Question

A piece of metal ore weighs 8.25 g. when a student places it into a graduated cylinder containing water, the liquid level rises from 21.25 ml to 26.47 ml. what is the density of the ore? 0.312 g/ml 1.58 g/ml 3.21 g/ml 0.633 g/ml

Answer 1

Answer: Option (b) is the correct answer.

Explanation:

As it is known that density is the mass present in per unit volume.

Mathematically,     Density = $\frac{mass}{volume}$

As initial volume is given as 21.25 ml and final volume is given as 26.47. Hence, change in volume will be calculated as follows.

               Change in volume = 26.47 ml - 21.25 ml

                                               = 5.22 ml

As mass is given as 8.25 g. Therefore, density of the given ore will be calculated as follows.

                  Density = $\frac{mass}{volume}$

                                = $\frac{8.25 g}{5.22 ml}$

                                = 1.58 g/ml

Thus, we can conclude that density of the ore is 1.58 g/ml.

Answer 2

26.47 mL - 21.25 mL = 5.22 mL

8.25 g / 5.22 mL = 1.58 g/mL