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slega [8]
1 year ago
8

Which has not been suggested as a reasonably practical way to store large amounts of hydrogen in relatively small spaces for its

use as a fuel?
A. Liquefy hydrogen under pressure and store it much as we do with liquefied natural gas today.


B. Absorb hydrogen onto activated charcoal; then heat the mixture to release the hydrogen.


C. Store it in the form of ionic metal hydrides, such as LiH, which release hydrogen gas when they react with water.


D. Encapsulate hydrogen molecules in fullerene molecules (large, carbon-based molecules that can act like cages) that may be heated later to release the hydrogen.
Chemistry
1 answer:
Yakvenalex [24]1 year ago
5 0

Answer: A. Liquefy hydrogen under pressure and store it much as we do with liquefied natural gas today.

Explanation:

Current Hydrogen storage methods fall into one of two technologies;

  1. <em>physical storage</em> where compressed hydrogen gas is stored under pressure or as a liquid; and
  2. <em>chemical storage</em>, where the hydrogen is bonded with another material to form a hydride and released through a chemical reaction.

Physical storage solutions are commonly used technologies but are problematic when looking at using hydrogen to fuel vehicles. Compressed hydrogen gas needs to be stored under high pressure and  requires large and heavy tanks. Also, liquid hydrogen boils at -253°C (-423°F) so it needs to be stored cryogenically with heavy insulation and actually contains less hydrogen compared with the same volume of gasoline.  

Chemical storage methods allow hydrogen to be stored at much lower pressures and offer high storage performance due to the strong binding of hydrogen and the high storage densities. They also occupy relatively smaller spaces than either compressed hydrogen gas or liquified hydrogen. A large number of chemical storage systems are under investigation, which involve hydrolysis reactions, hydrogenation/dehydrogenation reactions, ammonia borane and other boron hydrides, ammonia, and alane etc.

Other practical storage methods being researched that focuses on storing hydrogen as a lightweight, compact energy carrier for mobile applications include;

  • Metal hydrides  e.g. LiH
  • Nanostructured metal hydrides
  • Non-metal hydrides
  • Carbohydrates
  • Synthesized hydrocarbons
  • Aluminum
  • Liquid organic hydrogen carriers (LOHC)
  • Encapsulation , e.t.c.
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1. Suppose 0.7542 g of magnesium reacts with excess oxygen to form magnesium oxide as the only product, what would be the theore
Alina [70]

Answer :

(1) The theoretical yield of product, MgO is, 1.257 grams.

(2) The percent yield of MgO is, 64.13 %

(3) If the percent yield is calculated to be over 100% then there might be some impurity present in the desired product.

Solution : Given,

Mass of Mg = 0.7542 g

Molar mass of Mg = 24 g/mole

Molar mass of MgO = 40 g/mole

First we have to calculate the moles of Mg.

\text{ Moles of }Mg=\frac{\text{ Mass of }Mg}{\text{ Molar mass of }Mg}=\frac{0.7542g}{24g/mole}=0.03142moles

Now we have to calculate the moles of MgO

The balanced chemical reaction is,

2Mg(s)+O_2(g)\rightarrow 2MgO(s)

From the reaction, we conclude that

As, 2 mole of Mg react to give 2 mole of MgO

So, 0.03142 moles of Mg react to give 0.03142 moles of MgO

Now we have to calculate the mass of MgO

\text{ Mass of }MgO=\text{ Moles of }MgO\times \text{ Molar mass of }MgO

\text{ Mass of }MgO=(0.03142moles)\times (40g/mole)=1.257g

Theoretical yield of MgO = 1.257 g

Experimental yield of MgO = 0.8922 g

Now we have to calculate the percent yield of MgO

\% \text{ yield of }MgO=\frac{\text{ Experimental yield of }MgO}{\text{ Theretical yield of }MgO}\times 100

\% \text{ yield of }MgO=\frac{0.8922g}{1.257g}\times 100=70.97\%

Therefore, the percent yield of MgO is, 70.97 %

If the percent yield is calculated to be over 100% then the product would be greater than 1.257 g which indicates that there might be some impurity present in the desired product.

4 0
2 years ago
When 64.0 g of methanol (CHOH) is burned, 1454 kJ of energy is produced. What is the heat of combustion for methanol?
andreev551 [17]

 The heat  of combustion  for  methanol   is 727  kj/mol


    <em><u>calculation</u></em>

 calculate the moles  of methanol (CH3OH)

moles = mass/molar  mass

molar mass of methanol =  12 +( 1 x3)  +16 + 1= 32 g /mol

moles is therefore= 64.0 g / 32 g/mol =  2 moles


Heat of combustion  is therefore = 1454 Kj / 2 moles =  727  Kj/mol

6 0
1 year ago
What is the mass of 0.921 moles of sulfur dioxide gas (SO2)?
Serhud [2]

Answer:

mass = 58.944 g

Explanation:

Given data:

Number of moles of SO₂ = 0.921 mol

Mass of SO₂ = ?

Solution:

Formula:

Number of moles = mass/ molar mass

First of all we will calculate the molar mass.

SO₂ = 32 + 16×2 = 64 g/mol

Now we will put the values in formula.

Number of moles = mass/ molar mass

0.921 mol = mass /64 g/mol

mass = 0.921 mol × 64 g/mol

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8 0
1 year ago
How many moles of carbon are in 7.87x10^7 carbon molecules?
zaharov [31]
There are 6.022*10^23 molecules in 1 mole of carbon
So how many will moles will be 7.87*20^7?
Let the required number of moles be ‘x’.
1 mole ———6.022*10^23
x moles———7.87*10^7
(Cross multiplication)
x=7.87*10^7/6.022*10^23
Therefore x=1.3*10^-16
6 0
1 year ago
3. Which of these statements is an accurate description of the ionization energies of elements in the periodic table?
dalvyx [7]

Answer:

option A is correct

Explanation:

7 0
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