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matrenka [14]
2 years ago
5

A piece of metal ore weighs 8.25 g. when a student places it into a graduated cylinder containing water, the liquid level rises

from 21.25 ml to 26.47 ml. what is the density of the ore? 0.312 g/ml 1.58 g/ml 3.21 g/ml 0.633 g/ml
Chemistry
2 answers:
kap26 [50]2 years ago
8 0

Answer: Option (b) is the correct answer.

Explanation:

As it is known that density is the mass present in per unit volume.

Mathematically,     Density = \frac{mass}{volume}

As initial volume is given as 21.25 ml and final volume is given as 26.47. Hence, change in volume will be calculated as follows.

               Change in volume = 26.47 ml - 21.25 ml

                                               = 5.22 ml

As mass is given as 8.25 g. Therefore, density of the given ore will be calculated as follows.

                  Density = \frac{mass}{volume}

                                = \frac{8.25 g}{5.22 ml}

                                = 1.58 g/ml

Thus, we can conclude that density of the ore is 1.58 g/ml.

Solnce55 [7]2 years ago
4 0
26.47 mL - 21.25 mL = 5.22 mL

8.25 g / 5.22 mL = 1.58 g/mL
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