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serious [3.7K]
2 years ago
10

Calculate the amount of heat released to convert 150.0 g of to water to ice at 0ºC.

Chemistry
2 answers:
gladu [14]2 years ago
8 0

Answer:

There correct answer is option 1 (-50100 J)

Explanation:

Step 1: Data given

Mass of water = 150.0 grams

ΔHfus = 334 J/g

Temperature = 0°C

ΔHfus = the amount of energy needed to change phase of 1 mol water to ice

Step 2: Calculate the amount of heat required

Q = m*ΔHfus

⇒Q = the amount of heat reuired = TO BE DETERMINED

⇒m =the mass of water = 150.0 grams

⇒ΔHfus = 334 J/g

Q = 150.0 grams * 334 J/g

Q = 50100 J  of heat required

Step 3: Calculate heat released

Qrequired = -Q released

Qreleased = -50100 J

There correct answer is option 1 (-50100 J)

Svetlanka [38]2 years ago
7 0

Answer:

The answer is -50100 J

Explanation:

I just took the test as I'm in GCA as well (11th grade). My teacher walked us through each formula and gave us multiple practice questions in Jigsaw.

Honestly, all you need to be aware of is the fusion formula which is:

q = m*Hfusion

q = amount of energy

m = mass in grams

Hfusion = 334 J/g (it will not change)

Write down what we're given and what we're looking for:

q = ?

m = 150

Hfusion = 334 J/g

Set up the equation:

q = 150 * 334

Multiply 150 by 334 to get 50100.

You must keep in mind that we're finding how much heat is released which means the energy will be negative.

Add the negative sign to the number to get -50100 Joules

I don't know why that chart is there, it doesn't do anything for this equation. Disregard it for this problem.

Hope I helped! :D

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A substance has a density of 4.5gmL. What is this in kgL? Report your answer with two significant figures.
Ipatiy [6.2K]

Answer:

4.5 kg/L

Explanation:

Density is 4.5g/mL and it means that in 1 mL of volume, the mass contained is 4.5 g.

Let's make a rule of three

1L = 1000 mL

1 mL has a mass of 4.5 g

1000 mL would have 4500 g

Our new density would be 4500 g/L, but we may convert the g to kg

1 kg / 1000 g . 4500 g = 4.5 kg

In conclusion 4.5 g/mL = 4.5 kg/L

7 0
2 years ago
A 0.3870-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.7191Â g of co
olchik [2.2K]
The chemical formula for the compound can be written as,

    CxHyOz 

where x is the number of C atoms, y is the number of H atoms, and z is the number of O atoms. The combustion reaction for this compound is,
   
    CxHyOz + O2 --> CO2 + H2O 

number of moles of C:
     (0.7191 g)(1 mol CO2/44 g of CO2) = 0.0163 mol CO2
 This signifies that 0.0163 mole of C and the mass of carbon in the compound,
        (0.0163 mols C)(12 g C/ 1 mol C) = 0.196 g C

number of moles H:
      (0.1472 g H2O)(1 mol H2O/18 g H2O) = 0.00818 mol H2O

This signifies that there are 0.01635 atoms of H in the compound.
      mass of H in the compound = (0.01635 mols H)(1 g of H) = 0.01635 g H

Mass of oxygen in the compound,
   0.3870 - (0.196 g C + 0.01635 g H) = 0.1746 g

Moles O in the compound = (0.1746 g O)(1 mol O/16 g O) = 0.0109 mols O

The formula of the compound is,
      C0.0163H0.01635O0.0109

Dividing the numbers by the least number,
    C3/2H3/2O

The empirical formula of the compound is therefore,
    <em>  C₃H₃O₂</em>
5 0
2 years ago
For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = -20.5 kJ/mol?
harina [27]

Answer:

Q= 245 =2.5 * 10^2

Explanation:

ΔG = ΔGº + RTLnQ, so also ΔGº= - RTLnK

R= 8,314 J/molK, T=298K

ΔGº= - RTLnK = - 6659.3 J/mol = - 6.7 KJ/mol

ΔG = ΔGº + RTLnQ → -20.5KJ/mol = - 6.7 KJ/mol + 2.5KJ/mol* LnQ

→ 5.5 = LnQ → Q= 245 =2.5 * 10^2

6 0
2 years ago
An ice cube measuring 5.80 cm by 5.80 cm by 5.80 cm has a density of 0.917 g/mL What is the mass?
OLga [1]

Answer: 178.9 g

Explanation:

Density = \frac{mass}{volume in mL}

find volume of the cube: (5.80 cm) (5.80 cm) (5.80cm) = 195.112 cm³

1.0 cm³ = 1.0 mL

so 195.112 cm³ = 195.112 mL

plug value into density equation:

0.917 g/mL = (mass) / (195.112 mL)

and solve for mass!

3 0
1 year ago
What is the mass of 0.75 moles of (NH4)3PO4?
Tomtit [17]

Answer:

well it turns into N3H12PO4

Explanation:

8 0
2 years ago
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