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san4es73 [151]
1 year ago
13

Which substance can be described as cations bonded together by mobile electrons?a. S8(s)b. Ag(s)c. SiO2(s)d. KCl(s)e. Kr(l)

Chemistry
1 answer:
Alex73 [517]1 year ago
5 0

Answer:

Ag(s)

Explanation:

Metal atoms are held together by the metallic bond. The metallic bond consists of cations held together by a sea of mobile electrons.

Thus, the crystal of Ag(s) is composed of silver ions held together by a sea of mobile electrons. Electrostatic forces of attraction holds the crystal together.

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How many moles of oxygen atoms are in 132.2 g of MgSO4?
zzz [600]

4.4moles of oxygen atoms

Explanation:

Given parameters:

Mass of MgSO₄ = 132.2g

Unknown:

Number of moles of oxygen atoms = ?

Solution:

The number of moles is the quantity of substance that contains the avogadro's number of particles.

 To solve for this;

 Number of moles = \frac{mass}{molar mass}

Molar mass of MgSO₄ = 24 + 32 + 4(16) = 120g/mole

  Number of moles = \frac{132.2}{120} = 1.1 moles

In

     1 moles of MgSO₄ we have 4 moles of oxygen atoms

    1.1 moles of MgSO₄ contains 4 x 1.1 moles = 4.4moles of oxygen atoms

learn more:

number of moles  brainly.com/question/1841136

#learnwithBrainly

8 0
2 years ago
6K + B2O3 → 3K2O + 2B
atroni [7]

Answer:

104.84 moles

Explanation:

Given data:

Moles of Boron produced = ?

Mass of B₂O₃ = 3650 g

Solution:

Chemical equation:

6K + B₂O₃    →    3K₂O + 2B

Number of moles of B₂O₃:

Number of moles = mass/ molar mass

Number of moles = 3650 g/ 69.63 g/mol

Number of moles = 52.42 mol

Now we will compare the moles of  B₂O₃ with B from balance chemical equation:

                 B₂O₃          :          B

                    1              :          2

                52.42         :        2×52.42 = 104.84

Thus from 3650 g of  B₂O₃  104.84 moles of boron will produced.

6 0
2 years ago
2CH4(g)⟶C2H4(g)+2H2(g)
Rasek [7]

Answer : The enthalpy change for the reaction is, 201.9 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The balanced reaction of CH_4 will be,

2CH_4(g)\rightarrow C_2H_4(g)+2H_2(g)    \Delta H^o=?

The intermediate balanced chemical reaction will be,

(1) CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(l)     \Delta H_1=-890.3kJ

(2) C_2H_4(g)+H_2(g)\rightarrow C_2H_6(g)     \Delta H_2=-136.3kJ

(3) 2H_2(g)+O_2(g)\rightarrow 2H_2O(l)    \Delta H_3=-571.6kJ

(4) 2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(l)     \Delta H_4=-3120.8kJ

Now we will multiply the reaction 1 by 2, revere the reaction 2, reverse and half the reaction 3 and 4 then adding all the equations, we get :

(1) 2CH_4(g)+4O_2(g)\rightarrow 2CO_2(g)+4H_2O(l)     \Delta H_1=2\times (-890.3kJ)=-1780.6kJ

(2) C_2H_6(g)\rightarrow C_2H_4(g)+H_2(g)    \Delta H_2=-(-136.3kJ)=136.3kJ

(3) H_2O(l)\rightarrow H_2(g)+\frac{1}{2}O_2(g)    \Delta H_3=-\frac{1}{2}\times (-571.6kJ)=285.8kJ

(4) 2CO_2(g)+3H_2O(l)\rightarrow C_2H_6(g)+\frac{7}{2}O_2(g)     \Delta H_4=-\frac{1}{2}\times (-3120.8kJ)=1560.4kJ

The expression for enthalpy of the reaction will be,

\Delta H^o=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4

\Delta H=(-1780.6kJ)+(136.3kJ)+(285.8kJ)+(1560.4kJ)

\Delta H=201.9kJ

Therefore, the enthalpy change for the reaction is, 201.9 kJ

5 0
1 year ago
Round off each of the following numbers to two significant figures:
Kay [80]
A) 5.2 x 10^2
B) 86.
C) 6.4 x 10^3
D) 5.0
E) 22.
F) 0.89
7 0
2 years ago
Read 2 more answers
The reaction 2NO + O2 → 2NO2 is third order. Assuming that a small amount of NO3 exists in rapid reversible equilibrium with NO
Rina8888 [55]

Answer:

The equation for the rate of this reaction is R = [NO] + {O2}

Explanation:

The rate-determining step of a reaction is the slowest step of a chemical reaction which determines the rate (speed) at which the overall reaction would take place.

Reaction mechanism:

The slow and fast reactions both have NO3 which is cancelled out on both sides, in order to get the overall reaction.

The rate law for this reaction would be that for the rate determining step:

R = [NO] + {O2}

5 0
2 years ago
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