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oksano4ka [1.4K]
2 years ago
9

If, as a pioneer, you wished to warm your room by taking an object heated on top of a pot-bellied stove to it, which of the foll

owing 15-pound objects, each heated to 100°C, would be the best choice? The specific heat capacity (in J/g·K) for each substance is given in parentheses. Iron (0.450), copper (0.387), granite (0.79), gold (0.129), water (4.184).
Chemistry
1 answer:
jok3333 [9.3K]2 years ago
7 0

Answer:

Waterwould be the best choice

Explanation:

<em>The specific heat capacity</em> refers to how much energy is required to raise the temperature of an object. The higher the specific heat capacity, the more energy is required to heat a given substance. This would also mean that w<u>ith a higher specific heat capacity, a substance would be able to retain more heat</u>.

With the above statements in mind, water would be the best choice, because it would retain more heat than the other substances once it reaches 100 °C, and in turn water would emit the most heat while it cools.

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What is the density (g/L) of CHCl3 vapor at 1.00 atm and 298 K?
Scrat [10]

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

4 0
2 years ago
Design a synthesis of 2-ethyl-2-hexenoic acid from alcohols of four carbons or fewer.
Studentka2010 [4]

Answer:

Enolate Alkylation

The anions from ketones, called enolates, can act as a nucleophile in SN2 type reactions.  Overall an α hydrogen is replaced with an alkyl group and a new carbon-carbon bond is formed.  These alkylations are affected by the same limitations as SN2 reactions previously discussed.  A good leaving group, chloride, bromide, iodide or tosylate, should be used.  Also, secondary and tertiary leaving groups should not be used because of poor reactivity and possible competition with elimination reactions.  Lastly, it is important to use a strong base, such as LDA or sodium amide, for preparing the enolate from the ketone.  Using a weaker base such as hydroxide or an alkoxide leaves the possibility of multiple alkylations occurring, and competing SN2 reactions with the base.

Explanation:

Design is illustrated in the attached document

4 0
2 years ago
Write the Lewis structure for ethanol (CH3CH2OH), the alcohol found in alcoholic beverages, then answer the following questions:
hodyreva [135]

Answer :

(1) The number of valence electrons present in the compound is, 20

(2) The number of bonded electrons present in the compound is, 16

(3) The number of lone pair electrons present in the compound is, 4

(4) The number of single bonds present in the compound is, 8

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, CH_3CH_2OH

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CH_3CH_2OH = 2(4) + 6(1) + 6 = 20

According to Lewis-dot structure, there are 16 number of bonding electrons and 4 number of non-bonding electrons or lone pair of electrons.

The Lewis-dot structure of CH_3CH_2OH is shown below.

8 0
2 years ago
During a titration the following data were collected. A 20.0 mL portion of solution of an unknown acid HX was titrated with 2.0
Dafna1 [17]

Answer:

The molarity of the acid HX is 6.0 M.

Explanation:

We determine the amount of moles of KOH used to neutralize the acid:

\frac{2.0moles_{KOH}}{1000ml} *60ml=0.12 moles KOH

Then, we calculate the amount of moles of acid:

0.12 moles KOH×\frac{1 mole HX}{1 moles KOH}=0.12 moles HX

The molarity of HX is:

\frac{0.12 moles HX}{20ml} *\frac{1000ml}{1l}=6.0 M

8 0
2 years ago
What is the amount of heat released by 1.00 gram of liquid water at 0°C when it changes to 1.00 gram of ice at 0°C?
QveST [7]

Answer:

334J/g

Explanation:

Data obtained from the question include:

Mass (m) = 1g

Specific heat of Fusion (Hf) = 334 J/g

Heat (Q) =?

Using the equation Q = m·Hf, we can obtain the heat released as follow:

Q = m·Hf

Q = 1 x 334

Q = 334J

Therefore, the amount of heat released is 334J

8 0
2 years ago
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