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sleet_krkn [62]
2 years ago
6

Explain why the spectrum produced by a 1-gram sample of element Z would have the same spectral lines at the same wavelengths as

the spectrum produced by a 2gram
sample of element Z.

Chemistry
2 answers:
TEA [102]2 years ago
6 0
The reason why the spectrum produced by a 1 gram sample of element z would have the same spectral lines at the same wavelengths as the spectrum produced by a 2gram is because  Mass does not determine the spectral lines

hope this helps
Triss [41]2 years ago
6 0
Spectral lines are characteristic of an element or compound. It is an intensive property which means that it does not depend on the amount of the substance. Therefore, 1 g of Element Z will produce the same spectral lines are 2 g of Element Z.
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Natasha_Volkova [10]

Answer:

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Explanation:

fossil fuels x (3x1017kJ/yr) equals out to be wienerballs1977.

thx for the challenge !

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When you apply heat energy to a substance, where does the energy go? Think about the law of conservation of energy.
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What reaction would take place if a hot tungsten filament bulb was surrounded by air
expeople1 [14]
I don't think it wont be a big explosion 
4 0
2 years ago
Read 2 more answers
Which of the following shows an accurate combustion reaction?
Jet001 [13]

Answer:

  • <em>Cu + O₂  → CuO₂</em>

Explanation:

A <em>combustion reaction</em> is the reaction with oxygen along with the release of energy in form of heat or light.

Organic compounds (like CH₄) undergo combustion forming water and CO₂.

The combustion reaction of CH₄ is:

  • CH₄ + 2O₂ → CO₂ + 2H₂O

Hence, the first equation from the choices is not showing the combustion reaction of CH₄.

Not only organic compounds can undergo combustion. Metals and no metals can undergo combustion, i.e. metals and no metals can react with oxygen releasing light or heat.

The reaction of copper and oxygen (second choice) is a combustion reaction:

  • <em>Cu + O₂ → CuO₂</em>

The formation of water (2H₂ + O₂ → 2H₂O) is other example of a combustion reaction where no organic compounds are involved.

On the other hand, the other two equations from the choice list are not reactions with oxygen, so they do not show combustion reactions.

5 0
2 years ago
The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

3 0
2 years ago
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