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Nataly_w [17]
2 years ago
15

Cherylanne mixes together Chemical A and Chemical B in a test tube, forming Chemical C. The mixture instantly turns cool to the

touch. She then adds Chemical D, and the reaction becomes hot and explodes. What can be known about this situation? Chemicals A and B form an endothermic reaction, and chemicals C and D form an exothermic reaction. Chemicals A and B form an exothermic reaction, and chemicals C and D form an endothermic reaction. Chemicals A and C form an endothermic reaction, and chemicals B and D form an exothermic reaction. Chemicals A and B form an exothermic reaction, and chemicals B and D form an endothermic reaction.
Chemistry
2 answers:
Anarel [89]2 years ago
7 0

Answer:

Chemicals A and B form an endothermic reaction, and chemicals C and D form an exothermic reaction.

Explanation:

The reaction that produced chemical C is an endothermic reaction whereas, the reaction between C and D is an exothermic one.

An exothermic change is one in which heat is liberated to the surroundings. So the surrounding becomes hotter at the end of the reaction.

An endothermic reaction is a change in which heat is absorbed from the surrounding and hence the surrounding colder at the end of the change.

  • We can see that the first reaction is endothermic.
  • The second reaction is exothermic.
asambeis [7]2 years ago
7 0

Answer:

<h2><em><u>A or 1</u></em></h2>

Explanation:

<h3><u>Chemicals A and B form an endothermic reaction, and chemicals C and D form an exothermic reaction.</u></h3>

<h3><u>the rest are wrong</u></h3>

<u />

Chemicals A and B form an exothermic reaction, and chemicals C and D form an endothermic reaction.

Chemicals A and C form an endothermic reaction, and chemicals B and D form an exothermic reaction.

Chemicals A and B form an exothermic reaction, and chemicals B and D form an endothermic reaction.

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The solubility of N2 in blood can be a serious problem (the "bends") for divers breathing compressed air (78% N2 by volume) at d
OLga [1]

Answer:

The volume is 19.7 mL

Explanation:

<u>Step 1</u>: Given data

Pressure at sea level = 1.00 atm

Pressure at 50 ft = 2.47535 atm

kH for N2 in water at 25°C is 7.0 × 10−4 mol/L·atm

Molarity (M) = kH x P

<u>Step 2</u>: Calculate molarity

M at sea level:

M = 7.0*10^-4 * (1.00atm * 0.78) = 5.46*10^-4 mol/L

M at 50ft:

M = 7.0*10^-4 * (2.47535atm * 0.78) = 13.5*10^-4 mol/L

We should find the volume of N2. To find the volume whe have to find the number of moles first. This we calculate by calculating the difference between M at 50 ft and M at sea level.

13.5*10^-4 mol/L - 5.46*10^-4 mol/L = 8.04*10^-4 mol/L

Step 3: Calculate volume

P*V=nRT

with P = 1.00 atm

with V = TO BE DETERMINED

with n =  8.04*10^-4 mol/L  *1L = 8.04*10^-4

with R= 0.0821 atm * L/ mol *K

with T = 25 °C = 273+25 = 298 Kelvin

To find the volume, we re-organize the formula to: V=nRT/P

V= (8.04*10^-4 mol * 0.0821 (atm*L)/(mol*K)* 298K ) / 1.00atm = 0.0197L = 19.7ml

The volume is 19.7 mL

5 0
2 years ago
The volume of a gas is 27.5 mL at 22.0°C and 0.974 atm. What will the volume be at 15.0°C and 0.993 atm? Use Ideal Gas Law (PV =
Scorpion4ik [409]

Answer:

26.3 mL

Explanation:

Step 1:

Obtaining an appropriate gas law from the ideal gas equation.

This is illustrated below:

From the ideal gas equation:

PV = nRT

Divide both side by T

PV/T = nR

At this stage, we'll assume the number of mole (n) to be constant.

Note: R is the gas constant.

PV/T = constant.

We can thus, write the above equation as:

P1V1/T1 = P2V2/T2

The above equation is called the general gas equation.

Step 2:

Data obtained from the question. This includes the following:

Initial volume (V1) = 27.5 mL

Initial temperature (T1) = 22.0°C = 22.0°C + 273 = 295K

Initial pressure (P1) = 0.974 atm.

Final temperature (T2) = 15.0°C = 15.0°C + 273 = 288K

Final pressure (P2) = 0.993 atm

Final volume (V2) =..?

Step 3:

Determination of the final volume of the gas using the general gas equation obtained. This is illustrated below:

P1V1 /T1 = P2V2/T2

0.974 x 27.5/295 = 0.993 x V2/288

Cross multiply to express in linear.

295x0.993xV2 = 0.974x27.5x288

Divide both side by 295 x 0.993

V2 = (0.974x27.5x288)/(295x0.993)

V2 = 26.3 mL

Therefore, the new volume of the gas is 26.3 mL

4 0
2 years ago
Complete this equation for the dissociation of the electrolyte NaCl(aq). Omit water from the equation because it is understood t
ella [17]

1. Answer;

Equation;

-NaCl(aq) → Na{+}(aq) + Cl{-}(aq)

Explanation;

-The polar property of water allows ionic compounds such as sodium chloride to dissolve in water. (sodium chloride is an ionic compound).

-Sodium chloride dissociates in water into sodium ions and chloride ions as shown by the equation. Water molecules surrounds the negatively charged chloride ions and positive sodium ions and pulls them away into solution.

2. Answer;

Equation;

Fe(ClO4)3(aq) → Fe 3+(aq) + 3ClO4 - (aq)

Explanation;

Iron (iii) perchlorate (Fe(ClO4)3 dissociates in water into iron (iii) ion and perchlorate ion. Iron (iii) ion is positively charged while the perchlorate ion is negatively charged, they are pulled apart by the polar water molecules, a process called dissociation.

-

5 0
2 years ago
Read 2 more answers
A 0.15 m solution of chloroacetic acid has a ph of 1.86. What is the value of ka for this acid?
dem82 [27]

Answer: 1.67\times 10^{-3}

Explanation:

ClCH_2COOH\rightarrow ClCH_2COO^-+H^+

   cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Given:  c = 0.15 M

pH = 1.86

K_a = ?

Putting in the values we get:

Also pH=-log[H^+]

1.86=-log[H^+]

[H^+]=0.01

[H^+]=c\times \alpha

0.01=0.15\times \alpha

\alpha=0.06

As [H^+]=[ClCH_2COO^-]=0.01

K_a=\frac{(0.01)^2}{(0.15-0.15\times 0.06)}

K_a=1.67\times 10^{-3]

Thus the vale of K_a for the acid is 1.67\times 10^{-3}

4 0
2 years ago
Dua buah gaya masing-masing F1 = 10 N dan F2 = 5 N bekerja pada sebuah benda yang:
Stolb23 [73]

Pertanyaan ini tidak ditulis dengan benar.

Pertanyaan Lengkap:

Duah buah gaya masing masing F1=10N dan F2=5N bekerja pada sebuah benda yang terletak pada suatu permukaan lantai. Jika benda berpindah ke kanan sejauh 5 meter,usaha yang dilakukan pada benda oleh kedua gaya tersebut adalah

Answer:

75 Nm or 75 Joules

Explanation:

Dari pertanyaan tersebut, kami telah diberikan parameter berikut:

F1 = 10N

F2 = 5N

D = 5 Meter.

Kita diminta untuk mencari atau menghitung usaha yang dilakukan pada benda oleh dua gaya.

Rumus kerja yang dilakukan pada suatu benda dengan dua gaya =

W = (F1 + F2) × D

Dimana D = Perpindahan benda

W = (10N + 5N) × 5m

W = 15N × 5m

W = 75Nm atau 75Joules

Oleh karena itu, usaha yang dilakukan pada benda tersebut dengan dua gaya = 75Nm atau 75 Joules

6 0
2 years ago
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