At constant pressure, temperature is directly proportional to the volume and vise versa. The formula will be
V1/T1 = V2/T2
where V1 and T1 are the initial volume and temperature and V2 and T2 are the final volume and temperature. The temperature is in Kelvin and to convert Celsius to Kelvin add 273.
so, 6.24L/298 = V2/328
=6.87L
Answer:
It is a test for proteins in urine
Explanation:
The Biuret reagent is made of sodium hydroxide (NaOH) and hydrated copper(II) sulfate. The biuret reagent is commonly used to test for proteins. The biuret test is also known as Piotrowski's test. It is a chemical test commonly used in detecting the presence of peptide bonds. In the presence of peptides, a copper(II) ion forms purple-colored coordination complexes in an alkaline solution.
Hence the addition of this Biuret reagent to a urine sample in a test tube aims to detect the presence or absence of proteins in the given urine sample. If there is protein in the urine sample, the blue colour of the Biuret reagent turns purple. If there is no protein in the urine sample, the Biuret reagent remains blue.
In an alkaline solution, copper II is able to form a complex with the peptide bonds in proteins. Once this complex has been formed, the Biuret solution turns from a blue color to a purple color. This is the positive test for proteins.
<u>The given reaction is:</u>
F2 + ClO2 → 2FClO2
Rate = k[F2][ClO2]
<u>Explanation:</u>
The possible mechanism for this reaction can be broken down into two steps with the slow step being the rate determining step
Step 1: F2 + ClO2 → FClO2 + F ----------- Slow
Step 2: F + ClO2 → FClO2 ----------- Fast
-----------------------------------------------------------
Overall: F2 + 2ClO2 → 2FClO2
Rate = k[F2][ClO2]
Answer:
Explanation:
25.8 ml of .095 N NaOH is needed to neutralise the remaining acid
equivalent of NaOH used = 25.8 x .095 / 1000 = .002451 gm equivalent .
acid remaining = .002451 gm equivalent .
acid initially taken = 100 ml of .1 N / 1000 = . 01 gm equivalent
acid reacted with metal = .01 -.002451 = .007549 gm equivalent
This must have reacted with same gram equivalent of metal oxide
.007549 gm equivalent = .15 gm of metal oxide
1 gm equivalent = 19.87 gm
equivalent weight of metal = 19.87 - equivalent weight of oxygen
= 19.87 - 8 = 11.87 .
1
Answer:
On the opposite side of the rock.
Explanation: