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lilavasa [31]
2 years ago
11

The indicator propyl red has ka = 3.3 × 10–6 . estimate the approximate ph range over which this indicator would change color.

Chemistry
1 answer:
ollegr [7]2 years ago
7 0
We let the chemical equation for the weak acid indicator propyl red HPr be
     HPr + H2O ↔ H3O+ + Pr-
Therefore, the acid dissociation constant Ka is
     Ka = [H3O+][Pr-] / [HPr]
The color of this indicator turns from red to yellow or the other way around at its turning point at which 
     [HPr] = [Pr-]
Substituting this to the equation for Ka, we now have
     Ka = [H3O+]
The pH of the solution at its turning point is 
     pH = -log[H3O+] = -log(Ka) = -log 3.3×10^-6 = 5.48
<span>On this account, the pH range is pH 5.0 to 6.0.</span>
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2 years ago
Dissolving NaOH(s) in water is exothermic. Two calorimetry experiments are set up. Experiment 1: 2 g of NaOH are dissolved in 10
vlada-n [284]

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a. both temperature changes will be the same

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When sodium hydroxide (NaOH) is dissolved in water, a determined amount is released to the solution following the equation:

Q = m×C×ΔT

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Specific heat of both solutions is the same (Because the solutions are in fact the same). Specific heat = C.

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And Q is the heat released: If 2g release X heat, 4g release 2X.

Thus, ΔT in the experiments is:

Experiment 1:

X / 102C = ΔT

Experiment 2:

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5 0
2 years ago
how many moles of cesium carbonate will be produced when 5.34 moles of cesium reacts with iron iii carbonate
irga5000 [103]

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From the equation,

6moles of Cs produced 3 moles of Cs2CO3.

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What is the amount of Al2S3 remains when 20.00 g of Al2S3 and 2.00 g of H2O are reacted? A few of the molar masses are as follow
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