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2 years ago

If 3.18 x 10^23 atoms of iron react with 67.2 L of chlorine gas at STP, what is the maximum

1 answer:

3 0

84.34 grams of grams of iron (III) chloride that can be produced is maximum because Fe is the limiting reagent in this reaction and chlorine gas is excess reagent.

Explanation:

Balanced chemical equation:

2 Fe + 3 Cl2 → 2 FeCl3

DATA GIVEN:

iron = atoms

mass of chlorine gas = 67.2 liters

mass of FeCl3 = ?

number of moles of iron will be calculated as

number of moles = $\frac{total number of atoms}{Avagaro's number}$

number of moles = $\frac{3.18 x 10^23}{6.022x 10^23}$

number of moles = 0.52 moles of iron

moles of chlorine gas

number of moles = $\frac{mass}{molar mass of 1 mole}$

Putting the values in the equation:

n = $\frac{67200}{70.96}$ (atomic mass of chlorine gas = 70.96 grams/mole)

= 947.01 moles

Fe is the limiting reagent so

2 moles of Fe gives 2 moles of FeCl3

0.52 moles of Fe will give

$\frac{2}{2}$ = $\frac{x}{0.52}$

0.52 moles of FeCl3 is formed.

to convert it into grams:

mass = n X atomic mass

= 0.52 x 162.2 (atomic mass of FeCl3 is 162.2grams/mole)

<h3> = 84.34 grams </h3>

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Answer:

The answer to your question is:

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A 8.6 g sample of methane and 15.6 g sample of oxygen react according to the reaction in the video. identify the limiting reacta

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Answer:

<span>23.6 g carbon dioxide comes from 8.6 g of CH4 or 10.7 g carbon dioxide comes from 15.6 g O that means the 15.6 g of oxygen is still the limiting reactant because it gets used up and only makes 10.7 g of CO2. </span>

Explanation:

1) Balanced chemical equation:

CH₄ + 2O₂ → CO₂ + 2H₂O

2) mole ratios:
1 mol CH₄ : 2mol O₂ : 1 mol CO₂ : 2 mol H₂O

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O₂: 32.0 g/mol
CO₂: 44.01 g/mol

4) Convert the reactant masses to number of moles, using the formula

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CH₄: 8.6g / 16.04 g/mol = 0.5362 moles
<span />

O₂: 15.6 g / 32.0 g/mol = 0.4875 moles

5) If the whole 0.5632 moles of CH₄ reacted that yields to the same number of moles of CO₂ and that is a mass of:
mass of CO₂ = number of moles x molar mass = 23.60 g of CO₂

Which is what the first part of the answer says.

6) If the whole 0.4875 moles of O₂ reacted that would yield 0.4875 / 2 = 0.24375 moles of CO₂, and that is a mass of:
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Which is what the second part of the answer says.

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Which is what the chosen answer says.

8) From the mole ratios 0.4875 moles of O₂ produce 0.4875 / 2 moles of CO₂, and that is:
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Molecular Shape around Carbon Atom (Green):

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