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notsponge [240]
2 years ago
9

The molar mass of copper(II) chloride (CuCl2) is 134.45 g/mol. How many formula units of CuCl2 are present in 17.6 g of CuCl2? 7

.88 × 1022 formula units 1.84 × 1023 formula units 1.91 × 1023 formula units 1.42 × 1024 formula units
Chemistry
2 answers:
diamong [38]2 years ago
8 0

The answer is,

<u>A. 7.88 × 1022 formula units</u>



Sedaia [141]2 years ago
5 0
7.88  10^22 formula units 
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A substance has a density of 4.5gmL. What is this in kgL? Report your answer with two significant figures.
Ipatiy [6.2K]

Answer:

4.5 kg/L

Explanation:

Density is 4.5g/mL and it means that in 1 mL of volume, the mass contained is 4.5 g.

Let's make a rule of three

1L = 1000 mL

1 mL has a mass of 4.5 g

1000 mL would have 4500 g

Our new density would be 4500 g/L, but we may convert the g to kg

1 kg / 1000 g . 4500 g = 4.5 kg

In conclusion 4.5 g/mL = 4.5 kg/L

7 0
1 year ago
A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
Sedbober [7]

Answer:

81°C.

Explanation:

To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat released from water (Q = - 1200 J).

m is the mass of the water (m = 20.0 g).

c is the specific heat capacity of water (c of water = 4.186 J/g.°C).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = final T - 95.0°C).

∵ Q = m.c.ΔT

∴ (- 1200 J) = (20.0 g)(4.186 J/g.°C)(final T - 95.0°C ).

(- 1200 J) = 83.72 final T - 7953.

∴ final T = (- 1200 J + 7953)/83.72 = 80.67°C ≅ 81.0°C.

<em>So, the right choice is: 81°C.</em>

7 0
2 years ago
When a 3.22 g sample of an unknown hydrate of sodium sulfate, na2so4 ⋅ h2o(s), is heated, h2o (molar mass 18 g) is driven off. T
Mariana [72]

The value of X is 10 hence the formula of unknown hydrate   sodium sulfate is  NaSO4.10 H20

calculation

step 1:find the moles of NaSO4 and the moles of H2O

moles= mass/molar mass

moles of Na2SO4=1.42÷142=0.01 moles

moles of H20=  mass of H2O/molar mass of H2O

mass of H2O= 3.22-1.42=1.8g

mole of H2O is therefore 1.8÷18=0.1 moles

step 2: find the mole ratio by dividing each mole by smallest number of mole (0.01)

that is Na2So4= 0.01/0.01 =1

            H2O= 0.1/0.01=10

6 0
1 year ago
Write a balanced equation for: (a) alpha decay of gold-173
Wittaler [7]
<span>The element gold has 32 isotopes, ranging from A =173 to A = 204. during alpha decay Au will loose 2 in atomic number and 4 in mass number . it will form a iridium isotope and helium . according to the above statement, the balanced equation for the alpha decay of gold 173 will be given as below. 173 169 4 79 Au-------------->77 Ir + 2He</span>
8 0
1 year ago
Choose two different particles found in the air. Explain how they are different and how they are the same
BARSIC [14]

Answer:

Dust and smoke.

Explanation:

Dust and smoke are two different particles present in the air. Dust and smoke are different from one another due to their origin. Smoke formed from burning of materials while dust refers to the soil particles lifted by the wind due to their light weight. Dust and smoke are similar to each other due to their small in size, infinite number means uncountable and light weight.

6 0
2 years ago
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