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2 years ago

If 4.9 kg of CO2 are produced during a combustion reaction, how many molecules of CO2 would be produced?

Chemistry

1 answer:

solmaris [256]2 years ago

5 0

Answer:

6.7 x 10²⁶molecules

Explanation:

Given parameters

Mass of CO₂ = 4.9kg = 4900g

Unknown:

Number of molecules = ?

Solution:

To find the number of molecules, we need to find the number of moles first.

Number of moles = $\frac{mass}{molar mass}$

Molar mass of CO₂ = 12 + 2(16) = 44g/mol

Number of moles = $\frac{4900}{44}$ = 111.36mole

A mole of substance is the quantity of substance that contains the avogadro's number of particles.

1 mole = 6.02 x 10²³molecules

111.36 moles = 111.36 x 6.02 x 10²³molecules = 6.7 x 10²⁶molecules

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(a) calculate the %ic of the interatomic bond for the intermetallic compound tial3. (b) on the basis of this result, what type o

Mrrafil [7]

Answer :

The correct answer is %IC = 10 % and bond is covalent bond with slight polarity.

<u>Percent Ionic Character :</u>

It is defined as percent of ionic character present in a polar covalent bond . The formula of % ionic character (%IC) is given as follows :

$Percent Ionic character = 1 - e^-^0^.^2^5 ^*^(^X^a^-^X^b^) * 100$

Where Xa = Electronegativity of A atom and Xb = Electronegativity of B atom

Given : Molecule is TiAl₃

Electronegativity of Ti = 2.0

Electronegativity of Al = 1.6 ( From image shared )

Plug the value in above formula :

$Percent Ionic character = 1 - e^-^0^.^2^5 ^*^(^2^.^0^-^1^.^6^) * 100$

$Percent Ionic character = 1 - e^(^-^0^.^2^5 ^*^0^.^4^) * 100$

$Percent Ionic character = 1 - e^(^-^0^.^1^) * 100$

Value of e⁻¹ = 0.90

Percent ionic character = 1 - 0.90 * 100

Percent Ionic character = 10 %

<u>Since the % IC is 10 % , which is very less comparatively , hence the bond is covalent and very less polar .</u>

8 0

2 years ago

The Michaelis‑Menten equation models the hyperbolic relationship between [S] and the initial reaction rate V 0 V0 for an enzyme‑

ipn [44]

Answer:

The Michaelis‑Menten equation is given as

v₀ = Kcat X [E₀] X [S] / (Km + [S])

where,

Kcat is the experimental rate constant of the reaction; [s] is the substrate concentration and

Km is the Michaelis‑Menten constant.

Explanation:

See attached image for a detailed explanation

3 0

2 years ago

At higher elevations, the boiling point of water decreases, due to the decrease in atmospheric pressure. As a result, what could

amid [387]

When we say decrease in boiling point, that means, we achieve boiling at a more lower temperature (lower than 100deg C). This is due to the lower atmospheric pressure. Boiling happens when the vapor pressure is equal the atmospheric pressure. Lower atmospheric pressure takes lower temperature for vapor pressure to equate with the atmospheric pressure. The answer here is letter B.
At higher elevations, it would take longer to hard boil an egg, because there is a lower boiling point, so the egg is boiling in water at a lower temperature.

8 0

1 year ago

Micky Mo is a 64-year-old male admitted to the emergency room for asthma. His laboratory results are as follows: pH 7.31, pCO2 h

Salsk061 [2.6K]

Answer:

Micky Mo is suffering from respiratory acidosis.

Explanation:

The pCO2 level in micky"s body is higher than normal it means the excess amount of CO2 will reacts with water to generate carbonic acid(H2CO3).

On the other hand according to the question total HCO3- also higher than normal.As a result the excess HCO3- will react with proton to form carbonic acid which is in turn dissociate to generate CO2 and H2O to maintain normal acid base homeostasis.

From that point of view it can be said Micky Mo is suffering from respiratory acidosis.

5 0

2 years ago

HCN forms when synthetic fibers containing Orlon® or Acrilan® burn. Acrilan® has an empirical formula of CH2CHCN, so HCN is 50.9

hichkok12 [17]

Answer:

676 g

Explanation:

First, let's calculate the area of the rug: 3.70x4.20 = 15.54 m². Knowing that 1 yard has 0.9144 m, so

1 yd² = (0.9144 m)² = 0.8361 m²

So, there is 30.0 oz in 0.8361 m²

30.0 oz-----------------0.8361 m²

x -----------------15.54 m²

By a simple direct three rule:

0.8361x = 466.2

x = 557.6 oz of Acrilan in the rug

1 oz = 28.35 grams, so 557.6 oz = 15807.96 g

The potencial of HCN is 50.9% of this mass, so: 0.509x15807.96 = 8046.25 g.

But only 42.0% of the rug is burned, so the potencial of HCN is 42.0% of 8046.25: 0.42x 8046.25 = 3379.42 g.

And the yield is only 20.%, so the mass formed of HCN is:

0.20x3379.42 = 676 g

5 0

1 year ago