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2 years ago

the pressure on 325 ml sample of oxygen gas was determined to be 0.768 atm. what will the volume of the shape be at 1220 torr?

Chemistry

1 answer:

LenaWriter [7]2 years ago

7 0

Answer:

156 mL will be the new volume of the shape

Explanation:

First of all, we need to convert the Torr to atm.

1220 Torr . 1 atm / 760 Torr = 1.60 atm

When the temperature remains constant, it is satisfied that the volume is modified indirectly proportionally.

Pressure is increased, then volume decreases

Pressure is decreased, then volume increases

P₁ . V₁ = P₂ . V₂

0.768 atm . 325mL = 1.60 atm . V₂

V₂ = 0.768 atm . 325mL / 1.60 atm → 156 mL

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How many ATP are produced from a fatty acid that is 14 carbons long?

fenix001 [56]

Answer:

92 ATP

Explanation:

Fatty acid oxidation results in the formation of large number of ATP molecules. Three important process of fatty acid are activation of the fatty acid, beta oxidation and entry of acetyl CoA in Krebs cycle.

14 carbon fatty acid is Miristic acid. The complete oxidation of Miristic acid results in the formation of 7 acetyl CoA + 6NADH and $6FADH_2$

1 Acetyl CoA gives 10 molecules of ATP then 7 acetyl CoA gives 70 molecules of ATP.

1NADH = 2.5 ATP, 6NADH = 15 ATP.

$1FADH_2$ = 1.5 ATP, $6FADH_2$ = 9 ATP.

2 ATP has been consumed in the activation of fatty acid.

Total ATP = 70+15+9-2

=92 ATP.

Thus, the total ATP generated from the oxidation of 14 carbon fatty acid is 92.

3 0

2 years ago

131i has a half-life of 8.04 days. assuming you start with a 1.53 mg sample of 131i, how many mg will remain after 13.0 days ___

inn [45]

For this problem we can use half-life formula and radioactive decay formula.

Half-life formula,
t1/2 = ln 2 / λ

where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days

Hence,
8.04 days = ln 2 / λ
λ = ln 2 / 8.04 days

Radioactive decay law,
Nt = No e∧(-λt)

where, Nt is amount of compound at t time, No is amount of compound at t = 0 time, t is time taken to decay and λ is radioactive decay constant.

Nt = ?
No = 1.53 mg
λ = ln 2 / 8.04 days = 0.693 / 8.04 days
t = 13.0 days

By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg

Hence, mass of remaining sample after 13.0 days = 0.499 mg

The answer is "e"

8 0

2 years ago

If a 300.0 ml sample of a gas is heated at constant pressure from 25.0ºc to 55.0ºc, its new volume is _____ ml?

jekas [21]

The new volume is 330.2 ml

<u><em>calculation</em></u>

The new volume is calculated using the Charles law formula

that is V1/T1= V2/T2

where T1= 25.0 c into kelvin = 25 +273 = 298 K

V1= 300.0 ml

T2 = 55.0 c into kelvin = 273 +55 =328 K

V2 = ? ml

make V2 the subject of the formula by multiplying both side by T2

V2= V1T2/ T1

V2 =[ (300.0 ml x 328 k) / 298 k} = 330.2 ml

8 0

2 years ago

Place the following in correct sequence from simplest to most complex: 1. molecules 2. atoms 3. tissues 4. cells 5. organs

Lera25 [3.4K]

Answer:

Simplest to complex

Atoms, molecules, cells, tissues, organs

Explanation:

An atom is the smallest or basic unit of any substance or thing. therefore, it is simplest among given.

Two or more atoms joined together to form molecules. Therefore, molecules are complex than atoms.

Cell is the basic unit of life and a cell is made of many molecules and compounds. So, cells are more complex than molecules.

Several cells organised in a definite way to form tissue, so tissues are group of cells and perform a definite function inside a living thing. So, tissues are more complex than cell.

Organs consist of several cells and tissues and perform a specific functions. Therefore, organs are the most complex structure among given.

Therefore order from simplest to complex is as follows:

Atoms, molecules, cells, tissues, organs

6 0

2 years ago

What volume, in ml, of a 0.2089 m ki solution contains enough ki to react exactly with the cu(no3)2 in 43.88 ml of a 0.3842 m so

Triss [41]

The reaction is given as: $2Cu(NO_{3})_{2}+4KI\rightarrow 2CuI+I_{2}+4KNO_{3}$ Here, two moles of copper nitrate reacts with four moles of potassium iodide to give two moles of copper iodide, one mole of iodine and four moles of potassium nitrate. First, calculate the number of moles of copper nitrate. Number of moles is equal to the product of molarity and volume of solution in litre. Number of moles = $0.3842 M\times 0.04388 L$ (1 L =1000 mL)

= $0.016858696 mole$

Copper nitrate requires = $0.016858696 \times \frac{4}{2}$ mole of potassium iodide

= $0.033717392 mole$ of potassium iodide

Volume of solution in litre = $\frac{number of moles}{Molarity}$

Thus, volume of potassium iodide is = $\frac{0.033717392}{0.2089}$

= $0.1614 L$

1 L =1000 mL

Volume of potassium iodide in mL = $161.4 mL$

Hence, $161.4 mL$ 0.2089 M potassium iodide consist of sufficient potassium iodide to react with copper nitrate in 3.88 mL of a 0.3842 M solution of copper nitrate .

7 0

2 years ago