What is the pH of a 0.28 M solution of ascorbic acid (Vitamin C)? (The values for Ka1 and Ka2 for ascorbic acid are 8.0×10−5 and
1 answer:
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Answer: $1338.16
Explanation: Total cost of stock= $2568
Total cost of stock including the brokerage $
Selling price of stock = $3928
Selling price of stock including trading fee=($3928-$7)=$3919
Net Proceeds = Net selling price of stock - Cost Price of stock
Net Proceeds = ($3919 - $2580.84) = $1338.16
Answer:
129,600kg/day
Explanation:
The river is flowing at 30.0
1 = 1000L
Multiply by 1000 to convert to L/s
flowrate of river = 30*1000 =30,000L/s
Convert L/s to litre per day by multiplying by 24*60*60
flowrate of river = 30,000 * 24*60*60 L/day
= 2,592,000,000L/day
if the river contains 50mg of salt in 1L of solution
lets find how many mg of salt (X) is contained in 2,592,000,000L/day
X=
X= 129,600,000,000 mg/day
convert this value to kg/day by multiply by
X= 129,600kg/day
Answer : The volume of solution will be 2.96 liters.
Explanation :
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
In this question, the solute is NaF.
Now put all the given values in this formula, we get:
Therefore, the volume of solution will be 2.96 liters.
Answer:
Explanation:
Hello,
At first, it turns out convenient to compute the total moles of sodium that will be dissolved into the solution by considering the added amounts of sodium bromide and sodium sulfate:
Once we've got the moles we compute the final volume via:
Thus, the molarity of the sodium atoms turn out into:
Now, we perform the same procedure but now for the bromide ions:
Finally, its molarity results:
Best regards.