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Rina8888 [55]
2 years ago
8

A student has samples of two pure compounds, XClO3 and ZClO3, which contain unknown alkali metals X and Z. The student measures

the mass of each sample and then strongly heats the samples to drive off all the oxygen, leaving solid residues of XCl and ZCl. The student measures the mass of the solid residue from each sample. Which of the following questions can be answered from the results of the experiment?
A. Which has the greater molar mass, X or Z?

B. Which has the higher boiling point, X or Z?

C. Which has the higher melting point, XCl or ZCl?

D. Which has the greater density, XCl or ZCl?
Chemistry
1 answer:
deff fn [24]2 years ago
5 0

Answer:

<u><em></em></u>

  • <u><em>A. Which has the greater molar mass, X or Z?</em></u>

Explanation:

By strongly heating up the starting substances to drive off all the oxygen, the student performs the following chemical decomposition reactions:

  • 2XClO₃ (s)  → 2XCl + 3O₂ (g)
  • 2ZClO₃ (s) → 2ZCl + 3O₂ (g)

The student knows the mass of each sample and the mass of the solid residue from each sample. That permits her to determine the mass of oxygen gas released from each sample:

  • mass of oxygen = mass of sample - mass of solid residue

With the mass of oxygen released, she can calculate the number of moles of oxygen in the original sample:

  • number of moles of oxygen = mass in grams of oxygen / molar mass of oxygen

Then she can calculate the number of moles of each sample:

  • There are 3 moles of O in every mole of  XClO₃ and in every ZClO₃.

So, the number of moles of each sample is the number of moles of oxygen released by each one divided by 3.

Now, the formula molar mass = mass in grams / number of moles will permit to determine the molar mass of each sample.

Hence, the student can answer the question A. Which has the greater molar mass, X or Z?

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UkoKoshka [18]

<span>We can use the heat equation,
Q = mcΔT </span>

 

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>


Let's assume that the finale temperature is T.

Q = 1200 J

<span> m = 36 g
c = 4.186 J/g °C</span>

ΔT = (T - 22) 

 

By applying the formula,

   1200 J = 36 g x 4.186 J/g °C x (T - 22)

  (T - 22) = 1200 J / (36 g x 4.186 J/g °C)

  (T - 22) = 7.96 °C

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Hence, the final temperature is 30 °C.

8 0
2 years ago
Read 2 more answers
A sample of bismuth weighing 0.687 g was converted to bismuth chloride by reacting it first with HNO3, and then with HCI, follow
alisha [4.7K]

Answer:

The empirical formula is BiCl3

% Bi = 66.27 %

Explanation:

Step 1: Data given

Mass of bismuth = 0.687 grams

Mass of bismuth chloride produced = 1.032 grams

Molar mass of bismuth = 208.98 g/mol

Molar mass of bismuth chloride = 315.33 g/mol

Step 2: The balanced equation

Step 3: Calculate moles of Bi

Moles Bi = mass Bi / molar mass Bi

Moles Bi = 0.687 grams / 208.98 g/mol

Moles Bi =  0.00329 moles

Step 4: Calculate moles of Cl

Mass of Cl = 1.032 - 0.687  = 0.345 moles

Moles Cl = 0.345 moles / 35.45 g/mol

Moles Cl = 0.00973 moles Cl

Step 5: Calculate mol ratio

We divide by the smaller number of moles:

Bi: 0.00329 / 0.00329 = 1

Cl: 0.0097The empirical formula is BiCl33/0.00329 = 3

Step 6: Calculate molar mass of BiCl3

Molar mass = 208.98 + 3*35.45 = 315.33 g/mol

Step 7: Calculate percent of Bi

% Bi = (208.98 / 315.33) * 100%

% Bi = 66.27 %

3 0
2 years ago
Element X reacts with copper to form the compounds CuX and CuX2. In which group on the Periodic Table is element X found?
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Cu has two possible charges: plus 1 and plus 2. Thus, when copper is combined with an anion (negatively charged ion), the anion carries a subscript of one or two. This is shown in the given, Moreover, the given shows copper carries a subscript only of one. This means the anion has an original charge of negative one. These elements belong to the halogen family (Group 17).
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4 0
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A 74.0-gram piece of metal at 94.0 °C is placed in 120.0 g of water in a calorimeter at 26.5 °C. The final temperature in the ca
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Answer:

Explanation:

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= 74 x S x ( 94 - 32 )

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heat gained by water = mass x specific heat x rise in temperature

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= 660

Heat lost = heat gained

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Specific heat of metal = .14 cal  / gm

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