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ivolga24 [154]
2 years ago
7

The number of organisms that the environment in an ecosystem can handle is called its _____.

Chemistry
2 answers:
Basile [38]2 years ago
5 0
The answer to this question is "carrying capacity." The term "growth rate," refers to how fast a population grows, and the term "population density," refers to the number of organisms located within a specific area. Carrying capacity is correct because is directly addresses the maximum number of organisms that an ecosystem can handle, as opposed to how fast they are growing or how many there currently are.
Anon25 [30]2 years ago
4 0

Carrying Capacity  Is The Answer

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If you find that the hydrogen alpha line in a star’s spectrum occurs at a wavelength of 656.45 nm, what is the star’s approximat
Paladinen [302]

Answer:

The answer to the question is

The star’s approximate radial velocity is 68.52 km/s

Explanation:

To solve the

The formula is

\frac{\lambda-\lambda_{rw}}{\lambda_{rw}} = \frac{v_r}{c} where

v_r = velocity of the star

λ = Star's spectrum wavelength = 656.45 nm

\lambda_{rw} = Rest wavelength = 656.30 nm

c = Speed of light = 299 792 458 m / s

Therefore we have

\frac{656.45-656.30}{656.30} =\frac{v_r}{299 792 458} or v_r = 68518.7699 m/s or 68.52 km/s

8 0
2 years ago
How quickly must non-frozen ready-to-eat foods be consumed?
Alexxandr [17]

Answer:

i believe 24 hours

Explanation:

3 0
2 years ago
Read 2 more answers
What is the pH of a 0.28 M solution of ascorbic acid (Vitamin C)? (The values for Ka1 and Ka2 for ascorbic acid are 8.0×10−5 and
Tomtit [17]

Answer:

pH = 2.32

Explanation:

H2A + H2O -------> H3O+ + HA-    

Ka2 is very less so i am not considering that dissociation.

now Ka = 8.0×10−5

            = [H3O+] [HA-] / [H2A]

lets concentration of H3O+ = X then above equation will be

8.0×10−5 = [X] [X] / [0.28 -X]

8.0×10−5 = X2 /  [0.28 -X]

X2 + 8.0×10−5 X - 2.24 x 10−5

solve the quardratic equation

X =0.004693 M

pH = -log[H+}

    = -log [0.004693]

    = 2.3285

    ≅2.32

pH = 2.32

5 0
2 years ago
If fluorine 20 undergoes beta decay , what will it become ?
e-lub [12.9K]
Fluorine 20 (F - Atomic number 9 and atomic mass 20). Firstly we need to know what is beta decay. Beta decay occurs when one neutron changes into a proton and an electron therefore the atomic mass will remain the same as even though we loose a neutron it is replaced by a proton, the atomic number is always raised by 1 when one beta decay occurs. The produced electron is shot out of the nucleus at an incredible speed. This speedy electron we call a beta particle.

Ok now the reaction.

 20       20        0
F  -> Ne    +     e
 9         10       -1

Remember the atomic number determines the nature of the element ( i.e what elemnt it is).
Hope this helps :).
7 0
2 years ago
How many inner, outer, and valence electrons are present in an atom of each of the following elements?
Aneli [31]

<u>Answer:</u>

<u>For a:</u> The number of inner electrons, outer electrons and valence electrons are 28, 7 and 7 respectively.

<u>For b:</u> The number of inner electrons, outer electrons and valence electrons are 54, 1 and 1 respectively.

<u>For c:</u> The number of inner electrons, outer electrons and valence electrons are 23, 1 and 1 respectively.

<u>For d:</u> The number of inner electrons, outer electrons and valence electrons are 36, 2 and 2 respectively.

<u>For e:</u> The number of inner electrons, outer electrons and valence electrons are 2, 7 and 7 respectively.

<u>Explanation:</u>

Outer shell electrons are the electrons which are not tightly held by the electrons. They are called as valence electrons. The electrons present in the highest principle quantum number are known as valence electrons.

Inner shell electrons are the electrons which are tightly held by the electrons. They are called as core electrons.

Inner electrons = Total number of electrons - Valence electrons

Total number of electrons in an atom is equal to the atomic number of the element.

For the given options:

  • <u>Option a:</u>  Bromine (Br)

Bromine is the 35th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^5

Highest principle quantum number is 4

Number of valence electrons = 7

Number of outer electrons = 7

Number of inner electrons = 35 - 7 = 28

  • <u>Option b:</u>  Cesium (Cs)

Cesium is the 55th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^1

Highest principle quantum number is 6

Number of valence electrons = 1

Number of outer electrons = 1

Number of inner electrons = 55 - 1 = 54

  • <u>Option c:</u>  Chromium (Cr)

Chromium is the 24th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^13d^{5}

Highest principle quantum number is 4

Number of valence electrons = 1

Number of outer electrons = 1

Number of inner electrons = 24 - 1 = 23

  • <u>Option d:</u>  Strontium (Sr)

Strontium is the 38th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^2

Highest principle quantum number is 5

Number of valence electrons = 2

Number of outer electrons = 2

Number of inner electrons = 38 - 2 = 36

  • <u>Option e:</u>  Fluorine (F)

Fluorine is the 9th element of the periodic table having electronic configuration of 1s^22s^22p^5

Highest principle quantum number is 2

Number of valence electrons = 7

Number of outer electrons = 7

Number of inner electrons = 9 - 7 = 2

4 0
2 years ago
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