Answer:
q = -176kJ
Explanation:
HCl and NH3 reacts as following to NH4Cl
HCl(g) + NH3(g)=========>NH4Cl(s) : ΔH = -176 KJ
Clearly,
ENERGY IS EVOLVED MEANING IT IS A EXOTHERMIC REACTION .
therefore, the value of heat evolved as q = -176kJ
In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
Learn more: brainly.com/question/10079361
When we say decrease in boiling point, that means, we achieve boiling at a more lower temperature (lower than 100deg C). This is due to the lower atmospheric pressure. Boiling happens when the vapor pressure is equal the atmospheric pressure. Lower atmospheric pressure takes lower temperature for vapor pressure to equate with the atmospheric pressure. The answer here is letter B.
At higher elevations, it would take longer to hard boil an egg, because there is a lower boiling point, so the egg is boiling in water at a lower temperature.
Use ideal gas equation: pV = nRT
Now pass n to mass: n = mass / MM .... [MM is the molar mass]
pV = [mass/MM]*RT =>mass/V = [p*MM] / RT and mass / V = density
p= 130 kPa = 130,000 Pa = 130,00 joule / m^3
T = 10.0 ° + 273.15 = 283.15 k
MM of sulfur (S) = 32 g/mol = 32000 kg/mol
density = 130,000 Pa * 32000kg/mol / [8.31 joule / mol*k * 283.15 k] = 1.77*10^6 kg/m^3 = 1.77 g/L ≈ 1.8 g/L
Then, I do not get any of the option choices.
Is it possbile that the pressure is 13.0 kPa instead 130. kPa? If so the answer would be 18 g/L
Note that the mass is not used. You do not need it unless you are asked for the volume, which is not the case.
