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ozzi
2 years ago
15

Gold is one of the densest substances known, with a density of 19.3 g/cm3. If the gold in the crown was mixed with a less-valuab

le metal like bronze or copper, how would that affect its density?
Chemistry
1 answer:
Andrews [41]2 years ago
4 0

Answer:

Explanation:

Density of gold is 19.3 g / cm³

Density of copper is 8.96 g / cm³

Density of bronze is 8.7  g / cm³

Hence when the gold and copper or bronze are mixed , the density of gold will be reduced due to less density of copper and bronze in comparison to that of gold.

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A 250. ml sample of 0.0328m hcl is partially neutralized by the addition of 100. ml of 0.0245m naoh. find the concentration of h
Ksenya-84 [330]

Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.

Explanation:

1) Molarity of 0.250 L HCl solution : 0.0328 M

Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0328=\frac{\text{Number of moles}}{0.250 L}

Moles of HCl in 0.250 L solution = 0.0082 moles

2) Molarity of 0.100 L NaOH solution : 0.0245 M

Molarity=\frac{\text{Number of moles}}{\text{Volume of solution in liters}}=0.0245=\frac{\text{Number of moles}}{0.100 L}

Moles of NaOH in 0.100 L solution = 0.00245 moles

3) Concentration of hydrochloric acid in the resulting solution.

0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.

Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L

Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles =  0.00575 moles

Molarity=\frac{\text{number of moles}}{\text{volume of solution in L}}

Molarity of HCl left un-neutralized :\frac{0.00575 moles}{0.350L}=0.0164 M

0.0164 molar concentration of hydrochloric acid in the resulting solution.

3 0
2 years ago
Freon-12, CF2Cl2, which has been widely used in air conditioning systems, is considered a threat to the ozone layer in the strat
Vilka [71]

Answer:

The root mean squared velocity for CF2Cl2 is  v_{rms}= 207.06 m/s

Explanation:

From the question we are told that

         The temperature is T = -65 ^oC = -65+273 = 208K

Root Mean Square velocity is mathematically represented as

      v _{rms} = \sqrt{\frac{3RT}{MW} }

 Where  T is the temperature

              MW is the molecular weight of gas

              R is the gas constant with a value of  R = 8.314 JK^{-1} mol^{-1}

For  CF2Cl2 its molecular weight is  0.121 kg/mol

     Substituting values

  v_{rms} = \sqrt{\frac{3 * 8.314 *208}{0.121} }

          v_{rms}= 207.06 m/s

5 0
2 years ago
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Murrr4er [49]

Answer:

The disadvantages of each of the given model of electron configuration have been mentioned below:

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1 year ago
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Answer:

i believe that 14  at a higher rate is the answer

Explanation:

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1 year ago
At STP graphite and diamond are two solid forms of carbon which statement explains why these two forms of carbon differ in hardn
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It seems that you have missed the necessary options for us to answer this question, but anyway, here is the answer. At STP graphite and diamond are two solid forms of carbon, the statement that explains why these two forms of carbon differ in hardness is this: <span>Graphite and diamond have different molecular structures. Hope this helps.</span>
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