answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VMariaS [17]
2 years ago
13

Lead is malleable, so it can be pounded into flat sheets without breaking. How does the bonding within lead help to explain this

property?
Metallic bonds involve valence electrons that are removed from one atom and given to another, so the pounding helps the electrons move.
Covalent bonds involve valence electrons that are shared between two metal atoms, so the bonds are strong enough to resist the pounding.
Metallic bonds involve many valence electrons shared by many atoms, so the bonds can move around as the metal is pounded.
Covalent bonds involve valence electrons that are removed from one atom and given to another, so the pounding helps the electrons move.
Chemistry
2 answers:
jarptica [38.1K]2 years ago
9 0

The answer is Metallic bonds involve many valence electrons shared by many atoms, so the bonds can move around as the metal is pounded. The metallic bond structure of lead forms a cubic crystal structure and the atoms can roll over one another without breaking the metallic bonds. This is especially because the p orbital electrons of lead can be delocalized and the electrons can be shared with other lead ions in the cubic structure of lead.

Lena [83]2 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

In metallic bonding, the valence electrons are involved in bonding with many atoms.

As a result, valence electrons dissociate within their atomic core and form a sea of electrons which helps in binding the positively charged ions.

Thus, we can conclude that the bonding within lead help to explain this property as metallic bonds involve many valence electrons shared by many atoms, so the bonds can move around as the metal is pounded.

You might be interested in
Calculate the number of grams of xenon in 4.658 g of the compound xenon tetrafluoride.
andrezito [222]

Answer:

The mass of xenon in the compound is 2.950 grams

Explanation:

Step 1: Data given

Mass of XeF4 = 4.658 grams

Molar mass of XeF4 = 207.28 g/mol

Step 2: Calculate moles of XeF4

Moles XeF4 = mass XeF4 / molar mass XeF4

Moles XeF4 = 4.658 grams / 207.28 g/mol

Moles XeF4 = 0.02247 moles

Step 3: Calculate moles of xenon

XeF4 → Xe + 4F-

For 1 mol xenon tetrafluoride, we have 1 mol of xenon

For 0.02247 moles XeF4 we have 0.02247 moles Xe

Step 4: Calculate mass of xenon

Mass xenon = moles xenon * molar mass xenon

Mass xenon = 0.02247 moles * 131.29 g/mol

Mass xenon = 2.950 grams

The mass of xenon in the compound is 2.950 grams

5 0
2 years ago
When a known quantity of compound, at a known concentration, is added to a known volume of another compound to determine the con
Vladimir [108]

Answer:

A titration

Explanation:

A common example of a titration is when we have an acid of unknown concentration, so we add a known volume of a base of known concentration. This process lets us determine the concentration of the acid.

By definition, a titration is a quantitative analysis, as we determine how much of an analyte is there in a sample. However, <u>there are quantitative analyzes which are not titrations</u>. This is why the most appropiate answer is<em> a titration</em>.

5 0
1 year ago
The ksp of agcl is 1.6 x 10-10. what is the solubility of agcl in 0.010 m fecl3? give your answer using scientific notation (1.2
bija089 [108]

Ksp of AgCl= 1.6×10⁻¹⁰

AgCl=Ag⁺ +Cl⁻

Ksp=[Ag⁺][Cl⁻]

Assume [Ag⁺]=[Cl⁻]=x

Ksp=x²

1.6×10⁻¹⁰=x²

x=0.000012

In FeCl₃:

FeCl₃------>Fe⁺³+ 3Cl⁻

as there is 0.010 M FeCl₃

So there will be ,

[Cl⁻]= 0.030

So

[Ag⁺]=Ksp/[Cl⁻]

=1.6×10⁻¹⁰/0.030

=5.3×10⁻⁹

so solubility of AgCl in FeCl₃ will be 5.3×10⁻⁹.

7 0
2 years ago
Read 2 more answers
A solution is prepared by dissolving 10.0 g of NaBr and 10.0 g of Na2SO4 in water to make a 100.0 mL solution. This solution is
Colt1911 [192]

Answer:

M_{Na^+}=1.36M

M_{Br^-}=1.58M

Explanation:

Hello,

At first, it turns out convenient to compute the total moles of sodium that will be dissolved into the solution by considering the added amounts of sodium bromide and sodium sulfate:

n_{Na^+}=n_{Na^+,NaBr}+n_{Na^+,Na_2SO_4}\\n_{Na^+,NaBr}=10.0gNaBr*\frac{1molNaBr}{103gNaBr}*\frac{1molNa^+}{1molNaBr}=0.0971molNa^+\\n_{Na^+,Na_2SO_4}=10.0gNa_2SO_4*\frac{1molNa_2SO_4}{142gNa_2SO_4}*\frac{2molNa^+}{1molNa_2SO_4} =0.141molNa^+\\n_{Na^+}=0.0971molNa^++0.141molNa^+\\n_{Na^+}=0.238molNa^+

Once we've got the moles we compute the final volume via:

V=100.0mL+75.0mL=175.0mL*\frac{1L}{1000mL}=0.1750L

Thus, the molarity of the sodium atoms turn out into:

M_{Na^+}=\frac{0.238mol}{0.1750L} =1.36M

Now, we perform the same procedure but now for the bromide ions:

n_{Br^-}=n_{Br^-,NaBr}+n_{Br^-,AlBr_3}\\n_{Br^-,NaBr}=10.0gNaBr*\frac{1molNaBr}{103gNaBr}*\frac{1molBr^-}{1molNaBr}=0.0971molBr^-\\n_{Br^-,AlBr_3}=0.0750L*0.800\frac{molAlBr_3}{L} *\frac{3molBr^-}{1molAlBr_3}=0.180molBr^- \\n_{Br^-}=0.0971molBr^-+0.180molBr^-\\n_{Br^-}=0.277molBr^-

Finally, its molarity results:

M_{Br^-}=\frac{0.277molBr^-}{0.1750L}=1.58M

Best regards.

7 0
1 year ago
Which of the following statements correctly relates mutations and survival rates of plants?
Tasya [4]
Answer is: <span>Mutations sometimes improve the chances of survival for a plant.
</span>Mutations are very important because they change <span>variability in populations and in that way enable evolutionary change.
</span>There are three types of mutations:
1) good or advantageous mutations - <span> improve the chances of survival for a plant.
2) </span>bad or deleterious - decrease the chances of survival for a plant.
3) neutral -  not affect he chances of survival for a plant.
3 0
2 years ago
Other questions:
  • Explain why the spectrum produced by a 1-gram sample of element Z would have the same spectral lines at the same wavelengths as
    6·2 answers
  • If 2.0 ml of 6.0m hcl is used to make a 500.0-ml aqueous solution, what is the molarity of the dilute solution?
    10·2 answers
  • Which expression is equal to the number of grams (g) in 2.43 kilograms (kg)?
    14·2 answers
  • Why are the electrons in a nitrogen-phosphorus covalent bond not shared equally? which atom do the electrons spend more time aro
    7·1 answer
  • During an endothermic reaction, H for the reactants was −600 kJ/mol. Which of the following statements is correct about the H fo
    7·2 answers
  • The student decided to do another experiment with his leftover copper(II) sulfate (CuSO4) solution. He divided the solution up i
    12·1 answer
  • Which of the following statements is true for a system at chemical equilibrium?
    11·1 answer
  • A research balloon at ground level contains 12 L of helium (He) at a pressure of 725mmHg and a temperature of 30.00∘C. When the
    9·1 answer
  • Is humidity a extensive or intensive property
    15·2 answers
  • Discuss some of the biotic (living) and abiotic (nonliving) factors in the chimps’ ecosystem that affect their behavior.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!