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klemol [59]
1 year ago
12

6. Determine the amount in moles of the following:a. 12.15 g Mgb. 1.50 x 1023 atoms F​

Chemistry
1 answer:
igomit [66]1 year ago
3 0

a. 0.51 moles of Mg

b. 0.25 moles of F

Explanation:

a. To find the number of moles knowing the mass we use the following formula:

number of moles =  mass / molecular weight

number of moles of Mg = 12.15 / 24 = 0.51 moles

b. To find the number of moles knowing the number of atoms we use Avogadro's number to illustrate the following reasoning:

if in        1 mole of F there are 6.022 × 10²³ atoms of F

then in   X moles of F there are 1.5 × 10²³ atoms of F

X = (1 × 1.5 × 10²³) / 6.022 × 10²³

X = 0.25 moles of F

Learn more about:

Avogadro's number

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zhuklara [117]

Answer: The actual yield of B_2O_3 is 60.0 g

Explanation:-

The balanced chemical reaction :

B_2H_6(l)+3O_2(g)\rightarrow B_2O_3(s)+3H_2O(l)

Mass of B_2H_6 =Density\times Volume=1.131g/ml\times 36.9ml=41.7g

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} B_2H_6=\frac{41.7g}{27.668g/mol}=1.51moles

According to stoichiometry:

1 mole of B_2H_6 gives = 1 mole of B_2O_3

1.51 moles of B_2H_6 gives =\frac{1}{1}\times 1.51=1.51 moles of B_2O_3

Theoretical yield of B_2O_3=moles\times {Molar mass}}=1.14mol\times 69.62g/mol=79.3g

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\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

75.7\%=\frac{\text{Actual yield}}{79.3}\times 100

{\text{Actual yield}}=60.0g

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7 0
2 years ago
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Answer is: D. It is not sodium bicarbonate.

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This is chemical change (chemical reaction), because new substances are formed (sodium carbonate, carbon(IV) oxide and water), the atoms are rearranged, so there is no sodium bicarbonate (NaHCO₃) in the test tube.

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Answer:

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In point 4:

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