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Solnce55 [7]
2 years ago
12

If 3.18 x 10^23 atoms of iron react with 67.2 L of chlorine gas at STP, what is the maximum

Chemistry
1 answer:
spin [16.1K]2 years ago
3 0

84.34 grams of grams of iron (III) chloride that can be produced is maximum because Fe is the limiting reagent in this reaction and chlorine gas is excess reagent.

Explanation:

Balanced chemical equation:

2 Fe + 3 Cl2 → 2 FeCl3​

DATA GIVEN:

iron =  atoms

mass of chlorine gas = 67.2 liters

mass of FeCl3 = ?

number of moles of iron will be calculated as

number of moles = \frac{total number of atoms}{Avagaro's number}

number of moles = \frac{3.18 x 10^23}{6.022x 10^23}

number of moles = 0.52 moles of iron

moles of chlorine gas

number of moles = \frac{mass}{molar mass of 1 mole}

Putting the values in the equation:

n = \frac{67200}{70.96}               (atomic mass of chlorine gas = 70.96 grams/mole)

   = 947.01 moles

Fe is the limiting reagent so

2 moles of Fe gives 2 moles of FeCl3

0.52 moles of Fe will give

\frac{2}{2} = \frac{x}{0.52}

0.52 moles of FeCl3 is formed.

to convert it into grams:

mass = n X atomic mass

         = 0.52 x 162.2                   (atomic mass of FeCl3 is 162.2grams/mole)  

<h3>           = 84.34 grams         </h3>
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