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2 years ago

If 4.9 kg of CO2 are produced during a combustion reaction, how many molecules of CO2 would be produced?

Chemistry

1 answer:

solmaris [256]2 years ago

5 0

Answer:

6.7 x 10²⁶molecules

Explanation:

Given parameters

Mass of CO₂ = 4.9kg = 4900g

Unknown:

Number of molecules = ?

Solution:

To find the number of molecules, we need to find the number of moles first.

Number of moles = $\frac{mass}{molar mass}$

Molar mass of CO₂ = 12 + 2(16) = 44g/mol

Number of moles = $\frac{4900}{44}$ = 111.36mole

A mole of substance is the quantity of substance that contains the avogadro's number of particles.

1 mole = 6.02 x 10²³molecules

111.36 moles = 111.36 x 6.02 x 10²³molecules = 6.7 x 10²⁶molecules

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The interior of a refrigerator has a volume of 0.600 m3. the temperature inside the refrigerator in 282 k, and the pressure is 1

Dafna11 [192]

In this instance we can use the ideal gas law equation to find the number of moles of gas inside the refrigerator
PV = nRT
where
P - pressure - 101 000 Pa
V - volume - 0.600 m³
n - number of moles
R - universal gas constant - 8.314 J/mol.K
T - temperature - 282 K
substituting these values in the equation
101 000 Pa x 0.600 m³ = n x 8.314 J/mol.K x 282 K
n = 25.8 mol
there are 25.8 mol of the gas
to find the mass of gas
mass of gas = number of moles x molar mass of gas
mass = 25.8 mol x 29 g/mol = 748.2 g
mass of gas present is 748.2 g

6 0

2 years ago

Jamal wants to make a model of a hill near his house to test the way the slope affects how rain runs down the hill. Which type o

Nikitich [7]

a scale-model mound made of the same materials that make the real hill

4 0

2 years ago

Read 2 more answers

11. A sample contains 25% water and weighs 201 grams. Determine the grams of water in the

77julia77 [94]

Answer:

$m_{water}=50.25g$

Explanation:

Hello,

In this case, considering that the by-mass percent of water is:

$\% m/m=\frac{m_{water}}{m_{sample}}*100\%$

Given such percent and the mass of the sample, we can find the mass of water in grams in the sample by solving for it as shown below:

$m_{water}=\frac{\%m/m*m_{sample}}{100\%}\\ \\m_{water}=\frac{25\%*201g}{100\%}\\ \\m_{water}=50.25g$

Best regards.

5 0

2 years ago

A species has the following MO configuration: (σ1s)2(σ1s*)2(σ2s)2(σ2s*)2(σ2p)2(π2p)2. This substance is:_______.

Goshia [24]

Answer : The correct option is, (a) paramagnetic with two unpaired electrons.

Explanation :

According to the molecular orbital theory, the general molecular orbital configuration will be,

$(\sigma_{1s}),(\sigma_{1s}^*),(\sigma_{2s}),(\sigma_{2s}^*),(\sigma_{2p_z}),[(\pi_{2p_x})=(\pi_{2p_y})],[(\pi_{2p_x}^*)=(\pi_{2p_y}^*)],(\sigma_{2p_z}^*)$

As there are 14 electrons present in the given configuration.

The molecular orbital configuration of molecule will be,

$(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^2,(\sigma_{2s}^*)^2,(\sigma_{2p_z})^2,[(\pi_{2p_x})^1=(\pi_{2p_y})^1],[(\pi_{2p_x}^*)^0=(\pi_{2p_y}^*)^0],(\sigma_{2p_z}^*)^0$

The number of unpaired electron in the given configuration is, 2. So, this is paramagnetic. That means, more the number of unpaired electrons, more paramagnetic.

Hence, the correct option is, (a) paramagnetic with two unpaired electrons.

3 0

2 years ago

Which of the following can be best explained by temporary dipole moments?

Tju [1.3M]

Answer:

B. This explains how two noble gases' molecules can have an attractive force between them.

C. This explains why long hydrocarbon chains have relatively high boiling points.

Explanation:

Temporary dipole moments are weak intermolecular force of attraction between two or more compounds. They are the weakest of intermolecular forces. They form when non-polar molecules becomes polar due to the constant motion of their electrons. This may lead to an uneven charge distribution at an instant.

When this occurs, the molecule has a temporary dipole. The dipole can induce neighboring molecules to be distorted and form dipoles as well.

Two noble gases can exhibit this bonding attraction usually when at low temperature. The temporary dipole cause a temporary charge separation and can lead to attraction.
Long hydrocarbons of long chains also exhibits this bonding which can cause a rise in their boiling point.
Ammonia and nitrogen gas will exhibit hydrogen bonding, a strong dipole - dipole attraction.
Hydrogen fluoride and methanol has hydrogen bonds likewise dimethyl either and acetone.

6 0

2 years ago