexis T. Petit, noted in 1819 that the molar heat capacity of many solids at ordinary
natita [175]

The empirical formula of the compound : <u><em>RbO₂</em></u>

<h3>Further explanation</h3>

Dulong and Petit's rule's rule, which says that the molar heat capacity, Cp, of a solid can be expressed as

\large{\boxed{\bold{Cp=N(3R)}}

Where N is the number of atoms per formula unit and R is the universal gas constant

While the value of R is:

R = 8.3144621 J / K · mol

then:

3R = 24.94 J / K · mol

Heat capactiy per gram of a compound containing rubidium and oxygen is 0.64 J · K⁻¹ · g⁻¹

We try the possible empirical formula from the composition of Rb and O

  • Rb₂O

So the number of atoms: 3 (Rb = 2 atoms, O = 1 atom)

Then the value of the Cp:

Molar mass Rb₂O = 2.85.5 + 1.16 = 187 g/mol

\displaystyle Cp=N(3R)\\\\0.64=\frac{3.24.94}{187}\\\\0.64\neq0.4

Then this empirical formula Rb₂O  is not appropriate

  • RbO₂

So the number of atoms: 3 (Rb = 1 atom, O = 2 atoms)

Then the value of the Cp:

Molar mass RbO₂ = 1.85.5 + 2.16 = 117.5 g / mol

\displaystyle Cp=N(3R)\\\\0.64=\frac{3.24.94}{117.5}\\\\0.64=0.64

Then this empirical formula RbO₂  is appropriate

<h3>Learn more </h3>

chemical bond

brainly.com/question/5008811

ionic bonding

brainly.com/question/1603987

electron dots

brainly.com/question/6085185

 

Keywords:  an empirical formula,compound, gas constant, Dulong and Petit's rule,the molar heat capacity

#LearnWithBrainly

7 0
2 years ago
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