All categories

2 years ago

A Gas OCCUPIES 525ML AT A PRESSURE OF 85.0 kPa WHAT WOULD THE VOLUME OF THE GAS BE AT THE PRESSURE OF 65.0 kPa

2 answers:

german2 years ago

8 0

Boyle's law of ideal gas: This law states that the volume of a gas is inversely proportional to its pressure at a constant temperature. Acc to this law we can write the relation of pressure and volume as:

$PV=Constant$

That means:

$P_{1}V_{1}=P_{2}V_{2}$

From that equation we can calculate Volume of gas at a certain pressure:

P₁=Initial pressure

V₁=Initial volume

P₂=Final pressure

V₂= Final volume

Here P₁, initial pressure is given as 85.0 kPa

V₁, initial volume is given as 525 mL

P₂, final pressure is 65.0 kPa

$P_{1}V_{1}=P_{2}V_{2}$

so,

V_{2}=85\times 525\div 65

=686 mL

Volume of gas will be 686 mL.

tatiyna2 years ago

4 0

The answer is 45.0 I think idk tho

You might be interested in

Of the elements: b, c, f, li, and na. the element with the highest ionization energy is

padilas [110]

Carbon has the highest ionization energy as its energy 1086KJ\Mol and the rest are between 500 and 800.

6 0

2 years ago

When heating a flammable or volatile solvent for a recrystallization, which of these statements are correct? More than one answe

otez555 [7]

Explanation:

A volatile substance is defined as the substance which can easily evaporate into the atmosphere due to weak intermolecular forces present within its molecules.

Whereas a flammable substance is defined as a substance which is able to catch fire easily when it comes in contact with flame.

Hence, when we heat a flammable or volatile solvent for a recrystallization then it should be kept in mind that should heat the solvent in a stoppered flask to keep vapor away from any open flames so that it won't catch fire.

And, you should ensure that no one else is using an open flame near your experiment.

Thus, we can conclude that following statements are correct:

You should heat the solvent in a stoppered flask to keep vapor away from any open flames.

You should ensure that no one else is using an open flame near your experiment.

3 0

2 years ago

What is the density (in g/L) of a gas with a molar mass of 146.06 g/mol at 1.03 atm and 297k

marshall27 [118]

Lets assume the gas is acting Ideally, then According to Ideal Gas Equation the density is given as,

d = P M / R T ------- (1)
Where;
P = Pressure = 1.03 atm

M = Molar Mass = 146.06 g/mol

R = Gas Constant = 0.08206 atm.L.mol⁻¹.K⁻¹

T = Temperature = 297 K

Putting Values in eq. 1,

d = (1.03 atm × 146.06 g/mol) ÷ (0.08206 atm.L.mol⁻¹.K⁻¹ × 297 K)

density = 6.17 g/L

6 0

2 years ago

A sample of an unknown compound was decomposed and found to be composed of 1.36 mol oxygen, 4.10 mol hydrogen, and 2.05 mol carb

Flura [38]

Answer:

C3H6O2

Explanation:

To find the empirical formula of the compound, we divide the amount in moles of each of the elements by the amount in mole of the element with the smallest number of mole. In this question, the element with the smallest number of moles is oxygen with 1.36 mole. Hence, we divide the number of moles of each element by this.

H = 4.10/1.36 = 3

O = 1.36/1.36 = 1

C = 2.05/1.36 = 1.5

We then multiply through by 2 to yield the compound with the empirical formula C3H6O2

7 0

2 years ago

When C2H5Cl(g) is burned in oxygen, chlorine gas is produced in addition to carbon dioxide and water vapor. 5145 kJ of heat are

Arisa [49]

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

$\text{hydrocarbon}+O_2\rightarrow CO_2+H_2O$