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Vsevolod [243]
2 years ago
13

The group of molecules called nucleotides contain:

Chemistry
1 answer:
Grace [21]2 years ago
8 0
The group of molecules called nucleotides contain  phosphate groups, pyrimidines, purines, and <span>pentose (a 5-carbon sugar). Therefore, E. all of the above is the correct answer.</span> 
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A cell consists of a gold wire and a saturated calomel electrode (S.C.E.) in a 0.150 M AuNO 3 solution at 25 °C. The gold wire i
almond37 [142]

The half reaction that occurs at the Au electrode is  1.64

<u>Explanation:</u>

Half cell reaction at 'Au' electrode

We have the equation,

Au + (aq) + e-  ---> Au(s)

Given the concenration of AuNO3=0.150 M

[Au +] =0.150 m

From the equation,

Au + (aq) + e-  ---> Au(s)

Standard electric potential= Eo= 1.69 volt

Solving the problem using the Nerst equation

E cell= E0 cell - 2.303 RT/ nF  log Qc

Where,

T = 298 K

n= no of electron lost or gained

F= faraday's constant= 965000/mole

R= universal constant= 8.314 J/ K/ Mole

Substitue the values we get

E cell = 1.69 volt - 0.05 g/n log (1/0.150M)

E cell = 1.69 volt - 0.05 g/1  0.824

E cell= 1.64

The half reaction that occurs at the Au electrode is  1.64

<u />

6 0
2 years ago
A 0.50 M solution of formic acid, HCOOH, has a pH of 2.02. Calculate the percent ionization of HCOOH
kirza4 [7]

Answer is: <span>the percent ionizationof formic acid is 1,82%.
Chemical reaction: HCOOH(aq) </span>⇄ H⁺(aq) + HCOO⁻(aq).<span>
pKa(</span>HCOOH) = 3,77.

Ka(HCOOH) = 1,7·10⁻⁴.

c(HCOOH) = 0,5 M.

<span> [H</span>⁺] = [HCOO⁻] = x; equilibrium concentration.<span>
[HA] = 0,1 M - x.
Ka = [H</span>⁺] · [HCOO⁻] / [HCOOH].<span>
0,00017 = x² / 0,5 M - x.
Solve quadratic equation: x = 0,0091 M.
α = 0,0091 M ÷ 0,5 M · 100% = 1,82%.</span>

8 0
2 years ago
Read 2 more answers
Dry ice is solid carbon dioxide. A 0.050-g sample of dry ice is placed in an evacuated 4.6-L vessel at 30 °C. Calculate the pres
goldenfox [79]

The answer is 6.1*10^-3 atm.

The pictures and explanations are there.

3 0
2 years ago
Scientists determine that the wooden beams of a sunken ship have 67 % of the concentration of Carbon-14 that is found in the lea
DerKrebs [107]

Answer:

The age of ship is 1900 years.

Explanation:

The half life period of carbon - 14 is 5730 years

Ship have 67 % of the concentration of Carbon-14

And the ship lost (100- 67 = 33%) 33% of carbon - 14.

Therefore,

The age of ship = lost percentage X half life period of carbon -14

= 33 \times 5730 yrs = 1890.9yrs\equiv 1900\,years

Therefore, The age of ship is 1900 years.

3 0
2 years ago
Identify the functional groups attached to the benzene ring as either, being electron withdrawing, electron donating, or neither
Dominik [7]
-OH is elctron donating  -C=-N is electron withdrawing  -O-CO-CH3 is electron withdrawing  -N(CH3)2 is electron donating  -C(CH3)3 is electron donating  -CO-O-CH3 is electron withdrawing  -CH(CH3)2 is electron donating  -NO2 is electrong withdrawing  -CH2
8 0
2 years ago
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