Answer:
Maintaining a high starting-material concentration can render this reaction favorable.
Explanation:
A reaction is <em>favorable</em> when <em>ΔG < 0</em> (<em>exergonic</em>). ΔG depends on the temperature and on the reaction of reactants and products as established in the following expression:
ΔG = ΔG° + R.T.lnQ
where,
ΔG° is the standard Gibbs free energy
R is the ideal gas constant
T is the absolute temperature
Q is the reaction quotient
To make ΔG < 0 when ΔG° > 0 we need to make the term R.T.lnQ < 0. Since T is always positive we need lnQ to be negative, what happens when Q < 1. Q < 1 implies the concentration of reactants being greater than the concentration of products, that is, maintaining a high starting-material concentration will make Q < 1.
Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.
From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm
18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters
Answer:
3.52g
Explanation:
Zr = 90 g/mol
Si = 28 g/mol
O = 16 g/mol
ZrSiO4 = 90 + 28 + (16* 4) = 182g/mol
Mass = Numberof moles * Molar mass
Mass = 1mol * 182g/mol = 182g
In one mole of ZrSiO4, there are 4 oxygen atoms, hence the mass is given as;
4 * 16 = 64g
Hence, 64g of oxygen is present in 182g of ZrSiO4.
10g would contain x
64 = 182
x = 10
x = ( 10 * 64 ) / 182
x = 640 / 182 = 3.52g
Answer:
premium: 91 octane rating
Explanation:
Octane number refers to the percentage or volume fraction of isooctane in a fuel.
The octane number gives a picture of how safe a fuel is for an engine. The higher the octane rating the lesser the tendency of the fuel to cause knocking of the engine.
The type of gasoline with the highest percentage of octane among the options is premium.
Answer:
The empirical formula of the solid metal oxide is : 
Explanation:
M atom is present in the every corner and in the center of every face.
Number of m atoms :
Number of tetrahedral voids in F.C.C = 2n = 2 × 4 = 8
Oxide ion is present in the half of the tetrahedral void
Number oxide ions = 
The molecular formula of the solid metal oxide is : 
The empirical formula represent the lowest number of atoms present in a compound.
The empirical formula of the solid metal oxide is :
