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GREYUIT [131]
2 years ago
11

You may normally expect a _____ reaction if a _____ activation energy is required.

Chemistry
2 answers:
cestrela7 [59]2 years ago
6 0

Answer:

You may normally expect a slow reaction if a high activation energy is required.

Or, You may normally expect a fast reaction if a low activation energy is required.

Explanation:

Strike441 [17]2 years ago
4 0

Answer:

  • You may normally expect a <em>slow</em> reaction if a <em>high</em> activation energy is required.
  • Or, You may normally expect a <em>fast</em> reaction if a <em>low</em> activation energy is required.

Explanation:

  • To answer this question, we should define firstly the term of activation energy.
  • The activation energy is the minimum energy must the reacting molecules have to initiate the chemical reaction.
  • Also, we can define it as The energy barrier that the molecules must posses an amount of energy equal or more than the value of this barrier.
  • So, as the activation energy be of low value, the possibility that the reacting molecules can have this amount of energy to initiate and proceed the reaction increases and the reaction rate also increases.
  • Additionally, as the activation energy be of high value, the possibility that the reacting molecules can have this amount of energy to initiate and proceed the reaction decreases and the reaction rate also decreases.

Thus, we can answer this question as:

  1. You may normally expect a <em>slow</em> reaction if a <em>high</em> activation energy is required.
  2. You may normally expect a <em>fast</em> reaction if a <em>low</em> activation energy is required.
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You find a little bit (0.150g) of a chemical marked Tri-Nitro-Toluene, and upon combusting it in oxygen, collect 0.204 g of CO2
avanturin [10]

1) Answer is: the formula is C₇N₃O₆H₅.

M(TNT) = 0.150 g; mass of the trinitrotoluene.

ω(N) = 18.5% ÷ 100%.

ω(N) = 0.185; mass percentage of the nitrogen.

m(N) = 0.150 g · 0.185.

m(N) = 0.02775 ·; mass of the nitrogen.

n(N) = 0.02775 g ÷ 14 g/mol.

n(N) = 0.002 mol; amount of the nitrogen.

n(CO₂) = 0.204 g ÷ 44 g/mol.

n(CO₂) = 0.0046 mol.

n(C) = n(CO₂) = 0.0046 mol; amount of the carbon.

m(C) = 0.0046 mol · 12 g/mol.

m(C) = 0.0552 g; mass of the carbon.

n(H₂O) = 0.030 g ÷ 18 g/mol.

n(H₂O) = 0.00166 mol.

n(H) = 2 · n(H₂O) = 0.0033 mol; amount of the hydrogen.

m(H) = 0.0033 mol · 1 g/mol.

m(H) = 0.0033 g; mass of the hydrogen.

2) m(O) = m(TNT) - m(N) - m(C) - m(H).  

m(O) = 0.150 g - 0.02775 g - 0.0552 g - 0.0033 g.

m(O) = 0.06375 g.

n(O) = 0.06375 g ÷ 16 g/mol.

n(O) = 0.004 mol; amount of oxygen.

n(C) : n(N) : n(O) : n(H) = 0.0046 mol : 0.002 mol : 0.004 mol : 0.0033 mol.

n(C) : n(N) : n(O) : n(H) = 2.33 : 1 : 2 : 1.66 /×3.

n(C) : n(N) : n(O) : n(H) = 7 : 3 : 6 : 5.

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2 years ago
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OLEGan [10]

Answer:

A. There is more dissolved oxygen in colder waters than in warm water.

D. If ocean temperature rise, then the risk to the fish population increases.

Explanation:

Conclusion that can be drawn from the two facts stated above:

*Dissolved oxygen is essential nutrient for fish survival in their aquatic habitat.

*Dissolved oxygen would decrease as the temperature of aquatic habit rises, and vice versa.

*Fishes, therefore, would thrive best in colder waters than warmer waters.

The following are scenarios that can be explained by the facts given and conclusions arrived:

A. There is more dissolved oxygen in colder waters than in warm water (solubility of gases decreases with increase in temperature)

D. If ocean temperature rise, then the risk to the fish population increases (fishes will thrive best in colder waters where dissolved oxygen is readily available).

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sertanlavr [38]
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<span>The second ionization energy of Na is larger than that of Mg because after first loss of electron Na has gained Noble Gas Configuration (Stable Configuration) and now requires greater energy to loose both second electron and Noble Gas Configuration. While Mg after second ionization attains Noble Gas Configuration hence it prices less energy.</span>
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Rabbits are eaten by predators such as foxes and wild dogs. If rabbit number decline predators ( foxes ) compete for the rest of the resources in forest. This is the competition between the members of same species or : interspecific competition. Foxes compete for the same resource ( rabbits ).
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Answer:

Explanation:

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